similar to: Filling data frame data into a matrix - please help

Hi: Apologies for asking the following question. As?this may sound very basic and stupid for this forum?, I honestly do not know how to solve it and I do not have a teacher who can help me understand. ? I have list of genes (200)?that are involved in a particular process and I call this as a?ProcSet.?? From an independent experiment I found that out of 10,000 genes, 1500 are significant and I

dear group, i have a data matrix with some replicate items with different values. I want to extract the row with max value. for example: > x fruit weight 1 apple 1.3 2 apple 1.5 3 apple 1.6 4 orange 1.4 5 orange 1.6 x is a data frame. I want to extract unique items from fruits that has max weight. that is: 3 apple 1.6 5 orange 1.6 I want to be able to use

Dear Group, I have a data frame like the following: x <- c("Mike","A",0.01) x1 <- c("Carl","A",0.2) x2 <- c("Gene","C",0.3) x3 <- c("James","A",-0.3) x4 <- c("Dough","B",0) xx <- rbind(x,x1,x2,x3,x4) colnames(xx)<-c("Name","Class","NES") xx

Dear R-helpers, Lists in R are stumbling block for me. I kindly ask you to help me able to write a data-frame. I have a list of lists. > sls[1:2] $Andromeda_maya1 x y [1,] 369 103 [2,] 382 265 [3,] 317 471 [4,] 169 465 [5,] 577 333 $Andromeda_maya2 x y [1,] 173 507 [2,] 540 395 [3,] 268 143 [4,] 346 175 [5,] 489 91 I want to be able to write a data.frame like

hi I need help with list object. I have a list object > a <- c('apple','orange','grape') > b <- c('car','truck','jeep') > c <- list(a,b) > names(c) <- c('fruit','vehicle') > c $fruit [1] "apple" "orange" "grape" $vehicle [1] "car" "truck"

I'm trying to export a large data frame to a text file for permanent storage. The only thing I could find was the treeglia Package but that didn't work. Any suggestions? Thanks! Christina D Smith PhD Student, GRA Statistics Department Kansas State University

Hello Group, What is the meaning of the error. is there any place to look for this. I guess 'atomic' seems to be OOP related concept. thank you srini

I have not had a great amount of success installing/updating packages from the "Packages" menu of Rgui under Windows XL. (Except for installing from loacal zip files.) But I am not asking for help in using these facilities because I prefer to keep a folder of package zip files. On the other hand I do find it tedious having to right-click "Save link as" on every individual

I am analyzing some data obtained after measuring some parameters at different times in samples obtained from many subjects. The model is quite simple: aov(parameter ~ Time + Error(Subject/Time)) Now I want to make a pairwise comparison between the levels of Time. However, I have not find how to do such a thing. I cannot use TukeyHSD or pairwise.t.test, I supposse. Maybe using contrasts? Could

I hope this time I'm using the "iris" dataset correctly: ir <- rbind(iris3[,,1], iris3[,,2], iris3[,,3]) lir <- data.frame(log(ir)) names(lir) <- c("a","b","c","d") I'm trying to understand the meaning of expressions like "~ a+b+c+d", used with princomp, e.g. princomp(~ a+b+c+d, data=lir, cor=T) By inspection, it

hello: I have 3 data.frame objects. First df object: Of dim (149,31). Columns 2:31 are marked as T1..T14 and N1..N16. Name T1 T2 N1 T3 N2 N3 N4 T4 mu1 10 10 9 10 9 9 8 10 mu2 11 11 9 11 9 9 9 11 ... muN 12 12 9 11 9 9 8 12 Second df object: of Dim (50000,31). Columns 2:31 are maked as T1...T14 and N1..N16.

hi: I have matrix with dimensions(200 X 20,000). I have another file, a tab-delim file where first column variables are row names and second column variables are column names. For instance: > tmat Apple Orange Mango Grape Star A 0 0 0 0 0 O 0 0 0 0 0 M 0 0 0 0 0 G 0 0 0 0 0 S 0 0 0 0 0

hello: I am very confused when it comes to list operations in R. I seek help in the following problem. I have two different vectors myIDs - a character vector with no names to their elements x2 - another character vector derived from unlisting a list where an element has both a name and value. I am not happy the way x2 is with names and values to every element. > myIDs[1:10] [1]

Dear all: I have a character object x with ' (single-quote) character. x <- c('"hydrolase activity","actin binding","3',5'-cyclic-nucleotide phosphodiesterase activity") I want to write a function that will identify ' and replaces with \' myf <- function(term){ if (grep("'",term)) {

It might be a bit faster to do matrix indexing: R> tbm <- as.matrix(tb) # turn it into a character matrix R> tmat[cbind(match(tbm[,2], rownames(tmat)), match(tbm[,1], colnames(tmat)))] <- 1 > tmat Apple Orange Mango Grape Star A 1 1 1 0 0 O 1 1 0 0 0 M 0 0 1 0 0 G 0 0 0 0 0 S 1 1 1 0

Greeting R Community, I'm trying to learn Logistic Regression on my own and am using An Introduction to Logistic Regression Analysis and Reporting (Peng, C., Lee, K., & Ingersoll, G. ,2002). This article uses a Score Test Stat as a measure of overall fit for a logistic regression model. The author calculates this statistic using SAS. I am looking for an [R] function that can compute

While writing a function that includes placing grid lines at the same position as the axis ticks, I found that the axis* functions don't return anything. Thus I have had to copy the appropriate function, removing the call to axis() and adding a line to return the tick positions. Is there a more elegant way to determine the tick positions on an axis? Thanks. Jim (normally bitwrit at

I intend to use Dovecot without SSL. Hence, I built it without SSL support. When I am trying start Dovecot, I am getting the following error message. I have set ssl=no in 10-ssl.conf. Can anyone please let me know if it is possible to build and run Dovecot without SSL support?? If it is, how can I overcome the following error message? ? Thanks a lot. Srini ? Sep 21 11:18:11 master: Info: Dovecot

Hi Joel/Srini, Here are 2 patches for orphan lock in local mode. patch 1: In local mode, we don't need lvb, so don't init it. patch 2: In local mode, orphan lock and unlock don't need to go to dlm part. Regards, Tao

Hi There, There are 300 boy students and 100 girl students in a class. One interesting question is whether boy is smarter than girl or not. first given the exam with a difficulty level 1, the number of the student who got A is below 31 for boy, 10 for girl. Then we increase the difficulty level of the exam to level 2, the number of the student who got A is below 32 for boy, 10 for girl. We