similar to: Looping through all possible combinations of cases

Hi I have very simple issue as I am still new to the group of R I have basically vector of names for which i want to create mutliple combinations and then place them in different vectors. In some other language I can just place a third dimension to separate list (or matrix) but i do not know how to do it in R. My issue is simple I use cc<-combn(colnames(DD),2) I would need to have this

Is there a way to get a list of similar words to the ones a user has searched for? So if they search for (in my case) transferaze which has no matches I can get back an array like this [''transferase''] ? I know I can just add ~ on the end to make it fuzzy, but what I''d like is to be able to say "Sorry, no matches for ''transferaze''. Did you

Dear everybody, I have the following challenge. I have a data set with 2 subgroups, dates (days), and corresponding values (see example code below). Within each subgroup: I need to aggregate (sum) the values by week - for weeks that start on a Monday (for example, 2008-12-29 was a Monday). I find it difficult because I have missing dates in my data - so that sometimes I don't even have the

Hello All, I have just installed my R 2.4 (windows) as a test trying to load a data frame and run combn() for each line into another file. How do I do this? data.csv: a,b,c,d 1,2,3.4 g,3,6,t etc x=data.csv, m=3 Thank you Zam _________________________________________________________________________________ This email contains confidential information intended only for the person named

I am sorry, I'd like to split my column ("names") such that all the beginning of a string ("X..") is gone and only the rest of the text is left. x<-data.frame(names=c("X..aba","X..abb","X..abc","X..abd")) x$names<-as.character(x$names) (x) str(x) Can't figure out how to apply strsplit in this situation - without using a

Dear list, I have a set of 100+ variables. I would like to have one by one crosstables for each variable. I started with table(variable1, variable2) table(variable1, variable3) table(variable1, variable4) ... table(variable2, variable3) table(variable2, variable4) ... It seems rather tedious. Any better ideas around? Thanks for any help! Gerit -- NUR NOCH BIS 31.01.! GMX FreeDSL -

Dear all, Is there a way to compute and list all combinations with replication of two elements in sets of 8 elemnts? For example, I've two elements, 0 and 1, and I would to get all possible combinations with replication such as, for example, 00000000, 00000001, 00000010, and so on. They are 2^8 and it's very hard to list handly!! Thank you Marina -- View this message in context:

I am trying to print out a list of strings of length 11 based on integers 0 through 10. The rules as given to me for the ordering are: The first digit must be 0. The 2nd digit must be 0 or 1. The 3rd digit must equal the 2nd digit or the 2nd digit +1. ... Given the final digit, n, all digits 0 through n must appear in a given sequence. So the final 1024 item list should look like 0 1 2 3 4 5

I am new to R and I suspect my problem is easily solved, but I haven't been able to figure it out without using loops. I am trying to implement Blair & Karniski's (1993) permutation test. I've included a sample data frame below. This data frame represents the conditional means (C1, C2) for 3 subjects in 2 consecutive samples of a continuous data set (e.g. ERP waveform).

I''m sorry - just couldn''t come up with a subject that describes the problem :( Anyway, this is my problem. I have a long list of fields that need to be displayed when a ''show'' is requested on the controller. I''m now doing the list.rhtml and looking for a DRY way to do the following. For each data item, I have 2 fields - one is the item name, the

I have a matrix of size "n" and I want to create a new one in which the columns are sums of the original matrix, with some order in the sums. For example, if matrix A has 4 columns, then the new matrix should have 6 columns with the following info from the columns of A: 1+2, 1+3, 1+4, 2+3, 2+4, 3+4. If matrix A has 5 columns, then the new matrix has 10 columns: 1+2, 1+3, 1+4, 1+5, 2+3,

Hi, I am trying to generate all unordered combinations of a set of numbers / characters, and I can only find a (very) clumsy way of doing this using expand.grid. For example, all unordered combinations of the numbers 0, 1, 2 are: 0, 0, 0 0, 0, 1 0, 0, 2 0, 1, 1 0, 1, 2 0, 2, 2 1, 1, 1 1, 1, 2 1, 2, 2 2, 2, 2 (I have not included, for example, 1, 0, 0, since it is equivalent to 0, 0, 1). I have

Dear all! I have a vector of names names<-("V1", "V2", "V3",....., "V15") I could create all possible combinations of these names (of all lengths) using R: combos<-lapply(1:15,function(x) {combn(names,x) }) I get a list with all possible combinations of elements of 'names' that looks like this (just the very beginning of it): [[1]] - the

Hello! # I have 3 vectors of values: values1<-rnorm(10) values2<-rnorm(10) values3<-rnorm(10) # In real life, all 3 vectors have a length of 25 # I create all possible combinations of 4 based on 10 elements: mycombos<-expand.grid(1:10,1:10,1:10,1:10) dim(mycombos) # Removing rows that contain pairs of identical values in any 2 of these columns: mycombos<-mycombos[!(mycombos$Var1

Hi , I am new to R . I am facing difficulty how to make pairwise comparisions. For example. I have a file which looks like below a b c d x 3 6 7 6 y 7 8 6 5 z 5 4 7 8 Here I need to look for the each pairwise comparisions (ab,ac,ad,bc,bd,cd for each row) For instance ,looking at first row, for x i need to look for ab values and take the min(3,6) >5 ,if its satistfies the count should be

General problem: I have 20 projects that can be invested in and I need to decide which combinations meet a certain set of standards. The total possible combinations comes out to 2^20. However I know for a fact that the number of projects must be greater than 5 and less than 13. So far the the code below is the best I can come up with for iteratively creating a set to check against my set of

Hello all, I am trying to create a matrix of 1s and -1s without any repetitions for a specified number of columns. e.g. 1s and -1s for 3 columns can be done uniquely in 2^3 ways. -1 -1 -1 -1 -1 1 -1 1 -1 -1 1 1 1 -1 -1 1 -1 1 1 1 -1 1 1 1 and for 4 columns in 2^4 ways and so on. I finally used the function combn([0 1],3) that I found at the following link

Let say, I have a matrix with 8 rows and 6 columns:  >  df1  <- matrix(NA, 8, 4)  > df1       [,1] [,2] [,3] [,4]  [1,]   NA   NA   NA   NA  [2,]   NA   NA   NA   NA  [3,]   NA   NA   NA   NA  [4,]   NA   NA   NA   NA  [5,]   NA   NA   NA   NA  [6,]   NA   NA   NA   NA  [7,]   NA   NA   NA   NA  [8,]   NA   NA   NA   NA  Now I want to get **all possible** ways to fetch 6 cells at a

I have a list (length 750), each element containing a vector of unique strings (unique gene ids), with length up to ~40 (median 15). I want to compile a matrix of all possible triplets and their frequency within gene elements. Using combn and a lot of looping, I am accomplishing this but it is VERY slow. I've tried to figure out a way to vectorize this, using "match" and

like: "a" %in% "abcd" TRUE Thanks.