similar to: SAS Enterprise Miner -- OT

See: http://wwwpeople.unil.ch/jean-pierre.mueller/ ttda - tools for textual data analysis Regards Vito you wrote: Hi, Does a text miner exist in R-language similar to Splus miner or SAS text miner? I would appreciate any information. TIA, Aldi ===== Diventare costruttori di soluzioni Became solutions' constructors "The business of the statistician is to catalyze the scientific

Hello, Our company has been looking at "SAS enterprise guide 4" (Insightful Miner is a similar product from Insightful, I believe) which seems to provide a nice graphical way of displaying/managing a process or project. It is also accessible to non-programmers. Does any of the R GUIs provide similar functionality please? Can you point me in the right direction? Thanks in advance Best

EXPLORATORY DATA ANALYST / DATA MINER Australian Antarctic Division Band 6-7 (Research Scientist) AUS$47,563 - 63,922 pa The Exploratory Data Analyst (Data Miner) will use exploratory data analysis techniques to identify patterns in scientific data held in the Australian Antarctic Data Centre and elsewhere. The position has an equal emphasis on the exploratory and confirmatory aspects of

FYI, in R devel (to become 3.5.0), there's isFALSE() which will cut some corners compared to identical(): > microbenchmark::microbenchmark(identical(FALSE, FALSE), isFALSE(FALSE)) Unit: nanoseconds expr min lq mean median uq max neval identical(FALSE, FALSE) 984 1138 1694.13 1218.0 1337.5 13584 100 isFALSE(FALSE) 713 761 1133.53 809.5 871.5

Quite possibly, and I?ll look into that. Aside from the work I was doing, however, I wonder if there is a way such that sapply could avoid the overhead of having to call the identical function to determine the conditional path. From: William Dunlap [mailto:wdunlap at tibco.com] Sent: Tuesday, March 13, 2018 12:14 PM To: Doran, Harold <HDoran at air.org> Cc: Martin Morgan <martin.morgan

You?re right, it sure does. My suggestion causes it to fail when simplify = ?array? From: William Dunlap [mailto:wdunlap at tibco.com] Sent: Tuesday, March 13, 2018 12:11 PM To: Doran, Harold <HDoran at air.org> Cc: r-help at r-project.org Subject: Re: [R] Possible Improvement to sapply Wouldn't that change how simplify='array' is handled? > str(sapply(1:3,

Could your code use vapply instead of sapply? vapply forces you to declare the type and dimensions of FUN's output and stops if any call to FUN does not match the declaration. It can use much less memory and time than sapply because it fills in the output array as it goes instead of calling lapply() and seeing how it could be simplified. Bill Dunlap TIBCO Software wdunlap tibco.com On Tue,

I am glad to help. The pp program is the main tool to use to create the executable. -----Original Message----- From: "Duncan Murdoch" <murdoch at stats.uwo.ca> To: "Greg Snow" <Greg.Snow at intermountainmail.org> Cc: "Gabor Grothendieck" <ggrothendieck at gmail.com>; "Doran, Harold" <HDoran at air.org>; "r-help at

>>>>> Henrik Bengtsson <henrik.bengtsson at gmail.com> >>>>> on Tue, 13 Mar 2018 10:12:55 -0700 writes: > FYI, in R devel (to become 3.5.0), there's isFALSE() which will cut > some corners compared to identical(): > > microbenchmark::microbenchmark(identical(FALSE, FALSE), isFALSE(FALSE)) > Unit: nanoseconds > expr

Martin In terms of context of the actual problem, sapply is called millions of times because the work involves scoring individual students who took a test. A score for student A is generated and then student B and such and there are millions of students. The psychometric process of scoring students is complex and our code makes use of sapply many times for each student. The toy example used

Wouldn't that change how simplify='array' is handled? > str(sapply(1:3, function(x)diag(x,5,2), simplify="array")) int [1:5, 1:2, 1:3] 1 0 0 0 0 0 1 0 0 0 ... > str(sapply(1:3, function(x)diag(x,5,2), simplify=TRUE)) int [1:10, 1:3] 1 0 0 0 0 0 1 0 0 0 ... > str(sapply(1:3, function(x)diag(x,5,2), simplify=FALSE)) List of 3 $ : int [1:5, 1:2] 1 0 0 0 0 0 1 0 0

This is not an R question, but a question on some combinatorial mathematics. Apologies for the OT if it is wildy inappropriate. The traditional C(n.k) method tells me how many combinations k I can make with n objects. However, suppose I want the number of combinations where an object cannot be used more than Q times where Q is a parameter that changes? For instance: combn(LETTERS[1:5], 3) shows

Dear List: When I click on the link to download a reference manual for a package on cran, I get an error message that the file is damaged and could not be repaired. I randomly chose various packages and the same error message appears. Are the links actually broken? I have also restarted my machine and closed and re-opened acrobat. I am using Windows XP, Acrobat Professional 6.0.0.5, and

First off, Marc Schwartz posted this link earlier today, read it. http://cran.r-project.org/doc/FAQ/R-FAQ.html#Why-are-p_002dvalues-not-di splayed-when-using-lmer_0028_0029_003f Second, your email is not really descriptive enough. I have no idea what OR is, so I have no reaction. Third, you're comparing estimates from different methods of estimation. lmer will give standard errors that

Dear List I apologize for the multiple postings. After being in the weeds on this problem for a while I think my original post may have been a little cryptic. I think I can be clearer. Essentially, I need the following a <- c(2,3) b <- c(4,5,6) (2*4) + (2*5) + (2*6) + (3*4) + (3*5) +(3*6) But I do not know of a built in function that would do this. Any suggestions? -----Original

Hi all: I'm having difficulty with something I believe is very simple, but I'm stuck. I have a large data frame that took days to clean and prepare. All I now need to do is concatenate three variables into a single column. For example, I have tenn$up, tenn$down, and tenn$stable which all have values of 1 or 0. I simply want to put all three columns together to create a pattern (e.g.,

Harold: As a general rule, if you are using eval(parse(...)) you are doing it poorly in R; cf library("fortunes") fortune(106) Why is something like this not suitable: fun1 <- function(a1,a2,a3 = c("hi","by")) { cat(a3,a1+a2,"\n") } > fun1 (1,2) hi by 3 > fun1(1,2, a3 = "whoopee") whoopee 3 ... or, if you want to include the

Just out of curiosity, has anyone ever written a function that sends an email to you when an R process has finished? For instance, I often work with very large data sets and certain tasks (e.g., merging records, lmer runs) can take a long time and I find myself constantly looking over to see if R is done. But, it would just be neat if there was a way R could send me an email alerting me that a

Dear R: Am I having trouble downloading the LME4 library. I am using Windows and am using ver 1.7 I have tried the following: 1) Install package from CRAN, but LME4 is not listed 2) Downloaded LME4 from http://cran.us.r-project.org/, however, I cannot open the file when I try install from local drive. I get the following error: Error in file(file, "r") : unable to open connection

This is great. Thank you for your help, but let me make sure I fully understand. Here is the looping file I use to subset the data frame, create a tex file, and Sweave it. This results in N number of tex files where N is equal to the number of rows in the data frame. list <- unique(wide$stuid) master = "master.tex" for (i in list){ tmp1 <- subset(wide, stuid==i) tmp2