similar to: Please Help

Just out of curiosity, what is the difference between the terms for package and library ? Why are we loading a package with the library() command ? If this is a case of RTFM, I would be happy to do so if pointed in the right direction. I have searched the FAQ and mail archives and only came up with http://tolstoy.newcastle.edu.au/R/help/05/02/12162.html but this still does not explain what is

Dear all, I already posted a question regarding this to an existing thread: http://tolstoy.newcastle.edu.au/R/e2/devel/06/10/0852.html#start I apologize for the double posting but I have some further information that might be illuminating. I am trying to cross-compile my R-package under ubuntu linux, kernel 2.6.17-10-generic, on an IBM T60. I am following the suggested steps in

Hi! I have browsed the help archives but did not find anything on the subject: How to make publication quality graphs with R best? Is there some document about that topic out there? The problem is that the graphs look nice on the screen but when printed in black and white every color apart from black doesn't look very nice. Is there some guideline how to set color palettes and or fill

Hi R-users, Following this post http://tolstoy.newcastle.edu.au/R/help/06/06/28965.html , how do I get last two rows (or six or ten) by id group out of the data frame? Here the example gives just the last row. Sincere thanks, Lauri [[alternative HTML version deleted]]

Dear R help, In the middle of my session, I started receiving the error message "bad value" regardless of what I entered. I had to close R and restart it. When the error occurred, I was creating basic lattice plots, with no other add-on packages running. I am running R through John Fox's XEmacs interface, XEmacs version 21.4.20 on a Windows XP Pro machine with 2 GB of RAM. I have

Dear all, I have a matrix X with 47 lines and say 500 columns - values are in {0,1}. I'd like to compare lines. For that, I first did: for (i in 1:(dim(X)[1]-1)) for (j in (i+1):dim(X)[1]) { Y <- X[i,]+Y[j,] etc. but, since it takes a long time, I would prefer avoding loops; for that, my first idea was to add this matrix: X1=X[,rep(1:46,46:1)] to this one: res=NULL for (i in

Hi, First, let me thank Jaroslaw for making this survey. I find it quite illuminating. Now the questions: * the #1 solution below (based on cumsum) is numerically unstable. Specifically if you do the runmean on a positive vector you can easily get negative numbers due to rounding errors. Does anyone see a modification which is free of this deficiency? * is it possible to optimize the

To me it seems like writeBin() writes one char/byte more than expected. > con <- file("testbin", "wb") > writeBin("ttccggaa", con) > close(con) > con <- file("testbin", "rb") > readBin(con, what="character") [1] "ttccggaa" > seek(con, what=NA) [1] 9 > close(con) > con <-

Hello, I have difficulties combining boxes and lines in plot legend. I searched previous R-posts and found this (with no solution): http://tolstoy.newcastle.edu.au/R/help/06/07/30248.html. Is there a way to avoid boxes behind the line legends? x1 <- rnorm(100) x2 <- rnorm(100, 2) hist(x1, main = "", col = "orange",ylab = "density", xlab = "x", freq =

R-helpers: I have a dataset that has 168 subjects and 12 variables. Some of the variables have missing data and I want to use the multiple imputation capabilities of the "mice" package to address the missing data. Given that mice only supports linear models and generalized linear models (via the lm.mids and glm.mids functions) and that I need to fit Cox models, I followed the previous

Hi, I have a dataframe with 14319rows and 9 colums. for some rows there are null values.I want a dataframe without these null values.I wanna select only those that have values !=NA. kindly let me know how to do that. Ramya -- View this message in context: http://www.nabble.com/selecting-dataframe-values-that-are-not-nulls-tp19537093p19537093.html Sent from the R help mailing list archive at

I'm running R 2.7.1 on Windows XP. Lately and spontaneously, it will give an "error: bad value" message in response to any command. I have to restart R to (temporarily) fix the problem. There are two other threads I've found on the issue here: http://tolstoy.newcastle.edu.au/R/e4/help/08/01/0750.html and here: http://tolstoy.newcastle.edu.au/R/e2/help/07/06/19095.html but

<posted & mailed> Dear all, I'm trying to solve the problem, of how to find clusters of values in a vector that are closer than a given value. Illustrated this might look as follows: vector <- c(0,0.45,1,2,3,3.25,3.33,3.75,4.1,5,6,6.45,7,7.1,8) When using '0.5' as the proximity requirement, the following groups would result: 0,0.45 3,3.25,3.33,3.75,4.1 6,6.45 7,7.1

Hi All, Can anyone help me please?I don't know much about segmentation faults.I understand what it is,but why my script's throwing the error i don't know. This is my main function:---- *main<-function()* *{* * dbName<-"xyz_database"* * hostName<-"xyz.com"* * con<-myDbconnect(dbName,hostName) * *

I am attempting to import dates in the following format to R: 5/20/2010 6:45:32 PM Unfortunately I am unable to get the AM/PM function (%p) to work correctly under either 2.11.0 or 2.8.1. > strptime("5/20/2010 6:45:32 PM", "%m/%d/%Y %I:%M:%S %p") [1] NA but > strptime("5/20/2010 6:45:32", "%m/%d/%Y %I:%M:%S") [1] "2010-05-20 06:45:32"

Hi folks, I would like to trim the trailing spaces in my factor variables using lapply (described in this post by Marc Schwartz: http://tolstoy.newcastle.edu.au/R/e2/help/07/08/22826.html) but the code is not functioning (in this example there is only one factor with trailing spaces): y1 <- rnorm(20) + 6.8 y2 <- rnorm(20) + (1:20*1.7 + 1) y3 <- rnorm(20) + (1:20*6.7 + 3.7) y <-

Does Hadley's response to the following post still hold for the most recent version of ggplot2? http://tolstoy.newcastle.edu.au/R/e2/help/07/07/21347.html#21379qlink2 I'm trying to accomplish in ggplot2 what the "relation" component of "scales" does in lattice, e.g., stripplot(yield ~ variety | site, data = barley, scales = list(y = list(relation='free')))

Probably an old moon since evoqued one year ago in this link: http://tolstoy.newcastle.edu.au/R/e2/help/07/04/15738.html but I have recently re-installed Tinn-R with R 2.7.0 and forgot to insert options(warn=-1) library(svIDE) ... options(warn=0) in Rprofile.site... and could see that we have still the same warning launching R: Warning messages: 1: '\A' is an unrecognized escape in a

About 2 years ago, Tobias Verbeke asked: "I am looking for a way to capture the binary string that in normal use of graphics devices will bewritten to (most commonly) a file connection... Is there a way of capturing the binary `jpeg string' [generated by jpeg()]?" http://tolstoy.newcastle.edu.au/R/e2/devel/07/09/4276.html Brian Ripley's answer was "Nope, unfortunately,

Readers, Responding to an old post (http://tolstoy.newcastle.edu.au/R/e2/help/07/06/18850.html), and using the example in the manual: monthextract<-strptime("20/2/06 11:16:16.683", "%m") monthextract [1] NA Why is the result 'NA' and not '2'? -- r2151