similar to: time series plot

I have a list of data.frames, and i want to iterate over this list and generate graphs with the same title of the data.frame. I did the graphs with: lapply(anual, function(x) plot(x[,'chuva'], type='l', xlab= 'anos', ylab = 'Precicipatação(mm)', col='red')) where anual is list of data.frames. I am plotting just the column "chuva" at each

Existe algún paquete en donde puedo modelizar específicamente series diarias univariadas siguiendo la metodología de Box-Jenkins? Cómo modelizar mas de una estacionalidad en dichas series por ejemplo una estacionalidad semanal y anual? GRacias Santiago Cilintano [[alternative HTML version deleted]]

Hi, I'm having this Sendmail configuration problem and stuck. I've been doing googling/reading posts and none of the solutions matched my problem. I'm doing some testing, and have been getting this 550 5.1.1 ....User unknown error when I send the email to my company's email address. When I send it to an external email address, such as yahoo, the message delivered successfully.

In this real example (below), all four of the replicates in one treatment combination had zero failures, and this produced a very high standard error in the summary.lm. =20 Just adding one failure to one of the replicates produced a well-behaved standard error. =20 I don't know if this is a bug, but it is certainly hard for users to understand. =20 I would value your comments=20 =20 Thanks =20

Hi folks, Moving the discussion to llvm.dev. None of the changes we talked earlier help. Find attached the C source code that you can use to reproduce the issue. clang --target=aarch64-linux-gnu -c -mcpu=cortex-a57 -Ofast -fno-math-errno test.c -S -o test.s -mllvm -debug-only=licm LICM hoisting to while.body.lr.ph: %21 = load double** %arrayidx8, align 8, !tbaa !5 LICM hoisting to

Can you send me actual LLVM IR or a preprocessed source from using -E? I don't have a machine handy that has headers that target that arch. On Tue Jan 13 2015 at 4:33:29 PM Daniel Berlin <dberlin at dberlin.org> wrote: > Anything other than noalias or mustalias should be getting passed down the > stack, so either that is not happening or CFL aa is giving better answers > and

Yes. I've attached an updated patch that does the following: 1. Fixes the partialalias of globals/arguments 2. Enables partialalias for cases where nothing has been unified to a global/argument 3. Fixes that select was unifying the condition to the other pieces (the condition does not need to be processed :P). This was causing unnecessary aliasing. 4. Adds a regression test to

Hi to all, I initiate in R - Linux and I've some problems to find an editor with R interface as like RWinEdt for WinEdt. Anyone know one? Thanks in advance for your kind cooperation. Best regards Atenciosamente Ana Patricia Martins ------------------------------------------- Serviço Métodos Estatísticos Departamento de Metodologia Estatística Telef: 218 426 100 - Ext: 3210

On 13 January 2015 at 22:11, Daniel Berlin <dberlin at dberlin.org> wrote: > This is caused by CFLAA returning PartialAlias for a query that BasicAA > can prove is NoAlias. > One of them is wrong. Which one? I'm not sure from your description that this is a chaining issue. PartialAlias doesn't chain and isn't supposed to, it's a final answer just like NoAlias and

Oh, sorry, i didn't rebase it when i changed the fix, you would have had to apply the first on top of the second. Here is one against HEAD On Wed, Jan 14, 2015 at 12:32 PM, Ana Pazos <apazos at codeaurora.org> wrote: > Daniel, your patch does not apply cleanly. Are you on the tip? > > The code I see there is no line if (QueryResult == MayAlias|| QueryResult == PartialAlias)

Algo asi? l <- list()l$nombre <- "Ana"l$apellido <- "Pérez"parametro <- "nombre"paste(l[ parametro][[1]], 'OnValidate', sep='')[1] "AnaOnValidate"l[ parametro][[1]][1] "Ana"x <- 1:5AnaOnValidate <- function(x) print(x)if (exists(paste(l[ parametro][[1]], 'OnValidate', sep=''))) do.call(paste(l[

Buen día estimados, Tengo el siguiente código: df_1 <- data.frame(ana = c(15, 20, 30), maria = c(15,20,30), jose = c(15, 20, 30)) df_2 <- data.frame(nombre = c("jose", "ana", "maria"), valor = c(1,2,3)) # Find the corresponding columns in df_1 based on the values in df_2$nombre cols <- match(df_2$nombre, names(df_1)) # Subtract the values of df_2$valor

Eva, ¿Algo asi o te entiendo mal? l <- list()l$nombre <- "Ana"l$apellido <- "Pérez"parametro <- "nombre"if (exists(paste('nombre', 'OnValidate', sep=''))) nombreOnValidate(1:5) # cuidado con el enviroment nombreOnValidateif (exists(paste('s', 'um', sep=''))) sum(1:5) # esto lo agrego como ejemplo[1] 15l[

Hi, if i just want a vector filled with names which has length(index) > 0. For example if nombreC <- c("Juan", "Carlos", "Ana", "Mar?a") nombreL <- c("Juan Campo", "Carlos Gallardo", "Ana Iglesias", "Mar?a Bacaldi", "Juan Grondona", "Dario Grandineti", "Jaime Acosta",

Inline - George > On Jan 14, 2015, at 10:49 AM, Daniel Berlin <dberlin at dberlin.org> wrote: > > > >> On Tue, Jan 13, 2015 at 11:26 PM, Nick Lewycky <nlewycky at google.com> wrote: >>> On 13 January 2015 at 22:11, Daniel Berlin <dberlin at dberlin.org> wrote: >>> This is caused by CFLAA returning PartialAlias for a query that BasicAA can

Hello R-users and developers, Once again, I'm asking for your help. I can identify outliers in boxplot with this instruction result <- boxplot( Income ~ Sex, col = "lightgray", data=dados) if (length(result$out)) text(result$group, result$out, result$out, pos = 4, col = "red") But I can not identify the outlier's id (variable names) in the boxplot.

Hello R-users and developers, Once again, I'm asking for your help. There is other way to do the same more easily for applied simultaneous grep??? c<-subset(c,!rownames(c) %in% grep(".1",rownames(c),value=T)) c<-subset(c,!rownames(c) %in% grep(".5",rownames(c),value=T)) c<-subset(c,!rownames(c) %in% grep(".6",rownames(c),value=T))

Dear helpers, I need help to create a PDF file like the example ----------------------------------- | Title | ----------------------------------- | | | Text (print a list) | | | ----------------------------------- | | | | | | | image | image | | | | | | | -----------------------------------

Hello, I think this is Sill question but it's happens...... am$e_isell <- factor( with( am, ifelse( e_iacc == 1 & C5 == 1, 1, 0))) summary (am$e_isell) 0 1 3966 296 (Ok) am$e_isell [4256] [1] 1 Levels: 0 1 (OK) cbind( am$e_isell[4256], am$C6[4256]) [,1] [,2] [1,] "2" "1" (??) cbind( am$e_isell[4256]) [,1]

hello to all, I advice you to not use CDRtool from ag-projects : Fisrt ag-projects talk about is product like a gpl software however they don't provide at least some documentation for non commercial users . try to call them !! i'll offer you some money . You can not Call them for some advices ... It's really a bad product don't waste your time to setup it. this enterprise must