similar to: Average plan

Hi all - I'm trying to generate lattice barchart graphs with missing values, and came across the following: This does not run. I would expect it to: library(lattice) D = data.frame(X=1, Y=factor(letters[2], letters[1:2])) barchart(~ X, D, groups=Y) Error in grid.Call.graphics("L_rect", x$x, x$y, x$width, x$height, resolveHJust(x$just, : invalid line type which is simply

Folks, I have three dataframes storing some information about two currency pairs, as follows: R> a EUR-USD NOK-SEK 1.23 1.33 1.22 1.43 1.26 1.42 1.24 1.50 1.21 1.36 1.26 1.60 1.29 1.44 1.25 1.36 1.27 1.39 1.23 1.48 1.22 1.26 1.24 1.29 1.27 1.57 1.21 1.55 1.23 1.35 1.25 1.41 1.25 1.30 1.23 1.11 1.28 1.37 1.27 1.23 R> b EUR-USD NOK-SEK 1.23 1.22 1.21 1.36 1.28 1.61 1.23 1.34 1.21 1.22

No no, eso lo he sacaod, es decir, tengo la matriz de confusión para las OK/NOK, lo que no entiendo es como extraer las conclusiones sobre el modelo, de cara a como afectan las variables. He seguido dos estrategias: 1-Crear arboles de clasificacion con las variables más importantes del random Forest, pero el modelo se empobrece bastante. 2- Sacar los partialPlot, para ver la influencia de cada

Hi, so I don't speak computer and I have no idea what this code is telling the program to do, but I apparently need to be able to find and isolate influencial observations. Problem, I have no idea what the error means and where it may be from in the code. error I get is below the code { ## OLS results NameC<- lm(gpanew~female+female:lastinit+agenew+canadian+mom_ed+yearstudy) ## default:

Gracias por la pronta respuesta, pero tras leer la contestación de la gente, sigo sin entender muy bien la explicación. Le responden lo siguiente: "Each point on the partial dependence plot is the average vote percentage in favor of the "Yes trees" class across all observations, given a fixed level of TRI. It's not a probability of correct classification. It has absolutely

Dear R-users, As noted by Paul Murrell < p.murrell at auckland.ac.nz > there is errors in the code for polar plotting I send to R-help under the title "Polar plot, circular plot (angular data)" at Thu Oct 17 2002 - 12:18:20 CEST. Thanks! I have reorganized the code into a structure ('pp'). This allows plots to be modified to a greater extent by passing arguments by ...

Mi matriz de datos inicial estaba muy desbalanceada (5% de la clase minoritaria), por lo que he creado con el algoritmo SMOTE un dataset balanceado con el que he creado el modelo, y luego sobre ese modelo he creado la matriz de confusión con los datos originales. Respecto a lo que me comentas, Carlos, creo que además de todo lo que comentas, que está bien, en micaso es necesario también saber no

Buenas, Cuando estoy haciendo un random Forest para clasificación y hago el gráfico partialPlot, siendo mi respuesta OK/NOK, me sale en el eje X el valor de la variable, pero en el eje Y me salen valores de entre -1 y 1. ¿Qué significado tiene? Adjunto un ejemplo: https://www.dropbox.com/s/4b92lqxi3592r0d/Captura.JPG?dl=0 Gracias!!! [[alternative HTML version deleted]]

Here is the first Perl script I've tried to write to run rsync. It seems to work, but I don't see the progress like I should. I apologize if it's sloppy, I should add that it's not only the first perl script I've written for rsync, it's the first perl script I've written at all. ___________________________ #!/usr/bin/perl -w print " This command will DELETE

Hi, I'm looking for a function that will take a list of columns or data.frame and corvert it to cartesian pairlist. For example for this data.frame (see below), I'd like to get a list of all possible pairs: > sound cs rs ns 7 5 2 4 5 4 6 3 1 8 4 1 6 4 2 6 7 1 2 2 5 9 2 5 how can I get this? > mylist ((cs,rs), (cs,ns), (rs,ns))

I think my problems are coused by a fundamental R incompatibility in how matrices are stored and the usual way of specifying Cartesian coordinates. When I do data<-read.table("~/r/rt/data/unif/6cbcif2d.out",header=TRUE) x<-unique(data$lag1) y<-unique(data$lag2) z<-matrix(data$cif2d,length(y),length(x)) This z matrix is printed apparently correctly from a Cartesian point of

Hi all, I'm trying to plot this two curves in a single cartesian plane, but when I plot the first one, the plot appears with no negative "y" value. When I plot the second curve, it almost does not apear in the graph. I was trying the plot.window but with no success. Can someone help me with this? If possible, I'd like to plot this curves in a perfect cartesian plane. f =

Hi, I'd like to make a pairwise comparison of a data.frame and I'm looking for a function that will take a list of columns or data.frame and corvert it to cartesian pairlist. For example for this data.frame (see below), I'd like to get a list of all possible pairs: > sound cs rs ns 7 5 2 4 5 4 6 3 1 8 4 1 6 4 2 6 7 1 2 2 5 9 2 5 how can I get

My routine (below) works OK but misbehaves if the on-screen plot is made wider using the mouse. The problem is caused by using par("usr")[1] - 0.07 * (par("usr")[2] - par("usr")[1]) to locate two items on the y-axis. The rest of the labeling is controlled by the "line=0" parameter setting. Of course resizing changes the absolute plot width, and

Dear R-users, Hereby a polar plot function for plotting angular data. I hope it will be usefull for some of you. I had a need to plot frequencies of wind-directions. The not-that-cheap SigmaPlot software did not allow me to change the orientation of the angular axis to clockwise orientation (what is used for meteorological observations). I even tried the latest version availible at the time

Hi, At Rs6000/AIX-4.3.3 the rsync-2.5.5 works ok when make local connections or I use -e rsh or -e ssh for remote connections, like: (OK) ./rsync -vacz . /user (OK) ./rsync -vacz -e rsh . user@10.4.2.199:user (OK) ./rsync -vacz -e ssh . user@10.4.2.199:user but with standart remote rsync without -e (NOK) ./rsync -vacz . user@10.4.2.199::user returns: rsync: failed to connect to 10.4.2.199:

Dear R users I want to compute Kendall's Tau between two vectors x and y. But x and y may have zeros in the same position(s) and I wrote the following function to be sure to drop out those "double zeros" "cor.kendall" <- function(x,y) { nox <- c() noy <- c() # for (i in 1:length(x)) if (x[i]!= 0 | y[i] != 0) nox[length(nox)+1]<- x[i] for (i in

Is there packaged code to convert geographical coordinates (e.g., longitude, latitude, elevation) to Cartesian coordinates in 3-space? I can see how to do this using 1. a spherical-to-Cartesian conversion like pracma::sph2cart(tpr) http://cran.r-project.org/web/packages/pracma/ 2. a geographical-to-spherical conversion. This seems to involve (in roughly increasing order of difficulty or

I'm working in Rosario, Argentina, trying to plot some contours. I found the function "draw.contour" created by James Forester at R-bloggers. If you take a look at that function you'll see it's very useful! But I have a problem with it and James is trying to help me (but also asked me to seek for more help) I hope you can help me (don't worry if you can't): Using

hi all what about this... I just put together a box on a web shop (komplett.no) that will cost me NOK ~1850 (? 216) plus a small ?50 drive and cables, so say ?300. This consists of a cheap MB with a duron 1400, 256MB SDRAM and two HFC-PCI cards (if capijod will finish off the zaptel-driver soon). This is all in a cheap PC case. What do you think? Should this be doable? as a product? With only IP