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The S-plus function moving.ave(data, span = 2) calculates the moving average, but it does not have an argument to tell it how to deal with NA values, so it will return NA for all averages as shown below. Is there an R or S moving average function which is able to omit some NA values in the dataset? In the simple sample shown below it would be possible to just remove the rows with NA values. The

I have a work around for this, but can someone explain why the first example does not work properly? I believed it worked in the previous version of R, by selecting just the rows=200525 and omitting the na's. I just upgraded to 2.13. I am also concern with the row numbers being different in the selections, should I be worried? FYI, I just selected the first few rows for demonstration, please

Hello, again I'm on my weblog-script... having problems... This code: =========================== weblog <- read_weblog("web.log") weblog_by_date <- split(weblog, weblog$date) #for ( i in names(weblog_by_day) ) { print(i); print(weblog_by_day$i) } for ( datum in names(weblog_by_date) ) { print(datum) selected <- weblog_by_date[[datum]] res_size_by_host <-

REGISTE O SEU DOMÍNIO GRÁTIS Se tem um daqueles endereços complicados do tipo, http://www.endere\o.pt/paginas_pessoais/~minha_pagina/index.html, aproveite esta oportunidade para criar um endereço mais simples e fácil de comunicar, do tipo, www.minha_pagina.web.pt, SEM PAGAR NADA. Se tem um daqueles endereços complicados do tipo, http://www.endere\o.pt/paginas_pessoais/~minha_pagina/index.html,

REGISTE O SEU DOMÍNIO GRÁTIS Se tem um daqueles endereços complicados do tipo, http://www.endere\o.pt/paginas_pessoais/~minha_pagina/index.html, aproveite esta oportunidade para criar um endereço mais simples e fácil de comunicar, do tipo, www.minha_pagina.web.pt, SEM PAGAR NADA. Se tem um daqueles endereços complicados do tipo, http://www.endere\o.pt/paginas_pessoais/~minha_pagina/index.html,

REGISTE O SEU DOMÍNIO GRÁTIS Se tem um daqueles endereços complicados do tipo, http://www.endere\o.pt/paginas_pessoais/~minha_pagina/index.html, aproveite esta oportunidade para criar um endereço mais simples e fácil de comunicar, do tipo, www.minha_pagina.web.pt, SEM PAGAR NADA. Se tem um daqueles endereços complicados do tipo, http://www.endere\o.pt/paginas_pessoais/~minha_pagina/index.html,

REGISTE O SEU DOMÍNIO GRÁTIS Se tem um daqueles endereços complicados do tipo, http://www.endere\o.pt/paginas_pessoais/~minha_pagina/index.html, aproveite esta oportunidade para criar um endereço mais simples e fácil de comunicar, do tipo, www.minha_pagina.web.pt, SEM PAGAR NADA. Se tem um daqueles endereços complicados do tipo, http://www.endere\o.pt/paginas_pessoais/~minha_pagina/index.html,

Hi. I'm comparing output from rollapply.zoo, as produced by two versions of R and package zoo. I'm illustrating with an example from a R-help posting 'Zoo - bug ???' dated 2010-07-13. My question is not about the first version, or the questions raised in that posting, because the behaviour is as documented. I'm puzzled as to why na.rm no longer is passed to mean, i.e. why

Dear friends, I am trying to produce Contour Plot with R, but there are some NA in my data matrix. After I ran the following R script, I got the error message:"no proper `z' matrix specified". Does anybody know how to plot contour chart with R for the non-strict matrix? Thank you in advance!!!

Dear all, Say I have the following dataset: > DF x y z [1] 1 1 1 [2] 2 2 2 [3] 3 3 NA [4] 4 NA 4 [5] NA 5 5 And I want to omit all the rows which have NA, but only in columns X and Y, so that I get: x y z 1 1 1 2 2 2 3 3 NA If I use na.omit(DF), I would delete the row for which z=NA, obtaining thus x y z 1 1 1 2 2 2

I've forgotten to submit this as bug report (and haven't easily seen how to debug). The bug is both for is.na() and is.nan() {which makes much sense since the C code of the two is very similar!}; only one is shown below. Martin ------- start of forwarded message ------- From: Martin Maechler <maechler@stat.math.ethz.ch> To: R-core@stat.math.ethz.ch Subject: another is.nan

I am trying to it a particular nonlinear model common in Soil Science to moisture release data from soil. I have written the function as shown below according to the logist example in Ch8 of Pinheiro & Bates. I am getting the following error (R version 2.1.1) *Error in qr(attr(rhs, "gradient")) : NA/NaN/Inf in foreign function call (arg 1)* Below is the function and data. /#

buerkle@hawaii.edu writes: > Why is it that when a vector contains no NAs, na.omit returns an empty > vector rather than the object/vector that was passed to it? > > >na.omit(c(1,2,3,4)) > numeric(0) Well, because there is a bug in na.omit.default. The problem is in the section of code omit <- seq(along = object)[is.na(object)] nm <-

I'm trying out a Linksys PAP2T-NA. Calling out works great, no problems there. Calling in, though, the phone doesn't ring. Caller ID shows up, I can pick up the phone, and the call is connected, but no ring. I've tried it on two analog phones, same behavior. Suggestions? Asterisk SVN-branch-1.2-r31555. - James Moore

Full_Name: Bill Dunlap Version: 2.5.0 OS: Red Hat Enterprise Linux WS release 3 (Taroon Update 6) Submission from: (NULL) (24.17.60.30) If you read a dcf file with read.dcf(file,fields=c("Field",...)) and the file does not contain the desired field "Field", read.dcf puts a character NA for that entry in its output matrix. If you then call write.dcf, passing it the output of

>>>>> Soumen Banerjee <soumen08 at gmail.com> >>>>> on Sat, 21 Apr 2018 17:22:56 +0800 writes: > Hello! I am trying to fit a copula to some data in R and > I get the error mentioned above. This is the code for a > reproducible example - (not really reproducible: You did not set the random seed, so the data is different every time;

R-helpers! na.omit() can be used to remove rows with NA's but how can I remove columns ? and remember, which columns have been removed ? I guess I can do t(na.omit(t(o))) as shown below, but this probably creates a lot of overhead and I do not know which columns have been removed. Yours, R > o [,1] [,2] [,3] [1,] 1 NA 7 [2,] 2 NA 8 [3,] 3 NA 9 >

I have a vector Pes with 600 elements some of which are NA's. How can I form a vector of the indices of the NA's. for(i in 1:600) if(is.na(Pes[i])) print(i) prints the indices of the NA's but I can't figure out how to put the results in a vector. Thank you very much. Peter B. -- Peter B. Mandeville mandevip at deimos.tc.uaslp.mx Jefe del Depto. de

Dear Opus team, We are a PC, Tablets and Smartphones manufacturer in Brazil http://www.positivoinformatica.com.br/ . We were informed that the VP9 Video Codec will be added by Microsoft in the new versions of our contracts with them. We reseached this codec and sow that is developed by you and is royalty free. Would you please help me to check whether to sign any tipe of contract for the

Dear experts, Please forgive the puzzled title and the length of this message - I thought it would be best to be as complete as possible and to show the avenues I have explored. I'm trying to fit a linear model to data with a binary dependent variable (i.e. Target.ACC: accuracy of response) using lrm, and thought I would start from the most complex model (of which "sample1.lrm1" is