similar to: Plot error

Hi all, Sorry to be bothering again with probably an easy error to fix, but I've been trying to solve the problem and haven't been able yet to do it. So I'm doing this: > dados<-read.table("b.txt",sep="",nrows=30000) >

Hi all, I don't know how to choose the formula to use when plotting an svm model, I think I'm using the wrong one and so that is why I'm having trouble. I should be very grateful if someone could help me on this.. > dados<-read.table("b.txt",sep="",nrows=30000) >

Hi. I'm trying to plot a pair of intertwined spirals and an svm that separates them. I'm having some trouble. Here's what I tried. > library(mlbench) > library(e1071) Loading required package: class > raw <- mlbench.spirals(200,2) > spiral <- data.frame(class=as.factor(raw$classes), x=raw$x[,1], y=raw$x[,2]) > m <- svm(class~., data=spiral) > plot(m,

Hi. I'm trying to plot a pair of intertwined spirals and an svm that separates them. I'm having some trouble. Here's what I tried. > library(mlbench) > library(e1071) Loading required package: class > raw <- mlbench.spirals(200,2) > spiral <- data.frame(class=as.factor(raw$classes), x=raw$x[,1], y=raw$x[,2]) > m <- svm(class~., data=spiral) > plot(m,

Hi all, I'm having this error, since I'm working with a data matrix I don't understand what's happening; I've tried several ways to solve this, even working with sparse matrix, but nothing seems to solve it, I've also tried svm (with a simple matrix 3*3 and still got the same error. > dados<-read.table("b.txt",sep="",nrows=30000) >

Hi all, I'm working with some data: 54 variables and a column of classes, each observation as one of a possible seven different classes: > var.can3<-lda(x=dados[,c(1:28,30:54)],grouping=dados[,55],CV=TRUE) Warning message: In lda.default(x, grouping, ...) : variables are collinear > summary(var.can3) Length Class Mode class 30000 factor numeric ### why?? I

Dear R Community, I'm trying to write a loop to split my data into different series. I need to make a new matrix (or series) according to the series code. For instance, every time the "code" column assumes the value "433" I need to save "date", "value", and "code" into the "dados433" matrix. Please take a look at the following

Hi There, I'm facing one problem to construct a vector using the "for" command: I have one matrix named 'dados' (same as /data/ from portuguese), for example: > dados[140:150,] [,1] [,2] [,3] [1,] 212.7298 0.14 0.11 [2,] 213.3778 0.14 0.11 [3,] 214.0257 0.15 0.11 [4,] 214.6737 0.15 0.12 [5,] 215.3217 0.15 0.12 [6,] 215.9696 0.15 0.12 [7,] 216.6176 0.16

Hi, I want to remove the outliers of my database with the following program (an observation is considered an outlier if it is bigger than second quartile + 1,5* distance interquartiles or less than second quartile - 1,5*distance interquartiles): for(i in 1:length(dados)){ q3=quantile(dados[i], probs=.75) q3=quantile(dados[i], probs=.50) q1=quantile(dados[i], probs=.25) d=q3-q1 for(i2 in

Hi all, I have problems in a dataframe variables types. Look: from a loop function: for(...){ ... dados.fin <- rbind(dados.fin, c(L=j, A=j^2, Nsp=nsps, N=length(amosfin$SP), AmT="am",NAm=nam, AMST=amst)) dados.fin <- rbind(dados.fin, c(L=j, A=j^2,

----- Original Message ----- From: "Silvano" <silvano at uel.br> To: <r-help at r-project.org> Sent: Thursday, June 30, 2011 9:07 AM Subject: Tables and merge > Hi, > > I have 21 files which is common variable CODE. > Each file refers to a question. > > I would like to join the 21 files into one, to construct > tables for each question by CODE. >

Hi R-masters! I have a problem and need your help. I have 9 discrete variables with 2 levels each. In exploratory analisys I generate one matrix with chi-square for tables with 2 ariables each with this script setwd("F:/") dados<-read.csv("log.csv")[,2:10] dados.x<-matrix(NA,ncol=9,nrow=9) for(i in 1:8){ for(j in (i+1):9){ tab<-table(dados[,i],dados[,j])

Hi, I am having some problems using bwplot(lattice) in my data. I want change some parameters: 1) Fontfamily to serif 2) The size of the font 3) Put it in a bold face 4) Change de color of the lines How can I do that?! Now, I am using this to plot my boxplot. dados <- data.frame(varsep=as.factor(rep(1:2,10)),i=runif(20))

I am using pyramid.plot() from the plotrix package. I have something like this ############################################ xy.pop<-dados$masfr xx.pop<-dados$femfr #agelabels<-dados$femlab xycol<-color.gradient(c(0,0,0.5,1),c(0,0,0.5,1),c(1,1,0.5,1),11) xxcol<-color.gradient(c(1,1,0.5,1),c(0.5,0.5,0.5,1),c(0.5,0.5,0.5,1),11) xylab<-dados$maslab xxlab<-dados$femlab

Hola, ¿hay alguna forma de colocar la leyenda de un gráfico sin que se superponga con las barras de mi gráfico? Os dejo mi ejemplo para que me entendáis: ## dado_1<-sample(1:6,1200,replace=T)dado_2<-sample(1:6,1200,replace=T)dado_3<-sample(1:6,1200,replace=T) dados<-matrix(c(table(dado_1),table(dado_2),table(dado_3)),6) barplot(t(dados),beside=TRUE,ylab="Frecuencias

I was trying to make some multi figure plots and I had some strange problems. I'm using R 0.61.2. When I make this plot >postscript(file="timeplot5.ps",horizontal=TRUE) >par(mfrow=c(2,2)) >plot(dados$a1) >plot(dados$a2) >plot(dados$a3) >plot(dados$a4) The last panel is ploted without the box and it is always ploted in landscape mode. Can anyone reproduce this

Bom dia eu chamo-me Ana, estou a tentar fazer matriz de correla??o e covariancia para comparar 4 variaveis e saber quais s?o as mehores... fiz o segundo codigo mas devo tar a fazer alguma confus?o para nao me aparecer o output correcto: cor(dados[,2:5],method=c("pearson")) cor_with_p_test(dados[2:5]) ct <- cor.test(dados[,2:5]) ct$p ct$v #matriz de covariancias cov(dados[,2:5],

Hello rowland, follow the informations: 1) ./configure --prefix=/opt/samba --enable-selftest --enable-debug 2) samba-tool domain provision --domain=CMC --adminpass=Mudar2016 --dns-backend=BIND9_DLZ --server-role=dc --use-rfc2307 --realm=CMC.CORP 3) I created a script to start this as described in the manual Samba4 [global] netbios name = SAMBA realm = CMC.CORP

GUYS, I NEED HELP WITH ERROR: library(MASS) > dados<-read.table("mediaRGinverno.txt",header=FALSE) > vento50<-fitdistr(dados[[1]],densfun="weibull") Erro em fitdistr(dados[[1]], densfun = "weibull") : Weibull values must be > 0 WHY RETURN THIS ERROR? WHAT CAN I DO? BEST REGARDS [[alternative HTML version deleted]]

Hi, I am trying plot a grafic but generates an error: Erro em plot.default(xlim, ylim, type = "n", ann = FALSE, axes = FALSE, : argumento formal "type" corresponde a múltiplos argumentos especificados DATA: 44 40 39 38 0 7 7 1030 57 37 5146 40 41 4737 34 36 2636 28 33 3738 26 28 2742 38 36 3636 27 22 2853 43 33 40 plot(dados[1],type="o",pch=21,