similar to: matching elements from two vectors

Hi, I am writing a for loop that creates one object, say 'outn' on every round of the loop. I would like the name of each object to include the index of the loop as in, for example: out1, out2, out3, ... And I would like the naming of the object to take place automatically as the loop moves through? Similarly, I would like to be able to call different objects (in1, in2, in3,

Hi, If I have a vector: junk <- c(2,0,0,3,0) and want to access, say, all the elements that are greater than zero. I just do: junk[which(junk>0)] Now, If I have a list: jlist <- list(NULL,c(1,0),NULL,c(1,2,3), NULL) and want to access all the elements that have length greater than zero, I know how to find the elements with: which(sapply(jlist,length)>0) But how do I get a

Hi, Anyone knows what would be a short way of extracting a month from a date in numeric or integer format? months("1979-12-20") returns "December" in character format. How could I get 12 in numeric or integer format? Thanks! G. [[alternative HTML version deleted]]

Hi, I have: a <- matrix(c(0,1,0,1),nrow=2) b <- matrix(c(1,1,1,0,0,0),nrow=3) c <- 1 d <- c(1,0,1) And I would like to join them in an object 'thing' so that I can access a, b, c, or d through an index in a for loop. For example: thing[4] would return [1] 1 0 1 Note however, that I have many of these 'thing' components. So many that a command like thing

Hi, If I have a data frame A with the following format: Day1 Day2 Day3 Day4 1 1979-11-02 1979-11-03 1979-11-04 <NA> 2 1979-12-06 <NA> <NA> <NA> 3 1979-12-13 1979-12-14 1979-12-15 1979-12-16 4 1979-12-20 <NA> <NA> <NA> And a date "1979-12-14", for

Hi, I have a vector 'data' of 58 probability values (bounded between 0 and 1) and want to draw a probability density function of these values. For this, I used the commands: data <- runif(58) a <- density(data, from=0, to=1) plot(a, type="l",lwd=3) But then, when I try to approximate the area under the plotted curve with the command: area <- sum(a$y)*(a$x[1]-a$y[2])

Hi, 'true_name' is a list of numerical, matrix, and text items I do pass_name <- "true_name" and pass the name of the list to a function so that the character class variable 'passed_name' contains the name of the list called 'true_name' Inside the function, how can I get a specified element from the list? For example, if I want to get

Hi, I have a matrix BEE and want to find the row and column numbers of the minimum value in that matrix. The command which(BEE==min(BEE)) returns only one value which, I take, is the position of the minimum in a vector with as many elements as the matrix. Is there a quick and simple way of getting row and column numbers? Thanks, Gonçalo [[alternative HTML version deleted]]

Hi, I have a cloud of randomly distributed points in 2-dimensional space and want to set up a grid, with a given grid-cell size, that minimizes the distance between my points and the grid nodes. Does anyone know of an R function or toolbox that somehow addresses this problem? This is a problem of optimizing the location of the grid, not a problem of deciding what should be the grid-cell size,

Hi, I have a vector of strings (class character) with 6 elements (length 6). I call it 'names'. "Graham Chapman" "John Cleese" "Terry Gilliam" "Eric Idle" "Terry Jones" "Michael Palin" And I want to turn it into another vector of strings called 'shortnames' with the same length. The new vector should look like:

Hi, I have a data.frame SAMPLES with columns: Site Site# Season Day1 Day2 Day3 Day1, Day2, Day3 are class "Date", the other columns are numeric or factor. I have a date "mydate" that may or may not be listed in my data.frame and I need to find that out. If "mydate" is there, I want to get the number of the data.frame row where it occurs.

Hi, I want a function to write some of its output into a text file with the following format: 'some text' output matrix A 'some more text' output matrix B 'some other text still' output matrix C ... The dimensions of matrices A, B, ... are different and the total number of matrices that I want to place in the text file depends on what I pass to the function. (I

Hi, I am simulating an event that has 15 possible outcomes and I have a vector 'pout' that gives me the probability of each outcome - different outcomes have different probabilities. Does anyone know a simple way of simulating the outcome of my event? If my event had only two possible outcomes (0/1) I would pick a uniform random number between 0 and 1 and use it to choose between the two

Hi! I'm not experienced very experienced with R and i'm looking for a way doing plots like in this example http://www.mathworks.de/matlabcentral/fx_files/23566/2/color_line3.png, which basically it is a 2d plot in which the 3rd dimension (variable) is color coded. I have only seen elsewhere that it is possible to color code dots in a scatter plot and I tried it with success although I

I'm calculating nodes using Random Forest in R but i only get nodes for a fraction of the compounds i want to calculate, the rest is ommited and is not printed in the output file, (i'm working with 3012 compounds). What can i do to have nodes printed for all the compounds. Thanks Gon?alo

Hi Gon?alo Ferraz <gferraz29 at gmail.com> napsal dne 11.09.2007 16:35:57: > Thanks! What is the easiest way of declaring an empty data frame. Is there > anything similar to: > matrix(0,x,y) > In the help files, I am only finding longer commands that ask me to specify > each individual column. You can either do dat<-data.frame(x=rep(NA,10), y=rep(NA,10)) or to

Hello, I use caldera 2.4 , and evrything goes well with samba. Login, shares, homes and neighborhood but the windows stations cannot change their samba password on the Linux serveur. It allways answers that the old password is wrong and it is no. anyway the password was recognise at the login... Their is no relation with passwd sync or passwd chat. Thank you for your help (and your work ! ).

On Wed, Mar 08, 2023 at 08:54:24AM +0100, Leon Benthaus via samba wrote: >Dear all, > >I still have CentOS7 running with the latest Samba Version available >for it (samba-4.10.16-20.el7) >I'm experiencing a really strange issue. When I copy a file larger >than 2GB I? always get a network >drop. It just stops at around 1,74gb. The logs didn't show something >in

Dear all, In my dataset I have 12 columns and 5824 rows. The second column contains information about the height of a claim: it might be zero or positive. I would like to do an analysis on the positive part of this matrix, but I do need the other colums with this. So if there are like 1000 rows where the second column is positive, I would like to extract this 1000x13 matrix into another matrix.

Hi, I'd like to know if it's possible to specify different contrast matrices in lm() for a factor that is nested within another one. This is useful when we have a model where the nested factor has a different number of levels, depending on the main factor. Let me illustrate with an example to make it clearer. Consider the following data set: set.seed(1) y <-