similar to: list matching

Hi all, I want to write a wrapper for an analysis of variance and I face a curious problem. Here are two different wrappers: fun.1 <- function(formula) { summary(aov(formula)) } fun.2 <- function(formula) { oneway.test(formula) } values <- c(15, 8, 17, 7, 26, 12, 8, 11, 16, 9, 16, 24, 20, 19, 9, 17, 11, 8, 15, 6, 14) group <- rep(1:3, each=7) # While the first

Dear all, I noticed that a data.frame has four attributes: - names - row.names - class - variable.labels While one can use the first three (i.e. names(foo) or class(foo)), the fourth one can only be used via: attributes(foo)$variable.labels (which is kind of a tedious thing to type) Is it or would be possible to simply use: variable.labels(foo) like the first three attributes? I tried: varlab

Dear list, This should be a simple one, I just cannot see it. I need to generate a sequence of the form: 4 5 6 13 14 15 22 23 24 That is: starting with 4, make a 3 numbers sequence, jump 6, then another 3 and so on. I can create a whole vector with: myvec <- rep(rep(c(F, T, F), rep(3, 3)), 3) Then see which are TRUE: which(myvec) [1] 4 5 6 13 14 15 22 23 24 I'd like to avoid

Dear list, I have two functions created in the same environment, fun1 and fun2. fun2 is called by fun1, but fun2 should use an object which is created in fun1 fun1 <- function(x) { ifelse(somecondition, bb <- "o", bb <- "*") ## mymatrix is created, then myresult <- apply(mymatrix, 1, fun2) } fun2 <- function(idx) { if (bb == "o) { #

Hi again, I was contemplating the solution using base 3: set.seed(3) mat2 <- matrix(sample(0:2, 15, replace=T), 5, 3) Extracting the line numbers is simple: bases <- c(3, 3, 3)^(2:0) # or just 3^(2:0) colSums(apply(mat2, 1, function(x) x*bases)) + 1 [1] 7 23 25 8 1 The problem is sometimes the columns have different number of levels, as in: mat1 <- expand.grid(0:2, 0:2,

Dear all, I'd like to produce a simple pie chart for a customer (I know it's bad but they insist), and I have some difficulties setting the initial angle. For example: pie(c(60, 40), init.angle=14) and pie(c(80, 20), init.angle=338) both present the slices in the same direction, where: pie(c(60, 40)) pie(c(80, 20)) present the slices in different directions. I read everything I

Dear all, This is probably a stupid question for which I have a solution, which unfortunately is not as straighforward as I'd like. I wonder if there's a simple way to apply a weighting variable for the cases of a dataframe (well I'm sure there is, I just cannot find it). My toy example: > my.data <- data.frame(var1=c("c", "e", "a",

Dear all, When creating new functions in a package, there is a "See also" component in the Rd file. Usually one uses \link{otherfun}, if the other function is from the same package, or \link[otherpackage]{otherfun} otherwise. The trouble is that I install new packages not in the default R library folder, but into some other subfolder in my home, so the link searches for

Dear All, I assume this is an R-devel issue, apologies if I missed something obvious. I have a dataframe where the row names are country codes, based on ISO 3166, something like this: ------------ "v1" "v2" "UK" 1 2 "NA" 2 3 ------------ It happens that "NA" is the country code for "Namibia", and that creates problems on

Hello, I'm using R 2.0.0 with the latest Rcmdr package installed from CRAN, on Windows XP Professional. When trying to copy some commands or results, either from the upper or lower text window, this causes Rcmdr to crash: "R for Windows GUI front-end has encountered a problem and needs to close" Did anyone have the same problem? I don't think it's my system, as it

Hello, I'm using R 2.0.0 with the latest Rcmdr package installed from CRAN, on Windows XP Professional. When trying to copy some commands or results, either from the upper or lower text window, this causes Rcmdr to crash: "R for Windows GUI front-end has encountered a problem and needs to close" Did anyone have the same problem? I don't think it's my system, as it

Dear R-list, Could anybody tell me where to find information about changing the measurement unit from inch to centimeters? I read the help from X11, I read R-intro and I did some searhing in the R archives, but I couldn't find the answer. For example, I would like to produce a plot of a certain width and height: X11(width=10, height=5) and I would like these to be centimeters, rather

Dear all, There is something I'm missing in order to understand the following behavior: > aa <- c("test", "name") > ifelse(any(nchar(aa) < 3), aa[-which(nchar(aa) < 3)], aa) [1] "test" > any(nchar(aa) < 3) [1] FALSE Shouldn't the ifelse function return the whole aa vector? Using if and else separately, I get the correct result... >

Dear all, Some very wise data entry person gave me about an hour of a headache, trying to find out why a 2000x500 dataframe won't be read into R. After much trial and error, I pinpointed the problem to an accidentally inserted double quote into a string variable (some comments from an open question). This can be replicated by: aa <- data.frame(id=1:2, var1=c("some \"

Dear r-devel, I am trying to automatically check if two successive versions of a package have the same results (i.e. code not broken), by parsing the example sections for each function against a previously tested version. While trying to replicate the code from example(), I am facing an error related with te "index.search" function (line 7 in the example() code). This is the code I am

Dear Mao Jianfeng, "r-help-owner" is not the place for help, but: r-help at r-project.org (CC-ed here) In any case, strsplit() does the job, i.e.: > unlist(strsplit("BCPy01-01", "-")) [1] "BCPy01" "01" You can work with the whole variable, like: splitpop <- strsplit(df1$popcode, "-") then access the first part with >

Dear list, I have a vector of numbers, let's say: myvec <- c(2, 8, 24, 26, 51, 57, 58, 78, 219) My task is to reduce this vector to non-reducible numbers; small numbers can cross-out some of the larger ones, based on a function let's say called reduce() If I apply the function to the first element 2, my vector gets shorted to: > (myvec <- reduce(myvec[1])) [1] 2 24 51

Hello, Is there a way to extract multiple columns from a dataframe using their names instead of their numbers? Currently I use: data2 <- data1[, c(1,3,9)] And I am looking for something like data2 <- data1[, c("XX","YY","ZZ")] I use the same dataframe for many purposes, and I run codes that change the order of the columns every time. Many thanks, Adrian

I have a set data={A,B,C,D,E,F,G} I want to choose 2 letter from 8 letters, i.e. generate the combination set for choose 2 letters from 8 letters. I want to get the liking: combination set={AB,AC,AD,....} Does anyone konw how to do in R. thanks, Aimin

Dear list, I have a problem with a toy example: mtrx <- matrix(c(1,1,0,1,1,1,0,1,1,0,0,1), nrow=3) rownames(ma) <- letters[1:3] I would like to determine which is the minimum combination of rows that "covers" all columns with at least a 1. None of the rows covers all columns; all three rows clearly covers all columns, but there are simpler combinations (1st and the 3rd, or 2nd