similar to: Bug with curve?

Displaying 20 results from an estimated 20000 matches similar to: "Bug with curve?"

2007 Feb 23
4
using "integrate" in a function definition
Dear list members, I'm quite new to R, and though I tried to find the answer to my probably very basic question through the available resources (website, mailing list archives, docs, google), I've not found it. If I try to use the "integrate" function from within my own functions, my functions seem to misbehave in some contexts. The following example is a bit silly, but
2007 Apr 18
5
Problem with ?curve
Dear all R gurus, I have following syntax: y = c(1:10) chippy <- function(x) { y[5] = x sin(cos(t(y)%*%y)*exp(-t(y)%*%y/2)) } curve(chippy, 1, 20, n=200) But I am getting error while executing : Error in xy.coords(x, y, xlabel, ylabel, log) : 'x' and 'y' lengths differ In addition: Warning message: number of items to
2012 Jun 04
1
Plotting with Rgraphviz
Hi All, After a lengthy battle just to get the package installed, I am not able to actually use Rgraphviz to generate any plots. I tried just using the sample code in the documentation (http://www2.warwick.ac.uk/fac/sci/moac/people/students/peter_cock/r/rgraphviz/) and I get the following: *> > library(Rgraphviz) > test.matrix<-matrix(rep(c(0,1,0,0), 9), ncol=6, nrow=6) >
2005 Oct 27
1
Puzzled over curve() syntax.
It's probably toadally elementary (and, like, duhhhhh) but I can't figure out why the following doesn't work: curve(function(x){qnorm(x,4,25)},from=0,to=1) I get the error: Error in xy.coords(x, y, xlabel, ylabel, log) : 'x' and 'y' lengths differ But if I do foo <- function(x){qnorm(x,4,25)} curve(foo,from=0,to=1) it goes like a train. Also
2006 Jan 21
1
Bug in xy.coords() or documentation error?
Hi, I noticed the following problem with xy.coords() in R 2.2.1-patched (version info at the foot of this email) and R 2.3.0 unstable (subversion no: r37123): > xy.coords(x = matrix(1:20, ncol = 2)) Error in xy.coords(x = matrix(1:20, ncol = 2)) : argument "y" is missing, with no default > xy.coords(x = matrix(1:20, ncol = 2), y = NULL) $x [1] 1 2 3 4 5 6 7 8 9
2011 Feb 21
2
(no subject)
What is plot.new? and how can i get it to work so i can load other data? > library(splancs) > area = 6*4 > lambda = 1.5 > N = rpois(1,lambda*area) > u = runif(N,-2,4) > v = runif(N,0,4) > plot(u,v,asp=1) > h = chull(u,v) > h = c(h,h[1]) > plot(u[h],v[h],"1",asp=1) Error in plot.xy(xy, type, ...) : invalid plot type '1' >
2001 May 04
1
scoping error in xy.coords (PR#932)
Hola! > rm(list=ls(all=TRUE)) > x <- 1:20 > y <- 1+x+rnorm(x) > xy.coords(y ~ x,NULL) ... expected output, correct, but when called from inside lowess: > lowess(y ~ x) Error in xy.coords(x, y) : x and y lengths differ > debug(xy.coords) > lowess(y ~ x) debugging in: xy.coords(x, y) ... long listing deleted if (is.language(x)) { if (inherits(x,
2004 Nov 23
2
Quadratic curve on a loop
Dear R community, once again I request your generous help on an R issue I cannot seem to figure out. I am trying to do some analysis for multiple sites, in my example I am using only two, but the same will done on many sites. It's just ONE line, so I hope somebody can give a me a hand by email. Look at the loop to make the plot x ~ y. If the curve function is removed from the loop
2010 May 18
2
automate curve drawing on nls() object
Hi, I would like to use the curve() function to draw the predicted curve from an nls() object. for example: dd<-read.table("dd.txt",sep='\t',header=T,row.names=1) obj<-nls(y~c+(d-c)/(1+(x/e)^b),data=dd,start=list(b=-1, c=0, d=100, e=150)) coef(obj) b c d e -1.1416422 0.6987028 102.8613176 135.9373131
2003 Apr 16
2
trying to plot function using curve
Dear People, I hope someone can help me with this. I have a function (density) which I am trying to plot using curve. I am calling mg.hist(3,2,1), and getting the following errors. Error in xy.coords(x, y, xlabel, ylabel, log) : x and y lengths differ In addition: There were 50 or more warnings (use warnings() to see the first 50) > warnings() 1: longer object length is not a multiple of
2005 Dec 31
1
xy.coords
In ?xy.coords it says: If 'y' is missing and 'x' is a formula: of the form 'yvar ~ xvar'. 'xvar' and 'yvar' are used as x and y variables. list: containing components 'x' and 'y', these are used to define plotting coordinates. time series: the x values are taken to be 'time(x)' and the y
2008 Oct 23
3
xy.coords in text
Hello, I want to add text annotation about correlation on "pairs" plots. I found that I could pass a function to the "panel" argument of pairs : panel.annot <- function(x, y, ...) { points(x, y, ...) c <- cor.test(x, y) legend("topleft", legend=substitute(rho == r, list(r=sprintf("%.2f", c$estimate))), bty="n") } And then :
2004 Jul 13
2
help with as.function
HI, sorry but i don't understand how to make a function with as.function() formula<-"2+3*x" formu<-as.symbol(formula) > formu 2+3*x formul<-as.function(alist(x=,formu)) curve(formul,1,5,col="blue") Error in xy.coords(x, y, xlabel, ylabel, log) : x and y lengths differ > typeof(formul) [1] "closure" and not plot the curve function, Why?
2006 Jun 04
4
xy.coords(MATRIX) bug in code or documentation (PR#8937)
Hi, people. xy.coords() does not behave like its documentation says, when given some matrices. ?xy.coords says: If 'y' is 'NULL' and 'x' is a [...] formula [...] list [...] time series [...] matrix with two columns [...] In any other case, the 'x' argument is coerced to a vector and returned as *y* component [...] Now, consider this short
2004 Nov 30
4
adding regression curve to xyplot
Dear R-listers, It seems that predict() behaves differently within panel.xyplot. Am I doing something stupid? Thanks, Carlisle First, without xyplot(): > lmtest <- lm(t~s,data=subset(P100,whichLon100==1 & whichLat100==1)) > lmtest Call: lm(formula = s ~ t, data = subset(P100, whichLon100 == 1 & whichLat100 == 1)) Coefficients: (Intercept) t 33.3307
2012 Apr 01
1
Error in xy.coords(x, NULL, log = log) : (list) object cannot be coerced to type 'double'
Hi there, When I run the code below I get the error Error in xy.coords(x, NULL, log = log) :(list) object cannot be coerced to type 'double' Any tips how I can resolve this? > > library("waveslim") > > vols=read.csv(file="C:/Users/ocuk/My Documents/Abs Vol.csv", header=TRUE, > sep=",") > x<-c(vols[,1]) > #x > #data(ibm) >
2011 May 24
1
histogram with density
Hello All,* *I want to draw a histogram with density curve. * *For that simply i created a data called*"x" *and i used the function called * hist(x, col = "blue", freq = FALSE),** *from this function i got a histogram*. *After that , i tried this function* ** lines(density(x), col = "red", lwd = 2 ) *but i could not get the density curve. So, Again i used
2006 May 15
1
adding line to spinogram
Dear all, I wonder what's special about spinograms {vcd} that prevents me from using it the way I do with other plots. I do: > spine(f.speaker.identity ~ x.log.lengthening, > data=ms,breaks=45,gp=gpar(fill=c("red","green")),xlab="length difference > (log ms)",ylab="speaker") > curve(0*x,add=T) Error in plot.xy(xy.coords(x, y), type =
2009 Jun 06
1
large numbers of observations using ME() of spdep
Dear All, We aim to remove the spatial structure of our data using Moran Eigen Vectors and spdep package . Our data has 3694 samples and 13 variables. The computer stop working after almost 4 days of processing (we found it emitting a sharp sound and with all colors on the screen. No wories, it was restared without problem!). And we are left with nothing: no result file was produced since the
2004 Nov 23
6
Weibull survival regression
Dear R users, Please can you help me with a relatively straightforward problem that I am struggling with? I am simply trying to plot a baseline survivor and hazard function for a simple data set of lung cancer survival where `futime' is follow up time in months and status is 1=dead and 0=alive. Using the survival package: lung.wbs <- survreg( Surv(futime, status)~ 1, data=lung,