similar to: Operating matrix positions

I have the following code: list1 <- list() for (i in list.files(pattern="filename1")){ x <- read.table(i) list1[[i]] <- x } list2 <- list() for (i in list.files(pattern="filename2*")){ x <- read.table(i) list2[[i]] <- x } anslist <- vector('list', length(list1)) for(i in 1:length(list1)) if (list1[[i]] & list2[[i]] >1)

I want to fit a fairly long main title for a plot, supposedly by changing row after a while. As for now it starts way outside the picture margin at the left and continues way out right passed the right margins. >plot(A,main="This is my really long title and it's so long that I can see just about half of it.") Any suggestions? Shouldn't be that hard. -- View this message in

Hi there, I have a binary matrix (dim 100x100) filled with values 0 and 1. I need select a record "n" positions of that matrix when values are 1. How can I do that? Thanks for all, Miltinho Brazil --------------------------------- [[alternative HTML version deleted]]

I have this code: list1 <- list() for (i in list.files(pattern=".*c02.*AFDH0.*")){ x <- read.table(i,skip=20,fill=TRUE) list1[[i]] <- x } Somehow I would like the read.table function to read only values in each file that are over a certain limit, say >1. Is this the easiest way or is it better to tamper with 'list1' when it's done? -- View this message in

Hi, I have a vector of start positions, and another vector of stop positions, eg start<-c(1,20,50) stop<-c(7,25,53) Is there a quick way to create a sequence from these vectors? new<-c(1,2,3,4,5,6,7,20,21,22,23,24,25,50,51,52,53) the way Im doing it at the moment is pos<-seq(start[1],stop[1]) for (i in 2:length(start)){ new<-seq(start[i],stop[i]) pos<-c(pos,new) }

Hi, I have 2 questions on list object:   1. Suppose I have a matrix like: dat <- matrix(1:9,3)   Now I want to replicate this entire matrix 3 times and put entire result in a list object. Means, if "res" is the resulting list then I should have:   res[[1]]=dat, res[[2]]=dat, res[[3]]=dat   How can I do that in the easilest manner?   2. Suppose I have 2 list objects: list1 <- list2

Dear R-users, I am looking for a way to assign to slices of arrays where dimensionality of the array is not a-priory known. Specifically, I would like to be able to generalize the following example of dimensionality 2 to an arbitrary diminsionality: In this example we create an array x, a smaller array y and then assign y to a slice of x. > dimnmx <- list(c('a','b'),

Hi everybody, This has been causing me some trouble: I want to combine several lists of pairs into a single?vector but keep the pairs together. The lists are of the form: (1)?x1 x2 x3... N? (2) y1 y2 y3..? N I would like to keep it this way, simply appending one list to another, e.g. (1) x1i x2i... x1j x2j... N (2) etc. A?method like c(...) does not achieve this. It creates a single list,

Hi all, I have some rough code to sample consecutive integers with length according to a vector of lengths #sample space (representing positions) pos<-c(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20) #sample lengths lengths<-c(2,3,2) From these two vectors I need a vector of sampled positions. the sampling is without replacement, making things tough as the sampled integers need

I am trying to find the function where I can search for a pattern in a text string (I thought I could use grep for this but no :(). > x [1] "abcdefghijkl" I want to find the positions (i.e. equivalent of nchar) for "cd" and in case there are multiple hits .. then the results as a array Thank you.

Hello, I have a question regarding the following output: > database <- read.delim(file=path.input.file, header=TRUE, dec=".", sep="\t", na.strings = "#NV") > str(database) 'data.frame': 314 obs. of 13 variables: $ S : Factor w/ 314 levels "307073","400212",..: 147 72 299 137 162 62 189 236 134 307 ... $ A : Factor

Hi all, I was wondering whether it is possible to use the lapply() function to alter the value of the input, something in the spirit of : a1<-runif(100) a2<-function(i){ a1[i]<-a1[i-1]*a1[i];a1[i] } a3<-lapply(2:100,a2) Something akin to a for() loop, but using the lapply() infrastructure. I haven't been able to get rapply() to do this. The reason is that the "real"

Hi there, I run two regressions: y = a1 + b1 * x + e1 y = a2 + b2 * z + e2 I want to test against the null hypothesis: b1 = b2. How do I design the test? I think I can add two equations together and divide both sides by 2: y = 0.5*(a1+a2) + 0.5*b1 * x + 0.5*b2 * z + e3, where e3 = 0.5*(e1 + e2). or just y = a3 + 0.5*b1 * x + 0.5*b2 * z + e3 If I run this new regression, I can test against

For example, based on a certain condition, I may want to exit my code early: # Are there the same number of assets in "prices" and "positions"? if (nAssetPositions != nAssetPrices) { cat("Different number of assets! \n\n") <exit function> } I have searched, but not

Hi, When qqnorm on a vector of length 10M+ I get a huge pdf file which cannot be loaded by acroread or evince. Any suggestions? (apart from sampling the data). Thanks. -- Sam Steingold (http://sds.podval.org/) on Ubuntu 11.10 (oneiric) X 11.0.11004000 http://mideasttruth.com http://honestreporting.com http://camera.org http://openvotingconsortium.org http://pmw.org.il

> On Jun 6, 2019, at 2:04 PM, Richard O'Keefe <raoknz at gmail.com> wrote: > > How can expanding tildes anywhere but the beginning of a file name NOT be > considered a bug? > > I think that that IS what libreadline is doing if one allows a whitespace separated list of file names. As reported in R-help, https://www.mail-archive.com/r-help at

Hi Everyone, quick question before the end of the year. I have soem indices to select data from a bigger sample. I want to select n days before each index and n days after the index. Any clever way to do it. A for loop would do but I wanted to know if there is a moreR-friendly way to approach this Example # InitialIndices i2 = (90, 190, 290) # Indices I want to end up with i3 = c(85, 86, 87,

I have a problem with expressions. I am trying to create a title where the parameter of interest is displayed as a Greek character. Which parameter is being considered is stored in a character variable. As an example, if I have param <- "alpha" and then do plot(0, 0, main = bquote(Parameter==.(param))) then in the title I get "Parameter = alpha", whereas I want the

Dear R-users, Say that I have a sequence of zeroes and ones: x <- c(1,1,1,0,0,0,0,1,1,1,0,0,0,0,1,1,1,0,0,0,0) The sequences of ones represent segments and I want to report the starting and endpoints of these segments. For example, in 'x', the first segment starts at location 1 and ends at 3, and the second segment starts at location 8 and ends at location 10. Is there an efficient

Hi, As I can see via path.expand a filename which contains a tilde anywhere gets automatically crippled. +> path.expand("a ~ b") [1] "a /home/user b" +> path.expand("a ~ b ~") [1] "a /home/user b /home/user" I want to open a file regardless whether its name contains any character unless 0. The unix filesystem allow the creation of such files, it