similar to: ggplot doesnt work in loops?

Displaying 20 results from an estimated 11000 matches similar to: "ggplot doesnt work in loops?"

2008 Sep 04
2
printing name of object inside lapply
Dear list members, I am trying, within a lapply command, to print the name of the objects in list or data frame. This is so that I can use odfWeave to print out a report with a section for each object, including the object names. I tried e.g. a=b=c=1:5 lis=data.frame(a,b,c) lapply( lis, function (z) { obj.nam <- deparse(substitute(z)) cat("some other text",obj.nam,"and so
2007 Aug 21
2
standardized cronbach's alpha?
Hi list members Any easy way to get standardized cronbach's alpha for a scale, as in SPSS? Thanks Steve Powell proMENTE social research research | evaluation | training & consulting Kranj?evi?eva 35, 71000 Sarajevo mobile: +387 61 215 997 | office: +387 33 556 865 | fax: +387 33 556 866 Checked by AVG Free Edition. 17:44
2008 Nov 30
1
using survey weights for correlations
Dear list, I have a data file which includes, alongside various variables representing questionnaire scores, a variable for survey weights computed as the number of observations in the sample drawn from that group divided by the number of observations in the population in the group. I need to calculate a covariance matrix of the questionnaire scores for use in sem. How do I apply the weights?
2007 Sep 19
1
SEM - standardized path coefficients?
Dear list members, In sem, std.coef() will give me standardized coefficients from a sem model. But is there a trick so that path.diagram can use these coefficients rather than unstandardized ones? Thanks Steve Powell From: John Fox <jfox_at_mcmaster.ca> Date: Wed 28 Feb 2007 - 14:37:22 GMT Dear Tim, See ?standardized.coefficients (after loading the sem package). Regards, John John
2010 Jun 22
1
"save scores" from sem
Dear expeRts, sorry for such a newbie question - in PCA/factor analysis e.g. in SPSS it is possible to save scores from the factors. Is it analogously possible to "save" the implied scores from the latent variables in a measurement model or structural model e.g. using the sem or lavaan packages, to use in further analyses? Best wishes Steve Powell www.promente.org | skype
2010 Sep 10
3
ggplot bar geom: control the filling in the colour legend
Hi all, Is it possible to change the filling of the squares used to represent the colour legend in a bar plot with ggplot? in this example, fillings are raven black, I'd like them white. ggplot(diamonds, aes(clarity, colour = cut)) + geom_bar() Regards -- ------------- Benoit Boulinguiez Ph.D student Ecole de Chimie de Rennes (ENSCR) Bureau 1.20 Equipe CIP UMR CNRS 6226 "Sciences
2007 Jul 16
5
how do I draw such a barplot?
Hi, I cannot figure out how to draw a certain plot: could someone help me out? I have this data.frame from a survey my.data that looks like something like this: col1 col2 col3 col4 1 5 5 4 5 2 3 5 3 1 3 2 3 4 5 4 3 1 1 2 5 5 5 4 5 6 4 2 5 5 .... Each row represents a single questionnaire
2012 Jun 06
5
ggplot incorrect legend
How do I create a legend with ggplot? I think should be getting the FuelTypeNum in the legend. Plot: http://r.789695.n4.nabble.com/file/n4632471/Rplot.jpeg My code is: ggplot(data=tempTable, aes(x=Bands8, y=SubPercent, fill=FuelTypeNum)) + geom_bar(position="stack", stat="identity") + scale_colour_hue('my legend', breaks = levels(tempTable$FuelTypeNum),
2012 Jan 01
1
How to pass in a list of variables as an argument to a function?
Hello, I have some code that currently works fine and I am endeavoring to convert the major pieces of it into functions. This involves taking "hard coded" names of variables that are used in various places and figuring out how to abstract them out into functions where the arguments (i.e. a list of variables)?can be passed to the parent function and used within that function for various
2009 Feb 02
1
Broke ggplot...
It appears I broke ggplot in my script, but that maybe it is because the caffeine has worn off or maybe it is late in the day.   I thought I was beginning to understand ggplot, but I have encountered a silly little issue.   For some reason the following does not produce a histogram with fill due to the Person's characteristics: (Note that VADeaths_flat_df$Data works fine...)    
2011 Nov 16
1
geom_bar with missing data in package ggplot
Dear all, I was hoping someone could help with a ggplot question. I would like to generate a faceted bar chart, but missing data are causing problems. g<-structure(list(Date = structure(c(11322, 11687, 12052, 11322, 11687, 12052, 11322, 11687, 12052, 11322, 11687, 12052), class = "Date"), variable = c("Govt Revenues to GDP", "Govt Revenues to GDP",
2012 Mar 15
2
Ggplot barchart drops factor levels: how to show them with zero counts?
Hello, When plotting a barchart with ggplot it drops the levels of the factor for which no counts are available. For example: library(ggplot) mtcars$cyl<-factor(mtcars$cyl) ggplot(mtcars[!mtcars$cyl==4,], aes(cyl))+geom_bar() levels(mtcars[!mtcars$cyl==4,]) This shows my problem. Because no counts are available for factorlevel '4', the label 4 dissapears from the plot. However, I
2011 Jun 08
1
The simplest bar graph with ggplot is difficult to realize
Dear all, What is the simplest way of producing a bar graph using ggplot but avoiding calling qplot? That is, given: d <- data.frame(x=seq(1,5), y=seq(1,5)) Why does the following line return an error? ggplot(d, aes(x=x, y=y)) + stat_identity() + geom_bar(bindwidth=1) Thanks in advance, jcb!
2011 Oct 18
3
Ordering of stack in ggplot (package ggplot2)
I'm trying to reproduce the 3rd graph on the page of this site: http://learnr.wordpress.com/2009/03/17/ggplot2-barplots/ . However, the data below produces a ggplot with the stacks sorted in alphabetical order from the bottom up. I'd like the stacks to be in the order "Europe", "Asia", "Americas, "Africa", "Oceania". Is there an easy way to
2012 Jan 03
4
Changing X axis of ggplot
Thanks to Joshua Wiley for turning me on to ggplot2. I am making a plot using this: p <- ggplot(dallas, aes(x = offense_hour)) + geom_bar() + coord_polar() Dallas is a data frame, and offense_hour is a column with chron objects from the chron library. In this case, the chron object was created with the times function. It is only a time (H:M:S) with no date attached. The plot shows up fine,
2011 Sep 12
2
Automated generation of combinations
Hello,   I'd like to generate automatically all the possible combinations of a set of 8 variables (there are 535, too many to do it by hand). For example:   input: varA, varB, varC output: varA+varB+varC             varA+varB             varA+varC             varB+varC             varA             varB             varC Is there any function that produces this option?   Thank you [[alternative
2007 Jun 29
1
Print grid/ggplot to a metafile
Dear UseRs called Hadley, or Paul, I am trying to print an edited ggplot2/grid graphics to a metafile. With the commented line below it works, but when I edit the plot by uncommenting the line, it fails, because it's illegal to have 2 graphics in a metafile. It works with pdf, but even then I get two plots, which is a nuisance. I found a workaround by using windows(); savePlot, but it only
2009 Jul 16
2
GGPLOT Clipping Regions
Hi there, I'm trying to find out the command to stop clipping to plot region in ggplot. I have a bar chart (axis flipped) with labels on the bars, but the labels are clipped at the plot region box. I know it's possible to turn this off for base and lattice, but how about ggplot? par(xpd=NA) The ggplot2 manual doesn't seem to mention it, and a search for ggplot and
2009 May 14
1
text() to label points in ggplot
is there a way to label points in a graph using text(locator(1),"text") after ggplot() or qplot() ? > qplot(date, psavert, data = economics, geom = "line",main="jhdjd")->p > p+opts(text(locator(1),"HHHH"),new=T) does not work. -- View this message in context: http://www.nabble.com/text%28%29-to-label-points-in-ggplot-tp23545135p23545135.html Sent
2007 Oct 05
2
Apply vector of labels to columns of data frame
Dear list members I would like to apply a vector of labels v=c("lab1","lab2","lab3") to a dataframe df=data.frame(1:3,1:3,1:3) using some kind of loop or apply function. Any ideas? Thanks Steve Powell Checked by AVG Free Edition. 17:03 [[alternative HTML version deleted]]