similar to: Order observations in a dataframe

At 2012-06-30, leap second will be introduced. ftp://hpiers.obspm.fr/iers/bul/bulc/bulletinc.dat Does Samba affect leap second? -- --- Oota Toshiya --- t-oota at dh.jp.nec.com NEC Systems Software Operations Unit Shiba,Minato,Tokyo IT Platform Solutions Division Japan,Earth,Solar system (samba-jp/ldap-jp Staff,mutt-j/samba-jp postmaster)

Hallo All, I would like to apply a function to all permutations of variables in a dataframe (except the first). What is the best way to achieve this? I produce the permutations using: nvar <- ncol(dat) - 1 perms <- as.matrix( expand.grid(rep( list(1:0) , nvar ))[ , nvar:1] ) Thanks in advance Serguei Test-dataframe, comma-delimited: code,wav,w,area,gdp,def,pop,coast,milspend,agr

I glanced at the .leap.seconds object and noticed that it has not been updated for the most recent leap second that occurred 2005 December 31, 23h 59m 60s. See the IERS bulletin here: http://hpiers.obspm.fr/iers/bul/bulc/bulletinc.dat Moreover, after a more careful glance at the .leap.seconds object, I noticed that there are two incorrect entries. First, there was not a leap second on 1986 June

While I don't know anything about Box's M test, I googled around and found a Matlab M-file that computes it. Below is my straight-forward translation of the code, without knowing Matlab or the formula (and done in a few minutes). I hope this demonstrates one of Prof. Ripley's point: If you really want to shoot yourself in the foot, you can probably program R to do that for you. [BTW:

*Hola!!! resulta que tengo unos datos de divisas ordenados por fechas (días) los que he convertido a formato tipo YYYY-MM-DD donde DD siempre es 01:* * * * EUR.resto$date<-as.Date(EUR.resto$date) EUR.resto$mo <- substr(EUR.resto$date,6,7) EUR.resto$yr <- substr(EUR.resto$date, 1,4)

How should I install windows applications on clients joining a samba PDC? THX Davide Parise E-Mail: d.parise@agora.it

This is a mixed question, between theory and practice. I have a dataset with a continous variable grouped by a 33 levels factor. After having log-tranformed my original data I can assume the normality of my data but I have two strong departures from the basic assumptions for anova and t tests: *unbalanced data* (some groups contain ten samples, others hundreds) and *non homogenity of variances*

Is there a package in R that can do a variability plot? A variability plot is a kind of categorized dot plot. (If there is a lot of data in each category, box plots are used rather than dot plots.) Usually, the categories are factor level combinations. All the dot plots appear in the same window; below the x-axis a hierarchy of factors shows which dot plot corresponds to which factor-level

All, What would be the most efficient way to load the data at the following address into a dataframe? http://ratings.fide.com/top.phtml?list=men Thanks, David -- View this message in context: http://r.789695.n4.nabble.com/Loading-Chess-Data-tp4642006.html Sent from the R help mailing list archive at Nabble.com.

Hello list. I'm trying to rebuild the 2.6.9.67.0.20.EL kernel, but it fails even without modifications. How did I try it? Created a (non-root) build environment (not a mock ) Installed the kernel.scr.rpm and did a rpmbuild -ba --target=`uname -m` kernel-2.6.spec 2> prep-err.log | tee prep-out.log The build failed at the end: Processing files: kernel-xenU-devel-2.6.9-67.0.20.EL Checking

bonjour à toutes et à tous, d''abord désolé de ne pas parler/lire/comprendre l''américain/l''anglais, ce qui fait que j''ai beaucoup de mal à comprendre la doc par exemple. j''ai un souci d''utilisation de WXRuby avec SCIntilla, dans le cas d''un HTML + Javascript. je suis parti bien entendu de l''exemple scintilla.rb