similar to: boxplot hinge customization

Displaying 20 results from an estimated 5000 matches similar to: "boxplot hinge customization"

2007 Jul 03
2
The R Book by M. J. Crawley
Hello all- I would appreciate any guidance that can be provided. I am new to R and am using it exclusively in a statistics program I am undertaking that mainly references Minitab. My focus is on data modeling and further more multivariate data analysis as much of my work in involves chemical measurements from custom sensors using all sorts of transduction methods. I am looking for a
2007 Apr 11
1
Boxplot with quartiles generated from different algorithms
R users: I am trying to replicate the boxplot output I achieve with Minitab in R. I realize that R gives the user many more options on the algorithm used to calculate the IQR than Minitab, so I concentrated on type=6 when using the quantile() function in R. The problem I am having is setting the upper and lower limit of the whisker based on the nearest actual data that should be included. If
2012 Sep 29
3
Removing lower whisker in boxplot to see the effects of the high values
Good Afternoon- I was wanting to alter the boxplot to remove the lower whisker, both the whisker line and staple just on the lower end. Is there a way to do this? As my code is currently: boxplot(log_loads~ind,data=nfmaum, horizontal=TRUE, notch=T, outline=FALSE, whisker=0, main="Maumee River Near Future Climate Scenarios", ylab="Log Load",xlab="Climate Scenarios")
2003 May 11
2
what does boxplot draw?
Dear r-help, Unfortunately I cannot find in the documentation what determines ranges of a 'box' in the box-and-whisker plot. It is said in "Simple R" (http://www.math.csi.cuny.edu/Statistics/R/simpleR) that they are 1st and 3rd Qus usually. I tried to add to boxplot lines with (quantile(x,probs=0.25)), but lines do not coincide with edges of boxes.
2005 Jul 10
2
Boxplot in R
I am trying to draw a plot like Matlab does: The upper extreme whisker represents 95% of the data; The upper hinge represents 75% of the data; The median represents 50% of the data; The lower hinge represents 25% of the data; The lower extreme whisker represents 5% of the data. It looks like: --- 95% | | ------- 75% | | |-----| 50% | | | | -------
2009 Nov 11
1
AMRAtoMA
Hello R Users! I have a question about the output of ARMAtoMA when used to calculate the variance of a model. I have a mixed model of the form ARMA(1,1). The actual model takes the form: X(t) = 0.75X(t-12) + a(t) - 0.4a(t-1) Given that gamma(0) takes the form [(1 + theta^2 - 2*theta*phi)/(1-phi^2)]*sigma(a), I would expect a process variance of 4.02*sigma(a) when I substitute 0.75 for phi and
2011 Mar 07
3
linear mixed model with nested factors
Hi R-help. I am trying to run a linear mixed model with nested factors with either lme or lmer and I am having no luck obtaining the same results as Minitab. Here is Minitab's code: MTB > GLM 'count' = site year replicate(site year) site*year; SUBC> Random 'year' 'replicate'; Can you tell me how to code this in R? The settings are typeII, Tukey,
2005 Feb 11
1
importing minitab datasets
I'm having trouble using the read.mtp function in the foreign package to import datasets from minitab (.mtw) format. Specifically, each file I try to import fails to load any data beyond a header row stating the version of Minitab that saved the dataset. I get this error: incomplete final line found by readtableHeader on 'income.mtw' The dataset appears to be complete (ie, using
2005 Apr 20
6
Anova - adjusted or sequential sums of squares?
Hi I am performing an analysis of variance with two factors, each with two levels. I have differing numbers of observations in each of the four combinations, but all four combinations *are* present (2 of the factor combinations have 3 observations, 1 has 4 and 1 has 5) I have used both anova(aov(...)) and anova(lm(...)) in R and it gave the same result - as expected. I then plugged this into
2008 Jul 06
1
Different Autocorrelation using R and other softwares
Dear All, Would like to ask the inconsistency in the autocorrelation from R with SPSS/Minitab. I have tried a dataset x with 20 data (1-20) and ask R to give the autocorrelation of different lags using the command < acf(x, lag.max=100, type = "correlation"), However while SPSS and Minitab give the same answers (0.85 for lag1), R gives 0.3688 which is much smaller. Obviously, the
2004 May 14
1
covariates in lm
Dear R list, I have been trying to do a linear model, extracting the effect of a covariate.... and the results do not match, when I do it with other programs (e.g. minitab).... so it is obvious that I was doing something wrong. Whan I do it with minitab, I have this results: (sector is a factor and depth is the covariate): Source DF Seq SS Adj SS Adj MS F P
2003 Nov 19
2
Difference in ANOVA results - R vs. JMP/Minitab
Hi, I ran a small data set from a factorial experiment through R, Minitab and JMP... the result from R is significantly different from what Minitab or JMP give... The data set is at the following link: http://www.personal.psu.edu/nug107/Uploads/2x3_16repsANOVA.txt The first 5 columns are the factors and the next three are responses. In particular, for the response beta11MSE, two of the
2006 Feb 09
4
New user: Custom probability distribution
Hello, Given a probability function: p(x) = 12 / (25(x+1)) , x=0, 1, 2, 3 we generate the following values: C1 C2 0 0.48 1 0.24 2 0.16 3 0.12 Now, I'm supposed to create 50 random values using this table. In MiniTab, I simply selected Calc -> Random Data -> Discrete, and selected the columns, and it created 50 random values in a new column.[1] How do I do the
2008 Apr 21
1
R-2.7.0 RC (2008-04-20 r45403) fails fullcheck
A strange thing happened. After installing the most recent RC version of 2.7 (2008-04-20 r45403) I compiled it as usual with no errors. After installing it I ran "make fullcheck". I got as far as testing recommended packages and I got the following: ... -------- Testing package foreign -------- Running examples in 'foreign-Ex.R' ... Comparing `foreign-Ex.Rout' to
2007 Feb 05
5
Beginner Question on Persp()
I recently downloaded R for Windows, running on Win XP. I'm trying to create a perspective plot but not having any luck after reading the R manual and several examples found on the Internet. I have a 100 x 100 matrix of Z data as a tab-delimited text file exported from Minitab. I read this in to R using read.delim; this seemed to go ok. I created X and Y using seq() to get 100 divisions
2003 Dec 08
2
Character graphics
Does anyone else miss email-friendly character graphics such as the following example, produced using Minitab? Histogram of C6 N = 478 N* = 21 Each * represents 2 observation(s) Midpoint Count -12 16 ******** -11 53 *************************** -10 63 ******************************** -9 83
2004 Nov 21
1
Two factor ANOVA in lme
I want to specify a two-factor model in lme, which should be easy? Here's what I have: factor 1 - treatment FIXED (two levels) factor 2 - genotype RANDOM (160 genotypes in total) I need a model that tells me whether the treatment, genotype and interaction terms are significant. I have been reading 'Mixed effects models in S' but in all examples the random factor is not in the main
2008 Sep 25
5
Dot plot - equivalent of MINITAB
hi folks, Bit of a newbie, but I've spent a fair bit of time looking for an answer on this, with no joy. Can anyone help me? Dataset: A single column of values in a csv file (eg. 52, 53, 54, 85, etc) Goal: In Minitab, you have what they call a dot plot. It's a histogram, where a single dot represents a set of identical values (eg. 57, 57, 57 would be one dot). Multiple dots are
2010 Feb 09
3
Goodness
Hola, LLevo buscando desde hace tiempo como hacer el Goodness of fit test en R. Es decir, me explico, intento hacer una cosa parecida que se hace en Minitab, por ejemplo, yo tengo un conjunto de datos, y lo que quiero es sabes que tipo de distibuciĆ³n es, en minitab se hace un histograma para ver si se ajusta bien o no a la campana de Gauss, luego vemos si aproximar la distribuciĆ³n de la muestra
2000 Dec 22
1
Found "answer" to my question on MTB's INDICATOR
Dear R-Friends, Sorry to bother everyone with my earlier question: "Do we have similar R function to work like Minitab's INDICATOR?" I found the way to make things work: e.g., > x <- c(2,2,5,3,6,5,NA) > model.matrix(~ factor(x) - 1) factor(x)2 factor(x)3 factor(x)5 factor(x)6 1 1 0 0 0 2 1 0 0 0