similar to: Conversion of zoo object (with POSIXct-attributes) to dataframe

Hi there I have precipitation data from 2004 to 2006 in varying resolutions (10 to 20min intervals) with time in seconds from beginnig of the year (summation) and a second variable as year. I applied follwing code to convert the time into a date: times<-strptime("2004-01-01", "%Y-%m-%d", tz="GMT") + precipitation$time1 everytihng went well, except that every

hej i'm plotting time-series and label the x-axis as follows: r <- as.POSIXct(round(range(p1$time), "month")) to define the time range for labeling the xaxis plot(p1$time,p1$ p1, type="l", xaxt="n") plots p1 against time axis.POSIXct(1, at=seq(r[1], r[2], by="month"), format="%m") labels the axis in mothly steps. what I want do do

Hi there Does anyone know, why this is not working?: par(mfrow = c(5, 5)) for (i in 1:10){ plot(x=time, y=Var.i) } (x-variable is time y-variable is Var out of matrix with columns Var.1 Var.2 Var.3 etc...) even for (i in 1:10){ plot(x=time, y=paste("Var", i, sep=".") } does not work Thanks marc

Hello, Can anyone explain the following behaviour? To me it seems a bug, but maybe it is intentional. It seems that a diff on a zooreg class that is not _strictly_ regular only considers those entries that are 'deltat' apart. In the following, diff on the zooreg class only returns values where the index was one second apart. The example replicates by dev code, but I've also tested

Hi, I'm trying to plot the forecasts I generated using the Plot.Fore function of the BootPR package. But I got an error from zoo: My data: Time Series: Start = 1 End = 18 Frequency = 1 [1] 38731 38628 39117 92809 71984 31226 58613 72360 107956 92066 [11] 95208 99098 95848 120383 110717 105680 98469 101916 Script: y1<-ts(y1);

I have date data as a numeric and hourly data in 0 to 2300 hours in a dataframe. d <- rep(20110101,24) h <- seq(from = 0, to = 2300, by = 100) df <- data.frame(LST_DATE = d, LST_TIME = h, data = rnorm(24, 0, 1)) S <- chron(dates. = as.character(df$LST_DATE), times. = paste(as.character(df$LST_TIME/100), ":0:0", sep = ""), format =

Dear all, please consider my following workbook: library(zoo) lis1 <- vector('list', length = 2) lis2 <- vector('list', length = 2) lis1[[1]] <- zooreg(rnorm(20), start = as.Date("2010-01-01"), frequency = 1) lis1[[2]] <- zooreg(rnorm(20), start = as.yearmon("2010-01-01"), frequency = 12) lis2[[1]] <- matrix(1:40, 20) lis2[[2]] <-

I create a zooreg object that runs from Jan-1-2002 0:00 to Jun-1-2005 0:00... regts.start = ISOdatetime(2002, 1, 1, hour=0, min=0, sec=0, tz="") regts.end = ISOdatetime(2005, 6, 1, hour=0, min=0, sec=0, tz="") regts.zoo <- zooreg( NA, regts.start, regts.end, deltat=3600 ) Upon inspection: > regts.zoo[1:3] 2002-01-01 00:00:00 2002-01-01 01:00:00 2002-01-01 02:00:00

R-listers, I am using xts with a yearmon index, but am getting some inconsistent results with the date index when i drop observations (for example by using na.omit). The issue is illustrated in the example below. If I start with a monthly zooreg series starting in 2009, yearmon converts this to "Dec-2008". Not such a worry for my example, but strange. Having converted to xts, i drop

Dear R community, I have the following two zoo objects: MONTHLY CPI > plot(z) > par("usr") [1] 1977.76333 2011.15333 70.39856 227.03744 > z=zooreg(cpius$Value,as.yearmon("1979-11"),frequency=12) > str(z) ?zooreg? series from Nov 1979 to Oct 2010 Data: num [1:372] 76.2 77 77.8 78.5 79.5 80.3 81.1 82 82 82.6 ... Index: Class 'yearmon' num [1:372]

Hi,   I observed that if I use window() function available with the 'zoo' package to extract a portion of my times series and if that time series data is stored in some 'zoo' object with only 1 column, then the resulting zoo object is becoming vector.   Here is my observation:   > library(zoo) > Dat <- matrix(1:3, nc = 1) > Dat      [,1] [1,]    1 [2,]    2 [3,]    3

Dear R People: I'm trying to convert a daily zoo object to a weekly zoo object: xdate <- seq(as.Date("2002-01-01"),as.Date("2010-07-10"),by="day") library(zoo) length(xdate) xt <- zoo(rnorm(3113),order=xdate) xdat2 <- seq(index(xt)[1],index(xt)[3113],by="week") xt.w <- aggregate(xt,by=xdat2,mean) Error: length(time(x)) ==

Hi, I'm struggling to understand the documentation. ?lag.zoo x - a "zoo" object. k, lag - the number of lags (in units of observations). Note the sign of k behaves as in lag. differences - an integer indicating the order of the difference. What does the above line actually mean? I've tried a few settings on sample data but can't figure out what it is doing. x <-

Dear R People: I have the following data frame: > str(dog.df) 'data.frame': 7 obs. of 2 variables: $ V1: Factor w/ 3 levels "1/1/2000","1/2/2000",..: 1 1 1 2 2 3 3 $ V2: Factor w/ 3 levels "cat","dog","tree": 2 1 3 1 3 2 3 > dog.df V1 V2 1 1/1/2000 dog 2 1/1/2000 cat 3 1/1/2000 tree 4 1/2/2000 cat 5 1/2/2000 tree 6

Hi Guys, I'm using zoo package now. I found lag is not doing what I assumed. > x <- zoo(11:21) > z <- zoo(1:10, yearqtr(seq(1959.25, 1961.5, by = 0.25)), frequency = 4) > x 1 2 3 4 5 6 7 8 9 10 11 11 12 13 14 15 16 17 18 19 20 21 > lag(x) 1 2 3 4 5 6 7 8 9 10 12 13 14 15 16 17 18 19 20 21 > z 1959 Q2 1959 Q3 1959 Q4 1960 Q1 1960 Q2 1960 Q3 1960 Q4

Hi, I'd like to make a time series at an annual frequency. > a<-xts(x=c(2,4,5), order.by=c("1991","1992","1993")) Error in xts(x = c(2, 4, 5), order.by = c("1991", "1992", "1993")) : order.by requires an appropriate time-based object > a<-xts(x=c(2,4,5), order.by=1991:1993) Error in xts(x = c(2, 4, 5), order.by =

i have no idea how to definie for a parallel zone the host file if the second zone (net) should be the composition of the first zone (dmz). i tried all the following combinations in the interface and host files: interface: - eth0 - (variante 1) - eth0 192.168.0.255,255,255,255,255 (variante 2) - eth0 192.168.0.255,!192.168.0.255 (variante 3)

Hi, Can you tell me what is the meaning for "tail, 1" in "aggregate"? I also want to get some similar graph, but the data is not time series data. Suppose here is my data one, I want a graph with x-axis is just the index(1:9). The graph plot all the variable A, B,C,D. So there should be 4 lines for each graph. For the A line, at each time point, the letter A should be on

I'm stuck, but am sure it can be done I just don't understand how. I have data in an irregular timeseries. I want to be able to use stl to visualise the data (see seasonal parts etc), so I need to change to regular series of class ts (I think). I am using 2 zoo objects one is regular and the other is my irregular data. I am then merging to create the object I want but when I try to change

Hi List, I have weekly sales observations for several products drawn via ODBC. Source data is available at https://www.dropbox.com/s/78vxae5ic8tnutf/asr.csv. This is retail sales data, so will contain seasonality and trend information. I expect to see 52 or 53 observations per year, each observation occuring on the same day of the week (Saturday). Ultimately I'm looking to feed these series