similar to: Regexpr. analyzer

Hi,David Can you give me an example of how to add analyzer to ferret to Asian languages? My web application will have to support multi language search,which means,for example,both Chinese and English will be searched through the form. Currently,I have decided to use the simple token principles,which means that every Chinese character will be a token,although this is not so well in some

Hi all, I want to use ferrent in my website but when i input chinese words, i have the same symptom like Chengcai. In order to fix it, i have reviewed all the topics about chinese support in our forum and tried all the way your guys suggested but still made any progress. i downloaded the latest version of ferret from svn. Thanks and regards. captain Chengcai He wrote: > Hello everyone!

How to add Chinese language full text searching function by using acts_as_ferret? RegExpAnalyzer.new(/./,false) this analyzer, i don''t know how to use it! does it works like this: user searching---->acts_as_ferret---->ferret ???? -- Posted via http://www.ruby-forum.com/.

I just started using Ferret and I successfully indexed some documents. I can search this index using the following code: index = Index::Index.new(:path => path) index.search_each("something") do |doc, score| print "##{doc} #{index[doc][''url'']} - #{score}" print "\n" end However, when I try to use Search::Searcher and QueryParser

Lucene''s standard analyzer splits words separater with underscores. Ferret doesn''t do this. For example, if I create an index with only document ''test_case'' and search for ''case'' it doesn''t find anything. Lucene on the other hand finds it. The same story goes for words separated by colons. Which analyzer should I use to emulate

Hi, I''ve discovered ferret and aaf this evening, I''ve just done some tests and it seems perfect for my needs. I''m indexing text data (title, description, etc) and also ethernet hardware addresses (MAC). Sorry if that sounds trivial but I can''t find the way to correctly index and achieve correct searches on MAC addresses. If I do something like this: index =

Hi! I''m trying to install ferret on windows, so I chose ferret-0.10.9-mswin32.gem from the download page, as it includes a already pre-compiled ferret_ext.so (is that correct?) and I don''t have any C compiler here. The gem installed it correctly, but the test didn''t work. So I called these commands: rake ext ruby setup.rb config ruby setup.rb setup ruby setup.rb

In my model Topic: acts_as_ferret({ :fields => {:username => {:store => :yes, :boost => 30}, :subject => {:store => :yes, :boost => 20}, :body => {:store => :yes, :boost => 10}}, :remote => true }, { :analyzer => Ferret::Analysis::RegExpAnalyzer.new(/./, false) }) def self.full_text_search(q, options = {}, find_options = {}) return nil if q.nil? or

I''ve successfully installed ferret and acts_as_ferret and have no problem with utf-8 for accented characters. It returns correct results fot e.g. fran?ais. My problem is with non latin characters (Persian indeed). I have tested different locales with no success both on Debian and Mac. Any idea? (ferret 0.11.4, acts_as_ferret 0.4.0, rails 1.1.6) -- Posted via http://www.ruby-forum.com/.

Dear R Helpers, I am running R 2.6.2 on a Windows XP machine. I am trying to use regexpr to locate full stops in strings, but, without success. Here an example:- f="a,b.c at d:" #define an arbitrary test string regexpr(',',f) #find the occurrences of ',' in f - should be one at location 2 # and this is what regexpr finds #[1] 2

R-help, Sorry if this is more of a regex question than an R question. However, help would be appreciated on my use of the regexpr function. In the first example below, I ask for all characters (a-z) in 'abc123'; regexpr returns a 3-character match beginning at the first character. > regexpr("[[:alpha:]]*", "abc123") [1] 1 attr(,"match.length") [1] 3

Given a text like I want to be able to extract a matched regular expression from a piece of text. this apparently works, but is pretty ugly # some html test<-"</tr><tr><th>88958</th><th>Abcdsef</th><th>67.8S</th><th>68.9\nW</th><th>26m</th>" # a pattern to extract 5 digits > pattern<-"[0-9]{5}" #

Hi, I 'd like to match each member of a list to a target string, e.g. ------------------------------ mylist=c("MN","NY","FL") g=regexpr(mylist[1], "Those from MN:") if (g>0) { "On list" } ------------------------------ My question is: How to add an end-of-string symbol '$' to the to-match string? so that 'M' won't

Hi, I'm trying to parse lines of the form: dan001.hin (0): fingerprint={256, 411, 426, 947, 973, 976} What I need is the sequence of number between {}. I'm using grep as match <- grep("{([0-9,\s]*)}",s,perl=T,value=T) where s is a character vector. But all I get is the whole string s. I tried using regexpr in an attempt to get just the sequence I wanted: match <-

Help-Rs,   I'm doing some string manipulation in a file where I converted a string date in mm/dd/yyyy format and returned the date yyyy.   I've used regexpr (hat tip to Gabor G for a very nice earlier post on this function) in steps (I've un-nested the code and provided it and an example of what I did below.  My question is: is there a more efficient way to do this.  Specifically is

Greetings R list, I am stuck on a simple syntax problem. I want to list all files in a directory, excluding files of a certain type. I have tried pattern matching as follows: a <- list.files(data, full.name = TRUE, pattern != ".xml") # exclude all .xml files The warning returns that my syntax is incorrect. I have read the regexpr help files and search old posts to no

Dear all-- I am still forging my first arms with R and I am fighting with regexpr() as well as portability between unix and windoz. I need to extract barcodes from filenames (which are located between a double and single underscore) as well as the directory where the filename is residing. Here is the solution I came to: aFileName <-

Dear all I encountered strange problem with regexpr replacement I made this character object str <- "02.06.10 12:40 " > str(str) chr "02.06.10 12:40 " I read in an object which seems to be quite similar > str(as.character(becva$V1)[1]) chr "02.06.10 12:40 " However I can not remove trailing spaces from it > sub(' +$',

Hello, I have build a syntax to find out if a given substring is included in a larger string that works like this: d1$V1[regexpr("some text = 9",d1$V2)>0] <- 9 and this works all right till "some text" contains standard ASCII set. However, it does not work when accents are included as the following: d1$V1[regexpr("some t?xt = 9",d1$V2)>0] <- 9 I have

I'm trying to use the regexpr function to locate the decimal in a character string. Regardless of the position of the decimal, the function returns 1. For example, > regexpr(".", "Female.Alabama") [1] 1 attr(,"match.length") [1] 1 In trying to figure out what was going on here, I tried the below command: > gsub(".", ",",