Displaying 5 results from an estimated 5 matches similar to: "accessing the "address" of items in a recursive list"
2010 Sep 24
4
Object Browser
What's the best object browser?
Dear all,
I have tried all the popular R IDE or editors like Eclipse, Komodo, JGR,
Revolution...
They all have fancy fucntions like auto completion, syntax highlight....
BUT, I JUST WANT A OBJECT BROWSER!
The easiest way to view objects in R console is fix(), but you have no
global view of all the objects in the workspace.
Revolution has the best object
2012 Feb 20
3
Confused: Inconsistent result?
This is copy & paste from my session:
> xyz<-as.vector(c(ls(),as.matrix(lapply(ls(),class))))
> dim(xyz)<-c(length(xyz)/2,2)
>
> allobj<-function(){
+ xyz<-as.vector(c(ls(),as.matrix(lapply(ls(),class))));
+ dim(xyz)<-c(length(xyz)/2,2);
+ return(xyz)
+ }
> xyz
[,1] [,2]
[1,] "a" "character"
[2,]
2002 Apr 10
3
problem with do.call
Hi
I'm writing a function that uses four parameters (scalars) and I need to
run it in an iterative process (the parameters vary to find the minimum
RSS).
I don't want to use loops and so tried the do.call function. However it
didn't work. My understanding is that the do.call simple runs the
function replacing the arguments (scalars by vectors), instead of runing
the function for
2002 Apr 17
4
union of lists
Hi there,
Given 2 lists of integer vectors, i.e.:
> lista1
$"1"
[1] 1 34 5
$"2"
[1] 2 1
$"3"
[1] 3 10 15
> lista2
$"1"
[1] 1 5
$"2"
[1] 2 1
$"3"
[1] 3 10 29
I want to obtain the union of both, defined
as the union of the vectors, that is
lista.union[[1]] <- union(lista1[[1]],lista2[[1]]):
> lista.union
2000 Aug 21
2
Loop removal possible?
Dear all,
may be somebody have ideas to my following problem:
I have to multiplicate each element of a vector with his position
in the sorted vector. This isn't a problem ;-)
But now i have a weighting vector with the weight of each observation,
and my problem starts. A little example (due to my bad english) maybe
helps to understand:
x<-c(10,40,50,100) # income vector for instance