Displaying 20 results from an estimated 1000 matches similar to: "Polynomial fitting"
2004 Aug 09
1
returns the value of a polynomial of degree n evaluated at x.
> Background:
> OS: Linux Mandrake 9.1
> release: R 1.9.0
> editor: Xemacs 21.4
> frontend: ESS 5.1.23
> ---------------------------------
>
> Colleagues
>
Is there a function in R that is similar to polyval in matlab? (y =
polyval(p,x) returns the value of a polynomial of degree n evaluated at x.
The input argument p is a vector of length n+1 whose elements are the
2012 Jan 24
1
problems with rollapply {zoo}
Here is a relatively simple script (with comments as to the logic
interspersed):
# Some of these libraries are probably not needed here, but leaving them in
place harms nothing:
library(tseries)
library(xts)
library(quantmod)
library(fGarch)
library(fTrading)
library(ggplot2)
# Set the working directory, where the data file is located, and read the
raw data
2004 Aug 09
0
returns the value of a polynomial of degree n evaluated a t x.
Try something like:
install.packages("polynom")
library(polynom)
predict(polynomial(rev(p)), x)
HTH,
Andy
> From: McClatchie, Sam (PIRSA-SARDI)
>
> > Background:
> > OS: Linux Mandrake 9.1
> > release: R 1.9.0
> > editor: Xemacs 21.4
> > frontend: ESS 5.1.23
> > ---------------------------------
> >
> > Colleagues
> >
2009 Nov 11
1
Polynomial fitting
Dear R helpers
Suppose I have a following data
y <- c(9.21, 9.51, 9.73, 9.88, 10.12. 10.21)
t <- c(0, 0.25, 1, 3, 6, 12)
I want to find out the polynomial which fits y in terms of t i.e. y = f(t) some function of t.
e.g. y = bo + b1*t + (b2 * t^2) + (b3 * t^3) + ...... and so on.
In Excel I have defined y as independent variable, then defined t, t^2 and t^3 and using
2009 Oct 17
0
More polyfit problems
Hi Everyone,
I'm continuing to run into trouble with polyfit. I'm using the fitting function of the form;
fit <- lm(y ~ poly(x,degree,raw=TRUE))
and I have found that in some cases a polynomial of certain degree can't be fit, the coefficient won't be calculated, because of a singularity. If I use orthogonal polynomials I can fit a polynomial of any degree, but I don't get
2012 Sep 05
2
Improvement of Regression Model
Hello folks,
I am on learning phase of R. I have developed Regression Model over six
predictor variables. while development, i found my all data are not very
linear. So, may because of this the prediction of my model is not exact.
Here is the summary of model :
Call:
lm(formula = y ~ x_1 + x_2 + x_3 + x_4 + x_5 + x_6)
Residuals:
Min 1Q Median 3Q Max
-125.302
2009 Jun 11
2
Optimization Question
Hi All
Apologies if this is not the correct list for this question.
The Rglpk package offers the following example in its documentation
library(Rglpk)
## Simple mixed integer linear program.
## maximize: 3 x_1 + 1 x_2 + 3 x_3
## subject to: -1 x_1 + 2 x_2 + x_3 <= 4
## 4 x_2 - 3 x_3 <= 2
## x_1 - 3 x_2 + 2 x_3 <= 3
## x_1, x_3 are non-negative integers
## x_2 is a non-negative real
2003 Feb 19
4
fitting a curve according to a custom loss function
Dear R-Users,
I need to find a smooth function f() and coefficients a_i that give the best
fit to
y ~ a_0 + a_1*f(x_1) + a_2*f(x_2)
Note that it is the same non-linear transformation f() that is applied to
both x_1 and x_2.
So my first question is how can I do it in R?
A more general question is this: suppose I have a utility function U(a_i,
f()), where f() is say a spline. Is there a general
2008 Aug 04
2
Multivariate Regression with Weights
Hi all,
I'd like to fit a multivariate regression with the variance of the error term porportional to the predictors, like the WLS in the univariate case.
y_1~x_1+x_2
y_2~x_1+x_2
var(y_1)=x_1*sigma_1^2
var(y_2)=x_2*sigma_2^2
cov(y_1,y_2)=sqrt(x_1*x_2)*sigma_12^2
How can I specify this in R? Is there a corresponding function to the univariate specification lm(y~x,weights=x)??
2006 Jun 08
1
panel.abline and xyplot
Dear All,
I am wondering on how to use the abline.xyplot with xyplot such that I will have different vertical lines for each panel. More sepcifically, suppose that the xyplot generates 4 panels defined by the combination of two binary variables: X_1 and X_2. i.e.
xyplot(Y ~ Z | X_1*X_2, data = df)
I want something like:
abline(v = 5) if X_1=0 and X_2 = 0
abline(v =
2009 Dec 04
2
Solve linear program without objective function
Dear R-users,
i try to solve to following linear programm in R
0 * x_1 + 2/3 * x_2 + 1/3 * x_3 + 1/3 * x_4 = 0.3
x_1 + x_2 + x_3 + x_4 = 1
x_1, x_2, x_3, x_4 > 0,
x_1, x_2, x_3, x_4 < 1
as you can see i have no objective function here besides that i use the
following code.
library(lpSolve)
f.obj<-c(1,1,1,1)
f.con<-matrix(c(0,2/3,1/3,1/3,
1,1,1,1,
2007 Mar 29
3
Tail area of sum of Chi-square variables
Dear R experts,
I was wondering if there are any R functions that give the tail area
of a sum of chisquare distributions of the type:
a_1 X_1 + a_2 X_2
where a_1 and a_2 are constants and X_1 and X_2 are independent chi-square variables with different degrees of freedom.
Thanks,
Klaus
--
"Feel free" - 5 GB Mailbox, 50 FreeSMS/Monat ...
2000 Oct 03
5
Where is gam?
I noticed that there is no generalised additive model functions in R
(1.1.1) ... is there a package that implements them?
Thanks
Prasad
*****************************************************************
Mr. Anantha Prasad, Ecologist/GIS Specialist
USDA Forest Service, 359 Main Rd.
Delaware OHIO 43015 USA
Ph: 740-368-0103 Email: aprasad at fs.fed.us
Web:
2004 May 21
2
Help with Plotting Function
Dear List:
I cannot seem to find a way to plot my data correctly. I have a small data frame with 6 total variables (x_1 ... x_6).
I am trying to plot x_1 against x_2 and x_3.
I have tried
plot(x_2, x_1) #obviously works fine
plot(x_3, x_1, add=TRUE) # Does not work. I keep getting error messages.
I would also like to add ablines to this plot.
I have experimented with a number of other
2009 Oct 01
1
Help for 3D Plotting Data on 'Irregular' Grid
Dear All,
Here is what I am trying to achieve: I would like to plot some data in 3D.
Usually, one has a matrix of the kind
y_1(x_1) , y_1(x_2).....y_1(x_i)
y_2(x_1) , y_2(x_2).....y_2(x_i)
...........................................
y_n(x_1) , y_n(x_2)......y_n(x_i)
where e.g. y_2(x_1) is the value of y at time 2 at point x_1 (see that
the grid in x is the same for the y values at all times).
2013 Mar 05
2
Issues when using interaction term with a lagged variable
Hi there!
Today I tried to estimate models using both plm and pgmm functions, with an
interaction between X1 and lag(X2, 1). And I notice two issues.
Let "Y=b_1 * X_1 + b_2 * X_2 + b_3 * X_1 * x_2 + e" be our model.
1) When using plm, I got different results when I coded the interaction
term with I(X1 * lag(X2, 1)) and when I just saved this multiplication X1 *
lag(X2, 1) in a
2012 Sep 20
1
Gummy Variable : Doubt
Hi,
I have a system in which I analyze 2 subjects and 1 variable, so I have
2 models as follow:
y ~ x_1[, 1] + x_2[, 1] + x_1[, 2] + x_2[, 2]
Where
x_1[, i] = cos(2 * pi * t / T_i)
x_2[, i] = sin(2 * pi * t / T_i)
i = 1, 2
Data have two columns: t and y.
As you can see, I have a multiple components model, with rithm and
without trends, and I have a fundamental
2014 Aug 14
2
[LLVMdev] Alias Analysis Semantics
On Thu, Aug 14, 2014 at 6:37 AM, Daniel Berlin <dberlin at dberlin.org> wrote:
> On Wed, Aug 13, 2014 at 8:35 PM, Jeremy Salwen <jeremysalwen at gmail.com> wrote:
>> Hey Daniel,
>>
>> Thanks again for the help. I'm still a bit confused about the interface to
>> the alias analysis. It seems like we are talking about different
>> interfaces.
>
2011 May 28
2
Observation in a confidence ellipse
Hello everyone
I really need some help here. I made a confidence ellipse using the function ellipse from the package ellipse:
ellipse(SD, centre=colMeans(pcsref),t=sqrt((p * (n-1)/(n-p))*qf(0.99, p,n-p))
Now, I want to write a function whom return TRUE or FALSE if a given observation is in the confidence ellipse. But I have no clue how to do it
Can anyone help me?
Best regards
Jessica
2011 May 22
2
Finding solution set of system of linear equations.
I have a simple system of linear equations to solve for X, aX=b:
> a
[,1] [,2] [,3] [,4]
[1,] 1 2 1 1
[2,] 3 0 0 4
[3,] 1 -4 -2 -2
[4,] 0 0 0 0
> b
[,1]
[1,] 0
[2,] 2
[3,] 2
[4,] 0
(This is ex Ch1, 2.2 of Artin, Algebra).
So, 3 eqs in 4 unknowns. One can easily use row-reductions to find a
homogeneous solution(b=0) of:
X_1