similar to: Simple question about :list method in scaffolds

I created some scaffolding for an Address model and an Addresses controller. When running the functional tests for the addresses controller, I get this exception: "NameError: uninitialized constant Addres" The exception seems to start from this function: def list @address_pages, @addresses = paginate :address, :per_page => 10 end I''m guessing pluralization bug?

I have some code working that lists only items from a particular user. The code in my list action finds the user and then conditionally lists only his/her items: def list user = User.find(session[:user]) user_id = user.id @product_pages, @products = paginate :products, :per_page => 10, :conditions =>[''user_id = ?'', user.id]

How do I adapt this code to only list articles made by the user logged into the session? def list @article_pages, @article = paginate :articles, :per_page => 10 end -- Posted via http://www.ruby-forum.com/.

Hi, I am trying paginate (will_paginate) users posts. It is counting and showing the page links correctly, but still showing all the posts on one page. @entries = @user.entries.paginate :per_page => 5, :page => params[:page], :order => ''created_at DESC'' If I change it to @entries = Entry.paginate :per_page => 5 ........ It is fine, but I would like to show only

I am a Rails newbie and I am trying to build a test site in which users will have their own sets of data. I understand how to manipulate shared data very well. Most of the Rails examples out there seem to deal with such shared data. I am struggling with the "best practice" method for a user to work with their own data however (and not be able to view/edit other users''

Hello. I call a find_all_by_subject("action") which returns 2 videos and displays them properly. But when I add @video_pages, @videos = paginate :videos, :per_page => 10 so I can paginate the videos, it displays ALL the videos as if I selected list videos. Can someone please tell me what I am doing wrong? Thank you. selectaction.rhtml <table> <tr> <% x = 0 %>

I have a controller and list page for region object. My list page has a ''name'' text input that can be used to limit the list. It works except that the paginate gets the full set of regions unqualified by my search term. I believe this full list is contained in :regions symbol which I dont seem to be allowed to modify or replace (yes I am a ruby and rails newb). How can I

Hello, I have 2 tables table colors : +----------------------+ | id | user_id | name | +----------------------+ | 1 | 1 | test1 | | 2 | 2 | test2 | | 3 | 3 | test3 | +----------------------+ table users : +----------------------+ | id | enabled | name | +----------------------+ | 1 | 1 | bob | | 2 | 1

Hi Guys, I am trying to paginate the results from a search. When I use actual constants in the search conditions, it works fine: def query @k2_result_pages, @k2_results = paginate (:k2_results, :conditions => [''e_date >= ? AND e_date <= ?'', ''2006-07-12'', ''2006-08-12''],

Hi all, I''m creating admin module. in that module i need to get the list of users and also the projects created by the each user. No doubt i''m getting the list of users. but i''m not getting the list of projects done by each user.. This is my code:: <% for user in @users %> <%=link_to

> Unfortunately I still get the same error. Here is my code now (the > commented line works): > > def list > @upload_pages, @uploads = paginate(:uploads, :per_page => > 20, :order > => ''id'') > # @upload_pages, @uploads = paginate(:uploads, :per_page => 20) > end You may have an older version, try using the order_by clause

Hi, Why can''t I use a variable to specify the :per_page attribute when using the most basic form of pagination? (if I use a hardcode number, it runs) What did I do? Thx. My code: def list_orders page_size = 20 ... order_pages, @orders = paginate(:orders, :per_page => page_size) end My Errors: undefined method `>'' for false:FalseClass RAILS_ROOT:

I''m messing with the agiles store example. I added a field in my product table (user_id) that is also a foreign key relationship via fk_products_user In my scaffold I''d like to list the products as usual, but only those products from the logged in user. I assume that would be done in the controller.. How would I extend the basic controller: def list @product_pages,

I am trying to use pagination with the order option. I am following examples I''ve seen all over the web, but I am getting an error. My code seems simple: def list @upload_pages, @uploads = paginate :uploads, :per_page => 20, :order => ''id'' end Yet I keep getting this error: ___________________________________________

I am having this problem with pagination query in my controller class. I am using SQL server and following code to create pagination fails, complains about column name ''program_name'' (which is valid column/attribute of program) The error message is: DBI::DatabaseError: S0022 (207) [Microsoft][ODBC SQL Server Driver][SQL Server]Invalid column name

I''m using will_paginate in a Post class method; [code]def self.list(page) paginate :per_page => 10, :page => page, :include => :user end[/code] I can happily use the method on my posts controller index action; [code] class PostsController < ApplicationController def index @posts = Post.list(params[:page]) respond_to do |format|

I have the following: def index begin @restaurant_pages, @restaurants = paginate :restaurants, :order => (params[ :sort ] || "name"), :per_page => 2 @cuisines = Cuisine.find_all rescue redirect_to :action => :index end end # sort by cuisine def

There must be a better way to write this code: @project_pages, @projects= paginate :project, :per_page => 10, :conditions => ["account_id = ?", account] ?! If only I could pass the sub-collection account = ... @projects = account.project to paginate, instead of letting it extract it with a find :all + sql conditions Alain. -- Posted via

How come I allways immediately run into difficult stuff when I''m trying some new programming language? Am I blind for the simplicity of Ruby/Rail, which a see must be there? Anyway, don''t try and answer this rhetoric question. I have got another one for you, seemingly difficult. I''m struggling with a n:m relationship (in a database, that is) and its join table.

I''ve experimented around and have ran out of ideas, here''s the message: TypeError in True_false_questions#list can''t convert String into Integer RAILS_ROOT: script/../config/.. Application Trace <http://zbyte32:3000/true_false_questions/list/0#> | Framework Trace <http://zbyte32:3000/true_false_questions/list/0#> | Full