similar to: newbie lapply question

Hi -- Is there a way of detecting the exit code while calling system or pipe? eg (on Unix) > system("perl -e 'print \"foo\\\n\";exit(-1);'") foo Any help appreciated, Ranjan

I'm fairly new to R, coming from a programming background -- it's quite nice to work with dataframes, though, as opposed to explicit iteration. One thing I've found, which is surprising is that zero-length dataframes seem to cause errors: > t <- data.frame(bob=c(100)) > order(t$bob) [1] 1 > t1 <- t[t$bob < 50] > order(t1$bob) Error in order(na.last, decreasing,

Hi -- I'm working with some data frames with fairly high nrows (call it 8 columns, by 20,000 rows). Are there any indexes on these columns? When I do a df[df$foo == 42,] [which I think is idiomatic], am I doing a linear search or something better? If the column contents is ordered, I'd like to at least be doing a naive binary search. Thanks! Ranjan

Full_Name: Bo Zhou Version: 2.6.1 (2007-11-26) OS: Windows XP Submission from: (NULL) (207.237.54.242) Hi, I found an arithmetic problem when I'm doing something with POSIXct The code to reproduce it is as follows (This is the recommended way of finding out time zone difference on R News 2004-1 Page 32 URL http://cran.r-project.org/doc/Rnews/Rnews_2004-1.pdf) a=Sys.time()

I was looking for all the glm-related 'family' functions in stats using the following predicate that returns TRUE for any function whose first argument is called "link". is.family <- function(object) is.function(object) && identical(names(as.list(object))[1], "link") It threw an error when applied to SSfol > is.family(SSfol) Error in

New function below is a bit faster due to more efficent memory handling. for-loop FTW! directionless_circular_permutations2 <- function( n ) { n1 <- n - 1L v <- seq.int( n1 ) ix <- combinations( n1, 2L ) jx <- permutations( n-3L, n-3L ) jxrows <- nrow( jx ) jxoffsets <- seq.int( jxrows ) result <- matrix( n, nrow = factorial( n1 )/2L, ncol = n ) k

I don't know if this is more efficient than enumerating with distinct directions and weeding... it seems kind of heavyweight to me: ####### library(gtools) directionless_circular_permutations <- function( n ) { v <- seq.int( n-1 ) ix <- combinations( n-1, 2 ) jx <- permutations( n-3, n-3 ) x <- lapply( seq.int( nrow( ix ) ) , function( i ) {

Jeff, I wanted to let you know that your function is faster than generating the directional circular permutations and weeding. Here is the time for n = 10. I compared with just doing the permutations, there is no point in proceeding further with the weeding since it is slower at the start itself. system.time(directionless_circular_permutations(10)) user system elapsed 1.576 0.000

Hello Sir, I am Reetesh Ranjan, a 3rd year undergraduate student at the *INDIAN INSTITUTE OF TECHNOLOGY BHU, Varanasi-*one of the premier engineering colleges of India. I have gone through your webpage thoroughly and I am very interested in the work that you are undertaking on *Project: Weighting Schemes.*. I earnestly wish to work under your guidance, learn and progress through this experience.

Dear all, I have a question with regard to the use of hclust. I would like to be able to specify my own distance matrix instead of asking R to compute the distance matrix for me. It is computationally easier for me this way. My question is: How can I get hclust to accept this? Thanks, Ranjan -- *************************************************************************** Ranjan

Thanks! Yes, however, this seems a bit wasteful. Just wondering if there are other, more efficient options possible. Best wishes, Ranjan On Thu, 29 Mar 2018 22:20:19 -0400 Boris Steipe <boris.steipe at utoronto.ca> wrote: > If one is equal to the reverse of another, keep only one of the pair. > > B. > > > > > On Mar 29, 2018, at 9:48 PM, Ranjan Maitra

https://bugzilla.mindrot.org/show_bug.cgi?id=3202 Bug ID: 3202 Summary: Ed25519 key on HSM is not getting listed in ssh-add -l command Product: Portable OpenSSH Version: 8.2p1 Hardware: ARM64 OS: Linux Status: NEW Severity: enhancement Priority: P5 Component: ssh-add

Hi Jeff, 1). I have tried install.packages( c("dplyr", "tidyr" ) ) into the r-script file got below error:- > install.packages( c("dplyr", "tidyr" ) ) Installing packages into ?/tmp/1776492876238396447/lib/portableR-master/site-library? (as ?lib? is unspecified) Error in install.packages(c("dplyr", "tidyr")) : This version of R is

Thanks! I am trying to use it in R. (Actually, I try to give my students experiences with different kinds of files and I was wondering if there were tools available for such kinds of files. I don't know Lisp so I do not actually know what the lines towards the bottom of the file mean.( Many thanks for your response! Best wishes, Ranjan On Wed, 17 Jan 2018 20:59:48 -0800 David Winsemius

> On Jan 17, 2018, at 8:22 PM, Ranjan Maitra <maitra at email.com> wrote: > > Dear friends, > > Is there a way to read data files written in lisp into R? > > Here is the file: https://archive.ics.uci.edu/ml/machine-learning-databases/university/university.data > > I would like to read it into R. Any suggestions? It's just a text file. What difficulties

If one is equal to the reverse of another, keep only one of the pair. B. > On Mar 29, 2018, at 9:48 PM, Ranjan Maitra <maitra at email.com> wrote: > > Dear friends, > > I would like to get all possible arrangements of n objects listed 1:n on a circle. > > Now this is easy to do in R. Keep the last spot fixed at n and fill in the rest using permuations(n-1, n-1)

Dear All, Assume I have a data.frame that contains also factors and I would like to get another data.frame containing the factors as numeric vectors, to apply functions like sapply(..., median) on them. I read the warning concerning as.numeric or unclass, but in my case this makes sense, because the factor levels are properly ordered. I can do it, if I write for each single column

1) Definitely yes. They are on CRAN. Just type install.packages( c("dplyr", "tidyr" ) ) at the R console. 2) Don't know, but most likely the answer is yes. Since all R packages on Linux are compiled by R when installed, you either need to activate your virtual machine, compile the packages, and save the state for future use, or you have to build the package library on

It seems the file contains records, with each record having 18 fields. I would use awk (standard unix tool), creating an awk script to process the file into a new file with one line for each record, each line with 18 fields, say comma-separated. The csv file can then be easily read into R via the function read.csv. HTH, Eric On Thu, Jan 18, 2018 at 6:22 AM, Ranjan Maitra <maitra at

Dear All, I seem entirely unable to solve what should be a very simple problem. I have imported a SPSS dataset into R using spss.get from Frank Harrell's Hmisc library. The variables are imported classed as 'labelled': missing values are coded as either the SPSS missing value code, 8 or 88. All are imported correctly; 8 and 88 being identified as true numbers in the