similar to: help with bwplot

Hello to the R world... I have some problems regarding a GLM - repeated measures analysis. I want to test overall differences between AgeClass and Treatment (between subject) with OpenR1+OpenR2+OpenR3 (repeated measures, within subject). The table looks kind like this: AgeClass Treatment OpenR1 OpenR2 OpenR3 1 1 0 0 12.63 1 1 12.67 3.83 45.67 1 1 38.46 65.38 75.21 1 1 14.46 0 17.96 1 2 27.83

Leonardo-- R-help can be a very useful resource. Some suggestions to use it well: 1. use an informative subject line, not "help" 2. include a "minimal working example:" a *little* data, the code that, with those data, reproduces your problem, and the error message that resulted. As to your particular question, at this point I can only guess, but for starters it would

Dear expert friends, I'm pretty young of this world and my question at your eyes can be petty easy. I'll need to change the name of the levels inside a column of my data-frame levels(ind.davis$Ageclass) <- c("adult", "Juvanile", "sub-adult") names(ind.davis$Ageclass) <- c("Adult", "Juvenile", "Sub-adult") that is what I

Hi, is there a way I can calculate a summary statistics for a columns matrix let say we have this matrix x <- matrix(sample(1:8000),nrow=100) colnames(x)<- paste("Col",1:ncol(x),sep="") if I used summary summary(x) i get the output for each column but I need the output to be in matrix with rownames and all the columns beside it this how I want it

Hi R-users: [R 2.2 on OSX 10.4.3] I have a (sparse) vegetation data frame with 500 rows (sampling units) and 177 columns (plant species) where the data represent % cover. I need to summarize the cover data by returning the names of the most dominant and the second most dominant species per plot. I reduced the data frame to omit cover below 5%; this is what it looks like stacked. I have

Hi, How to order the levels os factor not by alphabetic order but by mean of Y. Somethink like this: I have this alphabetic order: > levels(pH) [1] "alto" "baixo" "medio" the order by mean os yvar is: > sort(tapply(Riqueza,pH,mean)) baixo medio alto 11.56667 20.00000 26.80000 How to make the levels of pH ordered by this mean to the result to

Dear all, Sorry for bringing up an old issue: >pexp(50, 0.5) [1] 1 In some cases, pexp() gives CDF=1. I read some discussion in 2002 saying it has been patched. However it's not working in "R2.4.1Patched". Could anyone help me out? Thanks a lot, Jeann _________________________________________________________________ Fine Dining & Fancy Food. Check Out This

Hello, I have an r function that creates the following dataframe tresults2. Notice that column 1 does not have a column heading. Tresults2: [,1] estparam 18.00000 nullval 20.00000 . . . ciWidth 2.04622 HalfInterval 1.02311 pertinent code: results<-cbind( estparam, nullval, t, pv_left, pv_right, pv_two_t, estse, df, cc, tbox, llim, ulim, ciWidth,

Hello R-help. I am trying to make a stacked barplot where the color of the sections of each bar depend on another variable. > myData[1:11,] score percent marker cellType Malignant 1 0 100.00000 ESR1 (ER) Bladder.M(5) TRUE 2 0 80.00000 PAX8 Bladder.M(5) TRUE 3 1 20.00000 PAX8 Bladder.M(5) TRUE 4 0 100.00000 ESR1 (ER) Brain.N(3) FALSE 5 0

Dear All, I created a script to calculate averages - two groups: "parcel" and "date" - and, based on these averages, make a graph. The problem is that 'R' does not recognize the first column even if I try to insert one. A brief example Raw data: Data <- sample(1:100, 30, replace = FALSE, prob = NULL) Date <-

Hi, I'm pretty new to R and have run into a task which although I'm certain is within R's capabilities, falls outside of mine. :-) Consider the following data set: 2012-07-22 12:12:00, 21 2012-07-22 12:15:00, 22 2012-07-22 12:18:00, 24 2012-07-22 12:39:00, 21 2012-07-22 12:45:00, 25 2012-07-22 12:49:00, 26 2012-07-22 12:53:00, 20 2012-07-22 13:00:00, 18 2012-07-22 13:06:00, 22 My

Hey All, I have a large dataset and I want to calculate the average of each column then return a new dataset. Here is my question: I dont know if there is a function that can allow me to calculate the average every 60 records of data in the whole dataset, and return a new data frame. Not sure if I have to divide the dataset first for every 60, then do the mean or can i directly do that. thanks

I'll try to be more clear, but will have to give much more info. Here we go.... As part of my Masters in Public Health I writing a dissertation reviewing the mortality trend of internally displaced persons in camp settings in Sub Saharan Africa. I have 50 surveys with - crude mortality rate (cmr), CMR lower confidence interval(cmrlci), CMR upper confidence interval(cmruci), - recall period

Hi There, Using t.test to test hypothesis about which one is greater, A or B? where A={10,20,30},B={25,30,15}. My question is which of the following conclusions is right? #################hypothesis testing 1 h0: A greater than or equal to B h1: A less than B below is splus code A=c(10,20,30) B=c(25,30,15) t.test(c(10,20,30),c(25,30,15),alternative="less") output: p-value=0.3359

Hi, I am new in R and I have problem with reading this data file 0 TITLE Title 0 XLEGEND Legend -1 LABEL x 1 1 12 1 2 30 1 3 34 I want to read only lines starting with 1 (it indicates 1st plotting line) and create data set from second and third value on this row. Thank for advice Jakub Zlamal -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list