similar to: Newbie on plotting

I have a table statement that returns the following: [10.839,10.841] (10.841,10.843] (10.843,10.846] (10.846,10.848] (10.848,10.85] 0 0 0 0 1 (10.85,10.852] (10.852,10.854] (10.854,10.857] (10.857,10.859] (10.859,10.861] 0 0 0 0 0 What I want to do is get the upper bound

I have a list of entrants (1-14 in this example) in a competitive event and corresponding win probabilities for each entrant. [(1, 0.049), (2, 0.129), (3, 0.043), (4, 0.013), (5, 0.015), (6, 0.040), (7, 0.066), (8, 0.038), (9, 0.204), (10, 0.022), (11, 0.234), (12, 0.044), (13, 0.068), (14, 0.035)] So, of course Sum(ps) = 1. In order to make some subsequent computations more

If I run the following example from: http://www.stat.auckland.ac.nz/~paul/grid/doc/grobs.pdf > grid.newpage() > pushViewport(viewport(w = 0.5, h = 0.5)) > myplot <- gTree(name = "myplot", children = gList(rectGrob(name = "box", + gp = gpar(col = "grey")), xaxisGrob(name = "xaxis"))) > grid.draw(myplot) >

Dear all, I have a large vector (lets call it myVector) and I want to plot its value with the logic below yaxis<-myVector[1] yaxis<-c(xaxis,mean(myvector[2:3]) yaxis<-c(xaxis,mean(myvector[4:8]) yaxis<c(xaxis,mean(myvector[9:16]) yaxis<c(xaxis,mean(myvector[17:32]) this has to stop when the new ..... yaxis<c(xaxis,mean(myvector[1024:2048]) will not find the correspondent number

Hi R list, I like the default ticks that are set up using grid.xaxis() or grid.yaxis() with no arguments. Finding good values for the 'at' argument is usually not a trivial task; the default behavior of these functions seems to work well. The problem with this strategy is that I cannot figure out how to "recover" the positions of these ticks when you do NOT specify the

Dear list, Can someone explain why the childNames below gives character(0) instead of the (canonical) names of the children grobs of the xaxis gTree ? [1] "major" "ticks" "labels" Many thanks in advance, Tobias ### minimal example code ### library(grid) pushViewport(plotViewport(c(5,4,4,2))) pushViewport(dataViewport(1:5, 1:5)) grid.points(1:5, 1:5)

I have some code as shown below. Basically, I would like three boxplots to be set next to each other with no ylabels on the two "inner" plots, and I want the same x axis range on all three. However, it seems like boxplot does not respect the xlim setting. I've tried the various ways I thought would work (par, boxplot(...xlim=)) but none of them seem to work. I then tried plot.window,

Hello, I am trying to create a graphic to help me visualise data. A (very simplified) sample of the data is http://n4.nabble.com/file/n1839676/circle_data.txt circle_data.txt : Aug-07 Nov-07 Feb-08 data1 1 1.5 -1 data2 1 1.2 1.6 data3 1.3 1.4 1.8 data4 1.3

Hi, I try to create a vertical line in my plot, which has a xaxis comprising time formated data. This is what I tried: ---------------- y<-152833 x<-strptime(y, format="%H%M%S") abline(v=x, col="red") ---------------- for some reason, it doesn't work and no error msg is displayed... I hope someone can tell me what I do wrong, or maybe an alternative. Thanks

Have an app using older version of Rails (2.3.2) that I need some routing assistance with if anyone has a minute. The app was originally designed to be purely html view, and an xml and json api was hacked on. To keep it clean, we are now moving the first version of the api (v1) under its own directory (v1) under app/ controllers but still responding to the old paths. One of the parts of the new

Hi, I'm trying to modify this function.I want to remove the existing xaxis(the tick marks and the values below each tick) and make it dynamic so that i can choose whether i want the xaxis at the top or bottom but i cant seem to change that.can somebody help me? plot.Sample <- function(x,xlab=NULL,ylab=NULL,...){ sampletest <- is.Sample(x,argname="'x' ") if

Hello (this might be a very simple question) My data is as follows (table name is student) Year StudentsPassed 1 2000 300 2 2001 360 3 2002 450 4 2003 450 5 2004 270 6 2005 280 7 2006 400 8 2007 270 I want to plot a barplot so for this If I use barplot(students) it says "Error in barplot.default(students) : 'height' must be a vector or a

Hello, I'm plotting an xyplot where a continuous var recorded every min is plotted on y, and time expressed as HH:MM:SS on x, as follows : xaxis=list(tick.number=12,rot=90) lst=list(x=xaxis) xyplot(upt$LOAD_1 ~ upt$TIME, data=upt, type=c('g','p', 'r'), scales=lst) On the x-axis, every time label is drawn and the label quickly become unreadable as they overlap on each

I need to make a fairly complex animated graphic and decided to use grid for it. A very simple example of what I need: ##============================================================================== library(grid) grid.newpage() pushViewport(plotViewport()) pushViewport(viewport(xscale = extendrange(c(0, 100)), yscale = extendrange(c(0, 100)))) grid.xaxis() grid.yaxis()

> Hi All R guru's, > > A couple of simple questions which I cannot find answers to in "an > introduction to R" or in the reference manuals. > > I am running R on Win95, and have plotted up quite a nice box and whisker > plot: > > char<-read.table("n:/reddinm/grifpr~1/survey/char.txt") > attach(char) > boxplot(Al,Fe,OC,pH,

Hi, Am sure this is a trivial question but for some reason, haven't been able to figure it out. I want to bucket data in a vector, and then iterate over the buckets. Say the data set is: > cleandata[,4] [1] 26 26 26 26 26 26 26 26 26 26 26 26 61 61 61 61 61 61 61 61 61 61 61 89 89 89 89 89 89 89 180 180 180 180 362 544 544 544 [39] 544 544 544 544 544 544

Hello, Sorry if this is a repeat, having trouble finding what I need on archive and am a novice with graphics in R! I have plotted the results of a logit regression by factor, where "city" is the factor set name. The problem is city names are too long and I need to rotate them 90 degrees along the xaxis. This is what I've tried... plot(city, predicted.probability, xlab =

Hi all, I''m having a stupid moment getting a remote file bucket working. My client only file buckets locally, not remotely. I have this site.pp: ********* filebucket { "main": server => "puppet" } File { backup => "main" } node ''default'' { include test } ********* and this test module: ********* class test { file {

Hi all, how do I change the magnification of xaxis annotation? I need a smaller axis text size in some of my plots. I tried cex.axix=0.5 in plot(), but this doesn't work. Thanks, Sven -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or

Hi, To set a simple an clear picture of what I'd like to do, here is an example. I would like to calculate mean of column A and B bucketed by factor in column X in a data.frame. lapply or aggregate operates on a single column. I found dapply function in some package which doesn't seem to exist any more. Is there anyway that I can accomplish something like this? Thank you so much in