Displaying 20 results from an estimated 900 matches similar to: "R: determinants and inverses"
2010 Feb 11
1
Fwd: Recall function: "evaluation nested too deeply: infinite recursion / options(expressions=)?"
hello all
i searched the archives and couldn't get a solution to the following question.
i have the following function:
F=function(z,v)
{
if (v==-.5) return(1) else return(2*v/z + 1/Recall(z,v-1))
}
and while testing whether it works (ie F(z,v) is approx = besselK(z,1+v)/besselK(z,V). the recursion formula allows one to calculate besselK(z,1+v)/besselK(z,V) for large values of z )
2009 Feb 23
1
r: intergrate behaviour
hello R users
strange behavior of the integrate function!
i assume this occurs because of the way in which the quadriture is set up! (any comments.)
f=function(x){exp(-exp(-x)-5*x)/gamma(5)}
xx=seq(from=-20, to=20, length.out=1000)
plot(xx,f(xx),type="l")
integrate(f, lower=-Inf, upper= 1)
integrate(f, lower=-Inf, upper= 10)
integrate(f, lower=-10, upper= 11)
integrate(f,
2007 May 02
1
missing values
hello,
I need your help for this example
> for(k in LR) {
+ donGeno[[k]] <- as.numeric(levels(factor(subset(don2, Id_Essai == 1006961 & Id_Cara == LC[1] & Id_Rep == k, select = Id_Geno)[,1])))
+ print(donGeno[[k]])}
[1] 65125 65126 65127 65128 65129 65130 65131 65132 65133 65134 65135 65136 65137 65138 65139 65140 65141 65142 65143 65144 65171
[1] 65126 65127 65128 65129 65130
2009 Jan 02
1
R: numerical integration problems
hello all
happy new year and hope you r having a good holiday.
i would like to calculate the expectation of a particular random variable and would like to approximate it using a number of the functions contained in R. decided to do some experimentation on a trivial example.
example
========
suppose x(i)~N(0,s2) where s2 = the variance
the prior for s2 = p(s2)~IG(a,b)
so the posterior is
2007 Sep 20
2
referencing packages?
Hi
I know how to referenc R in a scientific paper - but is there a
standardised way to reference packages?
Thanks
Rainer
--
NEW EMAIL ADDRESS AND ADDRESS:
Rainer.Krug at uct.ac.za
RKrug at sun.ac.za WILL BE DISCONTINUED END OF MARCH
Rainer M. Krug, Dipl. Phys. (Germany), MSc Conservation
Biology (UCT)
Plant Conservation Unit
Department of Botany
University of Cape Town
Rondebosch 7701
2007 Oct 01
4
Concatenating one character vector into one string
Hi
I am sure this is simple - but how can I convert one charecter vector
into one string?
example:
x <- c("This ", "is ", "one ", "sentence.")
should become
"This is one entence"
Thanks
Rainer
--
NEW EMAIL ADDRESS AND ADDRESS:
Rainer.Krug at uct.ac.za
RKrug at sun.ac.za WILL BE DISCONTINUED END OF MARCH
Rainer M. Krug, Dipl. Phys.
2010 Feb 11
0
Recall function: "evaluation nested too deeply: infinite recursion / options(expressions=)?"
hello all
i searched the archives and couldn't get a solution to the following question.
i have the following function:
F=function(z,v)
{
if (v==-.5) return(1) else return(2*v/z + 1/Recall(z,v-1))
}
and while testing whether it works (ie F(z,v) is approx = besselK(z,1+v)/besselK(z,V). the recursion formula allows one to calculate besselK(z,1+v)/besselK(z,V) for large values of z )
2010 Jan 18
0
linking r and C
hello
i have a few quick questions.
i am using a windows platform.
how does one include functions from a particular r package in the C code. e.g. rgamma can be included if we include #include <R.h>
#include <Rmath.h> , and #include <math.h> in the C code. what should be included if i want to use functions that are inside the MASS package (for example)?
When performing mcmc
2008 Mar 14
2
Selecting elements in vector
Hi
Consider the following code
> x <- rep(1:13, 13)
> y <- 1:3
I want to select all elements in x which are equal to 1, 2 or 3.
I know that I could use
> sel <- x==y[1] | x==y[2] | x==y[3]
> x[sel]
to obtain the values, but in my analysis, the y-vector is thousands of
elements long.
Is there any way, that I can do that easily?
Thanks
Rainer
--
Rainer M. Krug, Dipl.
2007 Aug 16
6
several plots on several pages
Hi
> version
_
platform i686-pc-linux-gnu
arch i686
os linux-gnu
system i686, linux-gnu
status
major 2
minor 5.1
year 2007
month 06
day 27
svn rev 42083
language R
version.string R version 2.5.1 (2007-06-27)
I want to create a pdf withe three graphs on a page and with two pages:
2008 Jun 12
2
numbers as part of long character
Hi,
I'm looking for some way to pick up the numbers which are contained and buried in a long character.
For example,
outtree.new="(((B:1204.25,E:1204.25):7581.11,F:8785.36):8353.85,C:17139.21);"
num.char =
2007 Dec 17
3
Cannot grasp how to apply "by" here...
I have a data frame named "database" with panel data, a little piece
of which looks like this:
Symbol Name Trial Factor1 Factor2
External
1 548140 A 1 -3.87
-0.32 0.01
2 547400 B 1 12.11
-0.68 0.40
3 547173 C 1
2007 May 28
1
Where to find "nprq"?
Hi
I am trying to install the package "pheno", but it needs the package
"nprq" by Roger Koenker et al. which I can I find this package? It does
not seem to be on CRAN and googling also doesn't give me an URL - is it
still somewhere available?
Thanks,
Rainer
--
NEW EMAIL ADDRESS AND ADDRESS:
Rainer.Krug at uct.ac.za
RKrug at sun.ac.za WILL BE DISCONTINUED END OF
2008 Mar 07
1
How to navigate in layout() created graph?
Hi
I created a complex layout with using layout() and it looks exactly as
I need it. But I don't want to print in the order in which the
subfigure are numbered, but in a different order.
How can I navigate in the layout so that I can specify the subfigure
in which to plot?
At the moment I am using a function which is converting the number to
mfg parameter for par, but it does not seem to
2008 Jul 09
1
version problems of rkward in ubuntu hardy repository
Hi
I tried to install rkward under ubuntu hardy heron, but it tried to
use the one from the cran repository which was newer, but it did not
install. To be able to install rkward, I had to disable the cran
repository, install rkward, lock it's version and enable the
repository again.
I have the feeling, that the dependencies are not correct (it is
looking for libqt4GUI, but I have a
2008 Sep 08
1
Vorticity and Divergence
Hi all,
I have some wind data (U and V components) and I would like to compute
Vorticity and Divergence of these fields. Is there any R function that
can easily do that?
Thanks in advance for any help
Igor Oliveira
CSAG, Dept. Environmental & Geographical Science,
University of Cape Town,
Private Bag X3,
Rondebosch 7701. Tel.: +27 (0)21 650 5774
South Africa Fax: +27 (0)21
2007 Mar 05
4
Identifying last record in individual growth data over different time intervalls
Hi
I have a plist t which contains size measurements of individual plants,
identified by the field "plate". It contains, among other, a field
"year" indicating the year in which the individual was measured and the
"height". The number of measurements range from 1 to 4 measurements in
different years.
My problem is that I would need the LAST measurement. I only
2007 Jan 14
4
Controlling size of boxplot when it is added in a plot
Greetings,
I am trying to add a boxplot to the bottom of a histogram, right
between the histogram bars and the x axis. Here is the code I am
using at the moment (the par line is probably not relevant for our
discussion):
hs <- hist(x, breaks = 20, plot = F)
par(mar = c(3,3,2,1))
hist(x, breaks = 20, main = NULL, ylim = c(-2, max(hs$counts)))
boxplot(x, horizontal = T, axes = T, add =
2008 Feb 27
2
Plan to build Package to use GRASS from R
Hi
Sorry for crossposting, but I think this can be of interest for GRASS and R
users.
I am planning to write a package to make the use of GRASS from R easier. The
idea is to wrap the system call to execute the GRASS command into an R
command of the same name.
e.g:
r.to.vect <- function(..., intern=TRUE, ignore.stderr=FALSE)
{
comm <- paste( "r.to.vect ", ...,
2008 Feb 01
1
problem getting multiple densityplots on one page
Hi,
I used the following statements to generate unsuccessfully a 5 by 5 multiple
densityplots on a single page. If I use plot, the whole thing works.
> data <- matrix(rnorm(25), 5, 5)
> op <- par(mfrow = c(5, 5))
> for (x in 1:5) {densityplot(data[,x])}
> par(op)
Thanks
Stanley
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