similar to: No convergence using ADAPT

Dear People, I'm trying to use the function adapt, from the adapt library package, which does multidimensional numerical integration. I think I must be using the wrong syntax or something, because even a simple example does not work. Consider foo <- function(x){x[1]*x[2]} and adapt(2, lo = c(-1,-1), up = c(1,1), functn = foo) This simply hangs. A more complicated example crashes R,

R-listers, In using the adapt function, I am getting the following warning: Ifail=2, lenwrk was too small. -- fix adapt() ! Check the returned relerr! in: adapt(ndim = 2, lower = lower.limit, upper = upper.limit, functn = pr.set, Would someone explain what the 'lenwrk' value indicates in order to help diagnose this issue. Also, what are the possible codes for Ifail, so I can set

I tried to integrate numerically a function wich is similar to the following: > dummy <- function(x) { exp(-1*x) * dnorm(x) } > dummy(-100) [1] 0 > dummy(-1000) [1] NaN > dummy(-10000) [1] NaN If I choose the lower boundary to be too small integrate causes a segmentation fault: > library(integrate) > integrate(dummy, -100, 0)$value [1] 1.387143 > integrate(dummy, -1000,

Hi there. Thanks for your time in advance. I am using R 2.2.0 and OS: Windows XP. My final goal is to calculate 1/2*integral of (f1(x)^1/2-f2(x)^(1/2))^2dx (Latex codes: $\frac{1}{2}\int^{{\infty}}_{\infty} (\sqrt{f_1(x)}-\sqrt{f_2(x)})^2dx $.) where f1(x) and f2(x) are two marginal densities. My problem: I have the following R codes using "adapt" package. Although "adapt"

Hello all, I am trying to minimize a function which contains a double integral, using "nlminb" for the minimization and "adapt" for the integral. The integral is over two variables (thita and radiusb) and the 3 free parameters I want to derive from the minimization are counts0, index and radius_eff. I have used both tasks in the past successfully but this is the first time

Dear r-users, Is there any command in R allowing to evaluate a double integral? for instance let say I want to evaluate the following integral: integrate[lo=(0,1),up=(2,3)] f(x,y)=x^2+y^2 where lo is the vector of lower bounds and up that of upper bounds. I thaught the function "adapt" would work but it did not. Many thanks, Dominique K.

how does one numerically intergate the following: A=function(x,y) { xy } over the range: 2<x<0 4<y<10 say. ie how would one set up the integrate function? i forgot!

Hi, I need to integrate a 2D function over range where the limits depend on the other e.g integrate f(x,y)=x*y over {x,0,1} and {y,x,1}. i.e \int_0^1 \int_x^1 xy dydx I checked adapt but it doesn't seem to help here. Are they any packages for this sort of thing? I tried RSitesearch but couldn't find the answer to this. Many thanks for you help. Regards Saptarshi Saptarshi Guha

Hi all, Running R 0.90.1 on a RH 6.1 system. Installation of the integrate_2.1-2 package went smoothly. My code contains a loop in which integrate() is called several times in each pass. I get a segmentation fault after what seems to be a random number of calls to integrate(). Debug output shows: Program received signal SIGSEGV, Segmentation fault. promiseArgs (el=0x40276414,

Hi, Would you help me solve the following question? Thanks. Question: If I try to set the probability=0.05 and find the approximate x. (The answer should be somewhere between 2.1782 and 2.1783.) I write about this R program as follows but I don¡¦t know how to get the value of x which is between 2.1782 and 2.1783. library(mvtnorm) value<-array(1000) a<-array(1000)

Hi people, Does anybody know some Density-Based Method for clustering implemented in R? Thanks, Fernando Prass _______________________________________________________

Good point. Now this returns 0.04062184. Hmmm..... On Mon, Oct 2, 2017 at 6:30 PM, Hollie Johnson (PGR) < h.a.johnson at newcastle.ac.uk> wrote: > Hi Eric, > > > Thanks for having a look into this. I think you have a small typo... > > B <- matrix(x, nrow=3, byrow = TRUE) should read B <- matrix(y, nrow=3, > byrow = TRUE) > > > Regards, Hollie >

Currently doing some work on local maxima on a random field and have encountered an issue with the Miwa algorithm used with the pmvnorm function in the mvtnorm R package. Based on recommendations by Mi et al., we ran the mvtnorm package using the Miwa algorithm, since we have a maximum of 4 dimensions with non-singular matrices. However, running the estimation procedure in this way, we obtained

Hello Bug people, I have an unexpected behavior and am unsure whether the problem is in my thinking, my implementation or the program R. Basically I get two different answers depending on how I call a function which takes other functions as arguments as indicated below. To me it should make no difference if f is a function that returns the function g then z(f(x)) whould give the same as y<-

I'm installing openssl 0.9.5a and openssh 2.3.0p1 on an Ultra 5 running Solaris 8 with the latest cluster patch. Openssl installed without any problems. When I do a configure for openssh I get: Checking for OpenSSL directory. . . configure: error: Could not find working SSLeay / OpenSSL libraries, please install I've reinstalled openssl and everything is there. As a note I've

I have a redhat EL5 samba server hosting a collection of printers and joined to a domain. I can connect to this server and print happily from a 32-bit XP box on the domain, but a 64-bit windows server 2008 box cannot connect, and returns the error 0x000006d1. I get the same results with samba 3.0.33 (came with redhat), 3.5.3 (the latest from sernet), and 3.3.12 (this message from the

Hi there, pmvnorm(lo=c(-Inf,-Inf), up=c(Inf,Inf), mean=c(0,0) ) should give me "1", right? But it doens't - it giver me "0". Would someone help me, please? [[alternative HTML version deleted]]

Hi, I would like to interface a C code into R. Is it possible to use in the C code, functions from a R package (for instance, to use pmvnorm within loops in the C code and to call the result in a R function)? Nathalie

Hello there! My operating system is Windows XP, my version of R is the latest (R-2.5.0). Recently I have downloaded the package "mvtnorm" and a problem with the command "pmvnorm" occured. Trying to enter the lines ... A <- diag(3) A[1,2] <-0.5 A[1,3] <- 0.25 A[2,3] <- 0.5 pvmnorm(lower=c(-Inf,-Inf,-Inf), upper=c(2,2,2),mean = c(0,0,0), corr=A) I got the following

Rather specialized. As this appears to be primarily a statistical, not an R programming question, you may do better posting on a statistical site like http://stats.stackexchange.com/ if you don't get a satisfactory reply here . Alternativey, if you think this is a package bug, perhaps contact the package maintainer directly, as (s)he may not monitor this list. -- Bert Bert Gunter