similar to: "Save to File..." option on File menu

Hi. I am aware of three different R packages for linear programming: glpk, linprog, lpSolve. From what I can tell, if there are N variables and M constraints, all these solvers require the full NxM constraint matrix. Some linear solvers I know of (not in R) have a sparse matrix input format. Are there any linear solvers in R that have a sparse matrix input format? (including the

Hi All, I searched around to find the number of R packages currently available, but didn't find anything, so I choose all repositories & told it to install. The list contained about 2,856 (correcting roughly for those installed). But the list includes repetitions such as 19 names that begin with "bvbovine". Selecting only CRAN and CRAN(extras) I get 1,344. Is there an easier

Hi. I have a procedure that reads a directory, loops through a set of particular .RData files, loading each one, and feeding its object(s) into a function, as follows: cvListFiles<-list.files(fnDir); for(i in grep(paste("^",pfnStub,".*\\.RData$",sep=""),cvListFiles)){ load(paste(fnDir,cvListFiles[i],sep="/")); myFunction(rliObject); rm(rliObject); };

Greetings, I'm learning R and I'm stuck on a basic concept: how to specify a logical condition once and then perform multiple transformations under that condition. The program below is simplified to demonstrate the goal. Its results are exactly what I want, but I would like to check the logical state of gender only once and create both (or any number of) scores at once.

Dear R-Helpers, I suspect I'm about to ask a FAQ, but I haven't been able to find an answer in the FAQ, AItR or an R Site Search. When I look at the methods of summary (below) it says, "Non-visible functions are asterisked". I looked at the help file for summary.princomp, which did not comment on it being non-visible. I ran its help file example, which printed visible output. I

Hi. Suppose I have a vector that I partition into disjoint, contiguous subvectors. For example, let v = c(1,4,2,6,7,5), partition it into three subvectors, v1 = v[1:3], v2 = v[4], v3 = v[5:6]. I want to find the maximum element of each subvector. In this example, max(v1) is 4, max(v2) is 6, max(v3) is 7. If I knew that the successive subvector maxima would never decrease, as in the example,

Hi. I am using R 2.3.1 on WIndows XP, and I am having trouble with the rank function in the presence of numerical NA data. I want the NA's all to get the same rank, but they don't. Here is an example from my session: >ct_align_rets_f2$liq[6851:6859] [1] 115396 NA 362595 NA 242986 340805 NA 692905 251533

Hi. I have the following code in a loop. It splits a vector into subvectors of equal size. But if the size of the original vector is not an exact multiple of the desired subvector size, then the first few subvectors have one more element than the last few. I know that the cut function could be used to determine where to break up the vector, but it doesn't seem to provide control over

Hi All, We have all had to face skeptical colleagues asking if software made by volunteers could match the quality and accuracy of commercially written software. Thanks to the prompting of a recent R-help thread, I read, "R: Regulatory Compliance and Validation Issues, A Guidance Document for the Use of R in Regulated Clinical Trial Environments (http://www.r-project.org/doc/R-FDA.pdf).

Hi All, I'm trying to understand the difference between do.call and lapply for applying a function to a list. Below is one of the variations of programs (by Marc Schwartz) discussed here recently to select the first and last n observations per group. I've looked in several books, the R FAQ and searched the archives, but I can't find enough to figure out why lapply doesn't do what

Hi All, I'm using the Hmisc summarize function and used list instead of llist to provide the by variables. It generated an error message. Is this a bug, or do I misunderstand how Hmisc works with lists? The program below demonstrates the error message. Thanks, Bob x<-1:8 group <- c(1,1,1,1,2,2,2,2) gender<- c(1,2,1,2,1,2,1,2) mydata<-data.frame(x,group,gender)

Hi Folks, SAS Institute is adding official support for R: http://support.sas.com/rnd/app/studio/Rinterface2.html Cheers, Bob ========================================================= Bob Muenchen (pronounced Min'-chen), Manager, Research Computing Support U of TN Office of Information Technology Stokely Management Center, Suite 200 916 Volunteer Blvd., Knoxville, TN

Dear HelpeRs, I'm confused about the role of quotes around package names on the library and detach functions. Books on R use both approaches: library(Hmisc) describe(mydata) detach(package:Hmisc) and library("Hmisc") describe(mydata) detach("package:Hmisc") The help file for detach says "quoted or unquoted" and the help file for library says about the

Hi. I recently tried the following in R 2.5.1 on Windows XP: >ev2<-c(0.8,-0.6) >ev1<-c(0.6,0.8) >ev1%*%ev2 [,1] [1,] -2.664427e-17 >sum(ev1*ev2) [1] 0 > (I got the same result with R 2.4.1 on a different Windows XP machine.) I expect this issue is very familiar and probably has been discussed in this forum before. Can someone please point me to some

Hi. I have a matrix stored in a large, tab-delimited flat file. The first row contains column names. Because the matrix is symmetric, the file has lower triangular format, so the second row contains one number, the third row two numbers, etc. In general, row k+1 contains k numbers; the matrix has 3000 rows, so the file has 3001 rows. The file has variable length records, so each row ends

Hi All, I'm learning JGR 1.4-15 with R 2.4.1 in Windows XP (all patches applied). JGR looks great but I'm having trouble getting the data editor to save my results. I don't see anything in R-help about it. Here are the steps I followed: 1. I chose "Tools>Object Browser" & double-clicked on a data frame, "mydata". 2. A spreadsheet editor popped up and

Hi All, If I need to stack two data frames, I can use rbind, but it requires that all variables exist in both sets. I can make that happen, but other stat packages would figure out where the differences were, add the missing variables to each, set their values to missing and stack them. Is there a more automatic way to do that in R? Below is an example program. Thanks, Bob # Top data frame has

Hi. Maybe this is a stupid question. If so, I apologize, but here goes. Suppose I have a function f1(x,...) that calls a function f2(y1,y2,...,yn) in the following way: if x satisfies a certain condition, then I want to call f2(x,y2,...,yn); otherwise I want to use the default value of y1, if there is one. I could do something like the following: v <- ifelse ( is.null(x), f2( , y2,...,

I am using spss.get to import an SPSS database "Data.sav", created with SPSS 14 : df1 <- spss.get("C:/temp/Data.sav" , lowernames=TRUE, datevars = c("dateinte")) I am getting this warning. I get the same warning with read.spss. Warning message: C:/temp/Data.sav: Unrecognized record type 7, subtype 16 encountered in system file This is a stupid

Hi Do you know some articles, papers, something than tell about comparision between R and others softwares statisticals. Thank You Ricardo -- View this message in context: http://www.nabble.com/Articles-about-comparision-between-R-and-others-softwares-tp19338210p19338210.html Sent from the R help mailing list archive at Nabble.com.