similar to: plotting help request II

Hello dear R people, for my MSc thesis I need to program some functions, and some of them simply do not work. In the following example, I made sure both vectors have the same length (10), but R gives me the following error: Error in if (vector1[i] == vector2[j]) { : missing value where TRUE/FALSE needed I googled for possible solutions, but I did not find a good explanation for this...

Hi All, I am counting the number of occurrences of the terms listed in one vector in another vector. My code runs: for( i in 1:length(vector3)){ vector3[i] = sum(1*is.element(vector2, vector1[i])) } where vector1 = vector containing the terms whose occurrences I want to count vector2 = made up of a number of repetitions of all the elements of vector1 vector3 = a vector of NAs that is

Dear all, I was encountering with a typical Matching problem and was wondering whether R can help me to solve it directly. Let say, I have 2 vectors of equal length: vector1 <- LETTERS[1:6] vector2 <- letters[1:6] Now I need to match these 2 vectors with all possible ways like: (A,B,C,D,E) & (a,b,c,d,e) is 1 match. Another match can be (A,B,C,D,E) & (b,a,c,d,e), however there

Dear Statisticians--- This is not even an R question, so please forgive me. I have so much ignorance in this matter that I do not know where to begin. I hope someone can point me to documentation and/or a sample. I want to compute a covariance as quickly as non-humanly possible on an Intel core processor (up to SSE4) under linux. Alas, I have no idea how to engage CPU vectorization. Do I need

hi is there a faster way to do this? i <- 1 for(x in vector1) for(y in vector2) { m[[i]] <- (x - y) i <- i + 1 } regards soren -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in

Looking for help with the following problem. Given a sample of zeros and ones, for example: > VECTOR1<-rep(c(1,0),c(15,10)) > VECTOR1 [1] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 How would I create a new sample (VECTOR2) also containing zeros and ones, in which the phi-coefficient between the two sample vectors was drawn from a population with a known

Hello, My name is Ick Hoon Jin and I am Ph. D. student in Texas A & M Univ.. When I run the C embedded in R in the Linux system, I confront the following error after 6,000 iteration. By googling I found this error is from the problem in C. *** caught segfault *** address (nil), cause 'memory not mapped' My C code is following:

Hi, I have many files containing one column of data. I like to use the scan function to parse the data. Next I like to bind to a large vector. I try this like: count<-1 files <- list.files() # all files in the working directory for(i in files) { tmp <- scan(i) assign(files[count], tmp) count<-count+1 } This part works! Now I like to plot the data in a boxplot.

Hola Jose, si CONCATENAR significa APILAR, es decir, concantenar verticalmente, por decirlo de algun modo, podrias hacerlo con rbind(): nuevovector <- rbind(vector1,vector2) Si ademas quieres que cada valor de los vectores originales sea identificado en el nuevovector, puedes usar: nuevovector <- stack(vector1,vector2) en este ultimo caso se agrega una columna adicional tipo factor, con

Dear all, i need some help with plotting. the specific problem is the following: #FYI a=100 b=95 d=94.5 e=70 all=c(a,b) all2=c(d,e) plot(all,type="b",col="blue",xlim=c(1,4),ylim=c(20,150)) lines(all2,type="o",col="yellow") this does work so far, but ... i´d like to have 4 intersects, just named by characters.. no scale please. the second problem is,

Hello everyone, I have two vectors having only one element different: vector1 vector2 vector1 TWC TWC TWC VFC TWX NA VIA/B VFC VFC

Dear all, I hope you can forgive me my stupid questions, but I am a very new R user (; So, this is my question: I have two matrices, those are: matrix1 <- matrix(cbind(vector1, vector2), 1,2, dimnames = list(c("values"), c("T value", "p value"))) matrix2 <- matrix(dcbind,2,6,dimnames =

Hi All, I am trying to match two character arrays (email lists) using either pmatch(), match() or charmatch() functions. However the function is "missing" some matches due to differences in the cases of some letters between the two arrays. Is there any way to disable case sensitivity or is there an entirely better way to match two character arrays that have identical entries but written

Another question on functions - I have something that looks like plotter<-function(i){ temp.i<-rwb[rwb$vector1 <=(i*.10),] with(temp.i, plot(vector2, vector3, main=(i*.10),)) mod<-lm(vector3~vector3-1,data=temp.i) r2<-summary(mod)$adj.r.squared rsqrd[i]<-r2 legend("bottomright", legend=signif(r2), col="black") abline(mod) rsqrd<<-rsqrd } I'd

Hi, I got two data point vectors. Now I want to make a ks.test(). I you print both vectors you will see, that they fit pretty fine. Here is a picture: http://www.jochen-bauer.net/downloads/kstest-r-help-list-plot.png As you can see there is one histogram and moreover there is the gumbel density function plotted. Now I took to bin-mids and the bin-height for vector1 and computed the

Windows binaries at CRAN (bin/windows/Windows-NT/base) have been updated to R-1.1.0. See below for a list of Windows-specific changes. We thanks all the people who checked over pre-test versions. guido masarotto (for the R-core team) Windows-specific changes to R ============================= There is now a GUI preferences editor on the Edit menu in Rgui. A data entry editor is now

Windows binaries at CRAN (bin/windows/Windows-NT/base) have been updated to R-1.1.0. See below for a list of Windows-specific changes. We thanks all the people who checked over pre-test versions. guido masarotto (for the R-core team) Windows-specific changes to R ============================= There is now a GUI preferences editor on the Edit menu in Rgui. A data entry editor is now

Dear all, i just wonder if there´s a way to use a two column time index field in plm package. the manual says the following concerning data indexing: a character vector of length two containing the names of the individual and the time index, What would y´all do with a quarterly dataset that contains one column for the period and one for the year. Do I have to convert it to one single date

Dear R users, I have a problem computing time differences using R. I have a date that are given using the following format: 20080620.00, where the 4 first digits represent the year, the next 2 ones the month and the last 2 ones the day. I would need to compute time differences between two vectors of this given format. I tried around trying to change this format into any type of time serie

por favor como se calculan las probabilidades para conformar el segundo vector SI.Distr, en este ejemplo puse la existente en SARS2003 #Análisis paso a paso rm(list = ls()) #existe información de la incidencia de casos de una enfermedad incidencia <-c (1,0,0,0,0,0,0,0,2,1,1,0,1,2,0,2,0,2,2,2,3, 1, 2, 0,2, 0, 1, 1, 2, 1, 1, 2, 3, 0, 1, 2, 0, 2, 1, 3, 1, 6, 3, 3,7, 4, 4, 3, 6,