similar to: Grouping data

I need to write code that will give me the previous value of from a data.frame. I have written the following code using the shift function from data.table . It does not work. I hope someone can help me correct the code. ########################### # Try to understand shift # ########################### if(!require(data.table)) install.packages("data.table") library(data.table) # Create

Hi, the command line with 'text' should be: text(-8,-8, expression(R^2 * " = 0.62, r = 0.79, N = 161"), cex = 2 ) Best, Kimmo su, 2024-02-04 kello 17:16 +0100, Jibrin Alhassan kirjoitti: > Here is the script I used to plot the graph indicating the text I > wanted to > insert. The line in the script that I have issues with is: text(-8,- > 8, > "R^2=?

Hi, you could use "scan" instead, it seems to work fine also when wrapped around "unz". Or, alternatively, you could use "unzip" instead of "unz". It works as expected, i.e. reads the last incomplete line and throws a warning about this. So it seems to me that "unz" creates a non-blocking connection, whereas "unzip" creates a

Hi, a quick additional note: try "edge.width= E(.)$weight" instead of the current "edge.width= network". Seems to work and makes a visible difference... HTH, Kimmo su, 2024-02-25 kello 19:11 +0000, Kimmo Elo kirjoitti: > > Hi again, > > your code is still not reproducible without modifications, but I > succeed in getting the data straight. All

Hi! I have used the following command: densityplot(~PV1CIV, groups=SGENDER, data=ISGFINC2, lwd=2, col=1, lty=c(1,2), pch=c("+","o"), key=list(text=list(lab=levels(ISGFINC2$SGENDER), col=1), space="bottom", columns=2, border=T, lines=T, lwd=2, lty=c(1,2), col=1), ref=T, plot.points=F) to produce a lattice density plot presenting the distribution of

I'm trying to figure out how to use lmer to fit models with factors that have some nesting and some non-nested groupings. For example, in this paper: http://www.stat.columbia.edu/~gelman/research/published/parkgelmanbafumi.pdf we have a logistic regression of survey respondents' political preferences (1=Republican, 0=Democrat), regressing on sex, ethnicity, state (51 states within 5

Hi, this seems to work (assuming that your problem was the setting of colours...): --- snip --- network %>% ggraph(., layout = "auto") + # This produces an error... # geom_edge_arc(curvature=0.3, aes(width=(E(network)$weight/10), color=c("darkblue", "red")[as.factor(edge_list$relationship)], alpha=0.5)) + # ... this works :-)

Hi, My problem is simple: since having updated the lattice package, I cannot load lattice anymore. If I type in the command 'library(lattice)' the loading fails with the following message: --- cut here --- Error in library.dynam(lib, package, package.lib) : shared library 'lattice' not found In addition: Warning messages: 1: In loadNamespace(package, c(which.lib.loc,

Hi, is there a command or parameter for reducing the plotting area with lattice? What I am looking for is an option similar to 'mai' or 'mar' from the graphs package. Background: I have plotted several charts with horizontal stacked bars and now I would like to add info about percentages of each "sub bar" beneath the plot (with mtext (?) ). So the plot should look

Hi, I have a small problem when using barchart. I have the following data: letters a 6 f 18 1 a 15 10 j 12 9 i 12 4 d 9 5 e 6 The data is from a survey and summaries the alternatives selected in one question. The idea is to have a bar chart illustrating the count of each selection in descending order. The data frame is already ordered in

Hi again, your code is still not reproducible without modifications, but I succeed in getting the data straight. All read.csv-command are missing 'sep="\t"', it is need to read you tsv-data. And it could be more reproducible if you used e.g. --- snip --- aes<-read.csv(text=" A.A B.B C.C D.D E.E F.F A.A 0 0 5 5 5 5 B.B 4 0 1 1 1 1 C.C 5 5 0 5 4 2 D.D 5 0 5 0 5 3 E.E

I am trying to use tree to partition a data set. The data set has 3924 observations. Partitioning seems to work for small subsets of the data, but when I use the entire data set, no partitioning occurs. The variables are: RESP respondent to a survey (0 = not a respondent, 1 = respondent) AGE_P Age (continuous) ORIGIN_I Hispanic Ethnicity (1 = Hispanic, 2 = non-Hispanic) RACRECI2 Race

Hi! I want to use R for network analysis and have tried to install the 'igraph' package. Unfortunately, the installation is aborted by an error: --snip-- gcc -std=gnu99 -I/usr/lib64/R/include -DNDEBUG -I/usr/local/include -DUSING_R -I. -Ics -Iglpk -Iglpk/amd -Iglpk/colamd -I/usr/local/include -fmessage-length=0 -O2 -Wall -D_FORTIFY_SOURCE=2 -fstack-protector -funwind-tables

Dear R-helpers, if I want to read a .dta-file generated by stata 9.0 with read.dta (foreign), I get the message "not a stata version 5-8 .dta-file". I'm using R-2.6.2 and the latest version of the foreign package. Has someone any hint? With many thanks, Albrecht

Hi, first of all, your example was not reproducible! But once I added "library(igraph)" and "library(scico)" plus generally replaced "aes_collapsed" by "edge_list", I started to work :-) Anyway, the error is produced by this line: + edge.width= network, It seems to me that you have forgotten to name a variable here (you now use the whole network

I have (toy example): x <- list(`1` = c(7, 13, 1, 4, 10), `2` = c(2, 5, 14, 8, 11), `3` = c(6, 9, 15, 12, 3)) and f <- factor(rep(1:3,5)) I want to create a vector v of length 15 such that the entries of v, corresponding to level l of f are the entries of x[[l]]. I.e. I want v to equal c(7, 2, 6, 13, 5, 9, 1, 14, 15, 4, 8, 12, 10, 11, 3) I can create v

Dear community Find enclosed the full working example. Many thanks Sibylle Test_cat.csv Names Subcategory_type sources.cyto source Factor A.A material "A" A 1 B.B material "B" B 1 C.C regulation "C" C 1 D.D regulation "D" D 1 E.E habitat "E" E 1 F.F cultural "F" F 1 Test_adjac.csv

Hi list I have a data frame I would like to loop over. To begin with I would like crosstabulations using the first variabel in the data frame, which is called "meriter". > table(meriter[[1]], meriter[[3]]) ja nej Annan 0

Dear r-help users, I am using Sweave and Latex to create tables with output from several statistical test. As an example: I have a grouping variable "group" with two levels ("x" and "y") which I compare on variables ("a" and "b"). I have created a table in which means, standard deviations, and the statistic and p.value resulting from a t.test is

Hi, i have that table Thesis Day A B C 1 0 83.43 90.15 22.97 1 0 85.50 94.97 16.62 1 0 83.36 95.38 20.70 1 0 84.47 92.16 23.58 1 0 83.98 95.33 19.39 1 0 82.86 93.78 24.55 1 0 83.39 92.67 19.56 1 0 85.17 95.24 17.95 1 0 81.62 93.32 28.49 1 0 82.99 92.85 19.73 1 0 81.11 95.67 27.20 1 0 83.39 94.69 16.51 1 0 79.56 89.87 30.39 1 0 80.54 93.32 21.76 1 0 82.11 92.58 22.17 1 14 85.65 94.00 19.19 1 14