similar to: image question

Dear All I want to plot a kind of figures, which can interactive with user. For example, i have a matirx which can be showed by image function. i.e. we can compare the value depend on different colors. However, the change of colors depend on the range of value. Nowaday, i want to set a bar, which can be moved by user such that the user can obtain the appropriate range. Does anyone suggest me which

Hi, Is it possible to diagonally fill a rectangle with a color gradient? I noticed that the gradient.rect of plotrix could fill a rect either up and down or from side to side. I am looking for something similar but fills diagonally instead, e.g., from the upper left corner to the bottom right. Does anyone know how to do it in R? Thanks, -- Tom [[alternative HTML version deleted]]

I need grayscale formatting for a wireframe. The only col.regions that I can find are color palettes are all colored: rainbow(n, s = 1, v = 1, start = 0, end = max(1,n - 1)/n, gamma = 1, alpha = 1) heat.colors(n, alpha = 1) terrain.colors(n, alpha = 1) topo.colors(n, alpha = 1) cm.colors(n, alpha = 1) The code follows: X11() library(lattice) par(family="serif", cex=1.2)

Hi, I have a vectors x and z, for example, x <- 0:20 z <- round(runif(20,1,7)) y <- 0.5 and I want to display z as an image. However if I then call image() with a vector image(x,y,t(z),zlim=c(1,7),col=heat.colors(7),xlab="Year",ylab="Action",yaxt="n",xaxs="r",yaxs="r") then I get the error Error in image.default(x, y, t(z), zlim =

Thanks for the proposition. As you see bellow, par("usr") is the same before and after the points() (the full code is bellow): .... > par("usr") [1] -0.2500000 1.2500000 -0.1666667 1.1666667 > # if you remove this points() function, axis will show nothing. > > points(1.5, 1.5, type="p") > p2 <- par(no.readonly=TRUE) > par("usr")

>>>>> Marc Girondot via R-help <r-help at r-project.org> >>>>> on Mon, 24 Jul 2017 09:35:06 +0200 writes: > Thanks for the proposition. As you see bellow, par("usr") is the same > before and after the points() (the full code is bellow): > .... >> par("usr") > [1] -0.2500000 1.2500000 -0.1666667

Thanks... I agree that the problem was explained in the documentation but I can't find a way to have axis() working even manipulating par("plt") or with graphics.reset = TRUE: - adding graphics.reset=TRUE does not allow axis() to be shown; - I see that par()$plt is involved but it is the not sufficient to explain why axis() works because if it is changed by hand, axes are not

I recently sent this email to a user in response to a problem report of phone calls going to voicemail without the phone ringing. I'm wondering if I've covered all bases, or whether there is some logical explanation I haven't considered, and generally what others' opinions/experiences are that relate. This is an Asterisk system, of course. ------- I looked at the server logs

Hi, I would have expected that I get always 3 colors as result which is not true: hcl.colors(3, alpha=c(0, 0.5, 1)) # 3 colors rainbow(3, alpha=c(0, 0.5, 1)) # 3 colors heat.colors(3, alpha=c(0, 0.5, 1)) # 3 colors terrain.colors(3, alpha=c(0, 0.5, 1)) # 6 colors cm.colors(3, alpha=c(0, 0.5, 1)) # 6 colors topo.colors(3, alpha=c(0, 0.5, 1)) # 9 colors R-Version and

Hello List! I asked this before (with no solution), but maybe this time... I'm trying to project a surface to the XY under a 3d cloud using lattice. I can project contour lines following the code for fig 13.7 in Deepayan Sarkar's "Lattice, Multivariate Data Visualization with R", but it fails when I try to "color them in" using panel.levelplot. ?utilities.3d says there

It is known (several discussions on internet) that axis() cannot be used after fields:::image.plot() (axis() shows nothing). However, if points(1.5, 1.5, type="p") is inserted before the axis() finctions, it works. I have investigated what points(1.5, 1.5, type="p") is doing to allow axis to work and I don't find a solution. par() options are identical (p1 and p2 are

Hello, I would like to make a plot (preferably lines, but points will do too), where the line segment changes color depending on the value of the y-axis. For example, let's suppose the y-axis range is from -1 to 1. Points close to -1 would be colored blue, while points close to 1 will be colored red. Points in between will be varying degrees of blue/red depending on how close they

To Whom It May Concern, I have been informed that there is a public domain software called "R" which is available through ftp://stat.auckland.ac.nz. I've tried the address but I can't find the software itself. Can you help me on this. Thanks. Belen Razo -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read

To Whom It May Concern, I have been informed that there is a public domain software called "R" which is available through ftp://stat.auckland.ac.nz. I've tried the address but I can't find the software itself. Can you help me on this. Thanks. Belen Razo -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read

Hi marc, Try: par("usr") before and after the call to points and see if it changes. Jim On Sat, Jul 22, 2017 at 12:05 AM, Marc Girondot via R-help <r-help at r-project.org> wrote: > It is known (several discussions on internet) that axis() cannot be used > after fields:::image.plot() (axis() shows nothing). > > However, if points(1.5, 1.5, type="p") is

Hi all, I was wondering whether it is possible to use the lapply() function to alter the value of the input, something in the spirit of : a1<-runif(100) a2<-function(i){ a1[i]<-a1[i-1]*a1[i];a1[i] } a3<-lapply(2:100,a2) Something akin to a for() loop, but using the lapply() infrastructure. I haven't been able to get rapply() to do this. The reason is that the "real"

Hi there, I have a binary matrix (dim 100x100) filled with values 0 and 1. I need select a record "n" positions of that matrix when values are 1. How can I do that? Thanks for all, Miltinho Brazil --------------------------------- [[alternative HTML version deleted]]

Hi there, I run two regressions: y = a1 + b1 * x + e1 y = a2 + b2 * z + e2 I want to test against the null hypothesis: b1 = b2. How do I design the test? I think I can add two equations together and divide both sides by 2: y = 0.5*(a1+a2) + 0.5*b1 * x + 0.5*b2 * z + e3, where e3 = 0.5*(e1 + e2). or just y = a3 + 0.5*b1 * x + 0.5*b2 * z + e3 If I run this new regression, I can test against

Hi All, I would like to fill the area under a curve with a gradient of colors. Are there any packages or trick I could use Thanks Stefan Stefan Van Dongen Antwerp [[alternative HTML version deleted]]

Questions on image: 1) How can I put labels on the x and y axes? 2) How to tell it to use e.g. 32 grey levels (not some colour map)? 3) How to know what the legend is (i.e. each grey level = what z value)? Thanks very much for any help. BTW I was wondering if persp was on the To Do list. That would be great! Bill Simpson