similar to: uneven list to matrix

Hello All, I've been using R for two years now and I am happy to say this is the first time I could not find the answer to my problem in the R-help archives. Here is the pending problem: I want to be able to insert delimiters, say commas, into a string of characters at uneven intervals such that: foo<-c("haveaniceday")#my string of character bar<-c(4,1,4,3) # my vector of

Hello All, I have had considerable bad luck with attempting the following with for loops. Here is the problem: # Suppose we have a data.frame with the following data, which can be considered a type of edgelist (for those with networks backgrounds): # # V1 V2 # 1 A # 1 A # 1 B # 2 A # 3 C # 3 A # 3 C # 3 B # # I want the output of the function to produce a matrix, such that #each factor of

Hello R-Users, I would like to use an iterative loop to collect user input from within a function. I'm sure that this would be some combination of "for","break", and "next" but have not been able to get the syntax down. I would like to print some text to the screen at each step in the loop, ask the user for input which is saved in an object, and then advance the

Hi, Here i have a matrix like this, OLDMatrix <- X1 X2 X3 ----- ------ ------ 22 24 23 25 27 27 10 13 15 the thing is, im running two function(SUM,COUNT) to get output in another matrix called NEWMatrix NEWMatrix <- c("SUM",colSums(OLDMatrix )) NEWMatrix <- c("COUNT",colSums(!is.na(OLDMatrix

I have DHCP and TFTP on a Solaris machine, pxelinux.0 loads, but it can't load the configuration file. The tftp server on Solaris tries to send the file, but data transfers do not receive ACKs. Previous posts to this list have indicated that the suspect was the PXE BIOS (ref "PXELinux can't load the config file?" dated March 20, 2003). Does that still appear to be the case

This will start off sounding very easy, but I think it will be very complicated. Let's say that I have a matrix, which shows the number of apples that each person in a group has. OriginalMatrix<-matrix(c(2,3,5,4,6),nrow=5,ncol=1,byrow=T,dimnames=list(c("Bob","Frank","Joe","Jim","David"),c("Apples"))) Apples Bob 2

I have been trying to copy the row names of one matrix to another matrix but having difficulty. The original matrix contains a row name which I would like to replicate in the new matrix. I use the following approach? The two matrices have identical dimensions. rN <- row.names(origMatrix) row.names(newMatrix) <- rN However the new matrix does not take on the labels. I have also tried,

Dear R-users I need to convert a matrix with three columns in a new array with multiple columns. For example, oldmatrix 1 4 5 1 54 52 1 9 43 2 32 5 2 54 6 2 76 6 3 54 54 3 543 7 3 54 6 newmatrix 5 5 54 52 6 7 43 6 6 if the first column have a new value then add a column to the new matrix and the new[i,j] <- old[,3][i] I write this code, but my initial matrix is very

Dear all, i am stuck with a syntax problem. i have a matrix which has about 500 rows and 6 columns. now i want to kick some data out. i want create a new matrix which is basically the old one except for all entries which have a 4 in the 5 column AND a 1 in the 6th column. i tried the following but couldn´t get a new matrix, just some wierd errors:

Hi all, I need to replace missing values in a matrix by 10 % of the lowest available value in the matrix. I've got a function I've used earlier to replace negative values by the lowest value, in a data frame, but I'm not sure how to modify it... nonNeg = as.data.frame(apply(orig.df, 2, function(col) # Change negative values to a small value, close to zero { min.val =

x <- c( "a1", "a10", "a2" ) y <- c( "b10", "b2", "a12", "ca1" ) DF <- expand.grid( x = x, y = y ) # randomize set.seed( 42 ) DF <- DF[ sample( nrow( DF ) ), ] # missing from gtools mixedrank <- function( x ) { seq.int( length( x ) )[ gtools::mixedorder(x) ] } o <- do.call( order, lapply( DF, mixedrank ) )

Dear developement team, I want to share a massive storage casted with Ceph by samba with windows workstations. All works well. My problem so is that in windows the ceph storage size statistics are wrong. Instead of seeing a 44TB hard drive I see a 176GB hard drive. Under linux that issue doesn't show. The size are properly reported. I investigated around and it seems that the problem

Hello All, I have been trying to do bonpow for a while now.Bonpow works for few graphs and for few others it goes out of memory. I did see reply to one of the posting Alph Centrality Crashed in Igraph memory error. The solution in the posting was to use sparse matrix. This is the link of the message. http://lists.gnu.org/archive/html/igraph-help/2008-04/msg00071.html I was able to obtain

Full_Name: Morten Welinder Version: 2 OS: Solaris/space/gcc2.95.2 Submission from: (NULL) (65.213.85.217) I changed src/nmath/standalone/test.c to read: --------------------------------------------------------------------------------- #define MATHLIB_STANDALONE 1 #include <Rmath.h> #include <stdio.h> int main() { double x; for (x = 99990; x <= 100009; x++) printf

Hi! I fairly new to R, have only done pretty basic things so far, so this may be a very basic question..... But I did search the forums and didn't see a solution.... I'm trying to get going with kripp.alpha(). I'm loading data from a file, like this: > library(irr) Loading required package: lpSolve > x <- read.table("foo", comment.char="#", header=TRUE,

Hi together I'm pretty new to R, so excuse me if it is a basic question. I have a big dataset (extract of it found in the attachment) of returns from firms. I'd like to compute the Pearson correlation of each firm with the "Market" and the corresponding p-Value. So I thought of making a list of 'cor.test's and then extract the needed values with a for loop. What I did so

Hello, by checking the precision of a convolution algorithm, we found the following "inexactness": We work with R Version 1.8.1 (2003-11-21) on Windows systems (NT, 2000, XP). Try the code: ## Kolmogorov distance between two methods to ## determine P(Poisson(lambda)<=x) Kolm.dist <- function(lam, eps){ x <- seq(0,qpois(1-eps, lambda=lam), by=1) max(abs(ppois(x,

Hi when I fit a glm by glm.fit(x,y,family = binomial()) and then try to use the object for prediction of newdata by: predict.glm(object, newdata) I get the error: Error in terms.default(object) : no terms component I know I can use glm() and a formula, but for my case I prefer glm.fit(x,y)... thanks for a hint christoph $platform [1] "i686-pc-linux-gnu" $arch [1]

I was wondering if someone can tell me the best way to search through a matrix and choose certain rows (based on certain conditions) to put into a separate matrix. What I have tried so far is very slow for a large dataset I'm working with. e.g., I have this piece of code to create a new matrix (newmat) based on my filtering conditions. Do I need to do this kind of thing where I keep

R versions 2.1.0 to present. Examples shown were computed under Windows R-devel, current SVN, but ix86 Linux shows similar behaviour (sometimes NaN or -Inf rather than Inf, depending on the compiler and optimization level used). The replacement pgamma algorithm used from R 2.1.0 has an inadequate design and no supporting documentation whatsoever. There is no reference given to support the