similar to: Symbolic substitution in parallel; use infinity symbol?

expression() accepts multiple expressions as arguments, thus: plot(1:2, 1:2) legend("topleft", expression(y == a * x^b, "where "* paste(y=="wood; ", x=="dbh"))) Is there a way to do this when values are to be substituted for a and b? i.e., the first element of the legend argument to legend() becomes,

Hi list. I''m writing a program that stores a lot of Floats into MySQL database. Simplified version of the program use the following form of class. class Val < ActiveRecord::BASE end And Vals table contains one column: num double One of my data contains -Infinity for num and when I try to Val.new Val.num = <- Here goes -Inifinity Val.save! Then the program crashes:

In this connection, note the following > a4 <- 4 > plotThis <- bquote(alpha==.(a), list(a=a4)) > do.call(plot, list(1:10, main=do.call(expression, c(plotThis)))) > do.call(plot, list(1:10, main=do.call(expression, plotThis))) Error in do.call(expression, plotThis) : second argument must be a list > ## Whereas plotThis has class "call", c(plotThis) has class

sorry the integration was from -Inf to 1.96 The integrate function in R is not taking Inf (infinity). How do you use infinity in R. I was doing: integrate(dnorm,- Inf, 1.96) and I was getting Error: NA/NaN/Inf in foreign function call (arg 2). Obviously this should be equal to pnorm(1.96)= 0.9750021. How do you get around the infinity problem in R?

In the following titletxt <- substitute(paste(tx, tilde(y) == sqrt(y)), list(tx="Replace y by ")) I'd like to be able to replace e.g. sqrt(y) by a symbol or symbolic expression that has the effect of inserting sqrt(y) into the place that it occupies. This would allow me to put an arbitrary expression into that position. [One can use text() or mtext() etc. to place titletxt

Bug Using read.table(file, encoding="UTF-8") to import a UTF-8 encoded file containing the infinity symbol (' ? ') results in the infinity symbol imported as the number 8. Other Unicode characters seem unaffected, example, Zhe: ? Expected Behavior: The imported data.frame should represent the infinity symbol as the expected 'Inf' so that normal mathematical operations

This seems like such an obvious idea that I''m having trouble believing I''m the first to think of it. Why not take ranges containing Float::INFINITY and translate them to the appropriate greater than or less than comparisons? Example: class Person scope :voters, -> { where(born_on: (-Float::INFINITY..18.years.ago)) } end This would generate something along the lines of

I have to calculate some formula like: gamma(x)/(gamma(x+y) and I observed that for relatively big values of x, R returns infinity and so cannot compute the formula. Is it possible to force R to give the real value of gamma(x) instead of Inf ? thanks

Dear members, here is my trouble: My data consists of counts of trapped insects in different attractive traps. I usually use GLMs with a poisson error distribution to find out the differences between my traitments (and to look at other factor effects). But for some dataset where one traitment contains only zeros, GLM with poisson family fail to find any difference between this particular traitment

I can confirm that it doesn't happen on Ubuntu 18.04.1 so Peter is most likely correct; it looks like its Windows specific. On Thu, 7 Feb 2019 at 12:55, peter dalgaard <pdalgd at gmail.com> wrote: > > This doesn't seem to be happening on MacOS, neither in Terminal nor RStudio, (R 3.5.1, R-devel, R-patched). So probably Windows specific. > > -pd > > > On 7 Feb

Hi r-users, How do we evaluate the summation of (1/m!) from 0 to infinity (for example). Any help is very much appreciated. Thank you.

I can reproduce this behavior on my Windows 10 system in RGui (cp1252): when I paste the Unicode infinity symbol into the console, it is treated as number 8. This is caused by Windows "best fit" default behavior in conversion of unicode characters to characters in the current native encoding: at some point in the past, 8 has been chosen as a good fit for infinity in Windows. In my

Hi, I am trying to fit a sigmoid curve to some data with nls but I am getting into some trouble. Seems that the optimization method is getting down to some parameter estimates that make the equation unsolvable. This is an example: >growth<-data.frame(Time=c(5,7,9,11,13,15,17,19,21,23,25,27),BodyMass=c(45,85,125,210,300,485,570,700,830,940,1030,1120))

Hello, I am trying to include legend text with math symbols from a predefined character variable that is read in from a file. ? If there is only one line of text in the legend, the following, although cumbersome, works for me: ? > LegendText = " 'U' [infinity], '=10 m/s' "?? # (read in from a file) ??> LegendName = paste("bquote(paste(",LegendText,

Hi, I am a non-expert user of R. I am essaying the fit of two different functions to my data, but I receive two different error messages. I suppose I have two different problems here... But, of which nature? In the first instance I did try with some different starting values for the parameters, but without success. If anyone could suggest a sensible way to proceed to solve these I would be

This doesn't seem to be happening on MacOS, neither in Terminal nor RStudio, (R 3.5.1, R-devel, R-patched). So probably Windows specific. -pd > On 7 Feb 2019, at 11:17 , David Byrne <david.byrne222 at gmail.com> wrote: > > Bug > Using read.table(file, encoding="UTF-8") to import a UTF-8 encoded > file containing the infinity symbol (' ? ') results in

Dear R-users I hope someone could help me on this problem. I want to create a multiple kiteChart showing the real values with a scalebar on each indicating the scale . Here are some sample data to show what I want to achieve. Y <- read.table(textConnection("Sample1 Sample2 60 20 150 50 300

There seems to be something odd with "?" on Windows (and not only with read.table) In native encoding (cp-1252 in my case), "?" gets converted to "8" x <- "?" Encoding(x) #> [1] "unknown" print(x) #> [1] "8" charToRaw(x) #> [1] 38 "?" is indeed "8" identical(x, "8") #> [1] TRUE Everything

Hello R-help List I am writing some R scripts to create graphs of water quality trends that will be called by a web service running R. The axis titles will need to change as the input data (ie. water quality variable) changes according to a user's choice made via a web page. The way I am currently passing call-specific parameters to the R script is via a text file created on the fly by the

Tomas, > In my scenario, the conversion is invoked by RGui before returning the input to the main R loop, even before the input gets to the parser. In principle, we could change this particular conversion in RGui to avoid the substitution. Not sure whether I am missing something here, but I used RStudio for my examples (I should have said) and David's mentioned RStudio as well, so it does