similar to: generating lower triangular matrix

Hi what does this mean when i get above error? When I call function foo(), specifying parameters a and b as below a<-5 b<-6 > y <- foo(a,b) > Error in foo(a, b) : unused argument(s) (6) Thanks Zava -------------------------------------------------------- This is not an offer (or solicitation of an offer) to bu...{{dropped:24}}

Hi, what is the recommended way to vertically concatenate 2 data frames with the same column names but different number of rows? My problem is something along these lines: df1 <- data.frame(var1=var1,var2=var2,var3=var3) # nrow(df1)=1000 df2 <- data.frame(var1=var4,var2=var5,var3=var6) # nrow(df2)=2000 I tried df <- c(df1,df2), no success. stack does not seem to be appropriate

Hi, is there any function in R that shifts elements of a vector to the opposite direction of what Lag() of the Hmisc package does? (something like, Lag(x, shift = -1) ) Thanks Zava -------------------------------------------------------- This is not an offer (or solicitation of an offer) to buy/se...{{dropped}}

Hi I rbind data frames in a loop in a cumulative way and the performance detriorates very quickly. My code looks like this: for( k in 1:N) { filename <- paste("/tmp/myData_",as.character(k),".txt",sep="") myDataTmp <- read.table(filename,header=TRUE,sep=",") if( k == 1) { myData <- myDataTmp } else{ myData

Hi, i am trying to connect to a DB2 server using the DBI library. getData <- function() { driver <- dbDriver("DB2") conn <- dbConnect(driver,"server","uname","pword") data <- dbSendquery(conn, "select etc.") } When I run the function, i get the error > data <- getData() Error in

Hi, I am just starting to play with R. What is the recommended manner for calculating time spans between 2 dates? In particular, should I be using the "chron" or the "date" package (so far I just found how to calculate a timespan in terms of days)? Thanks Zava -------------------------------------------------------- This is not an offer (or solicitation of an offer) to

Hi, I have a list myList (see below) that consists of id's $'7',....,$'10' and each id has an individual array, the length of which can vary from id to id. How can I convert this list into an array, ie. stacking the individual arrays into one large array? Thanks Zava myList: $`7` [1] 20050201 20050301 20050401 20050501 $`8` [1] 20050201 20050301 20050401

Hi, I have a file fileFoo.R, say that contains these two lines, invoking function foo that is specified in "foo_details.R": source("foo_details.R") foo(parameter1) I want to specify and pass parameter1 in my command line when invoking R in linux: R --no-save <fileFoo.R. How can I do that? And how can I retrieve the value of parameter1 in my fileFoo.R function

Hi, I have a matrix HR(9x27). I would like to make a single vector with elements: t(HR[,1]) followed by t(HR[,2]) and then t(HR[,3] ... etc. Is there any neat way of converting this matrix into a vector rather doing something like c(t(HR[,1]), t(HR[,2]), t(HR[,3]) ..)? Thanks in Advance. Kind regards, Ezhil ____________________________________________________________________________________

Hi Folks, Given k RVs with MVN distribution N(mu,S) (S a kxk covariance matrix), let (w.l.o.g.) X1 denote the first r of them, and X2 the last (k-r). Likewise, let mu1 and mu2 denote their respective expectations. Then, of course, the expectation of X2 given X1=x1 is mu2 + S21*inv(S22)*(x1 - mu1) and the covariance matrix of X2 given X1=x2 is S22 - S21*inv(X11)*S12 where Sij is the

Hi, I have a simple beginner's question on removing a list of objects. Say I have objects C243.Daily1, C243.Daily2...C243.Daily5 in my workspace. I'd like to remove these without using rm five times. So I write. > a <- list(paste("C243.Daily",sep="",1:5)) > rm(a) Obviously this wouldn't work, as it would only remove the object a. But is there any way

Hello, I have two data. x<-c(1, 2, 1, 3, 2) y<-c(3, 1, 2, 3, 5) 1. How do i create matrix from this two. what i want is this x y 1 1 3 2 2 1 3 1 2 4 3 3 5 2 5 2. what is the best way to use chisq.test to get the p.value thanks Claire -- View this message in context: http://www.nabble.com/Creating-Matrix-tp17168173p17168173.html Sent from the R help mailing list

Given a vector;> ab = seq(0.5,1, by=0.1)> ab[1] 0.5 0.6 0.7 0.8 0.9 1.0 The euclidean distance between the vector elements is given by the lower triangular matrix > dd1 = dist(ab,"euclidean")> dd1    1   2   3   4   52 0.1                3 0.2 0.1            4 0.3 0.2 0.1        5 0.4 0.3 0.2 0.1    6 0.5 0.4 0.3 0.2 0.1 Convert the lower triangular matrix to a full

I have output from a program which produces a distance matrix I want to read into a clustering program in R. The output is a .txt file and is 'almost' lower triangular in the sense that it is just the triangle below the diagonal. So for example a 4-by-4 distance matrix appears as, 1 2 3 4 5 6 i.e. it looks like a lower triangular of a 3-by3. I thought I might be able

Dear list, I will like to learn how to read a lower triangular matrix in R. The input file *.txt have the following format: A B C D E A 0 B 1 0 C 2 5 0 D 3 6 8 0 E 4 7 9 10 0 How this can be done? Thanks in advance for your help Rog??rio

Hi, I have a comma separated file with element names in first column like shown below : Name_1,0 Name_2,0.8878,0 Name_3,0.6777,0.7643,0 Name_4,0.9844,0.1234,0.1414,0 Original data is a 10000x10000 symmetric matrix (600 MB). To reduce file size, I have minimized matrix to only lower triangle. Is there a (memory) efficient way to 1) read file 2) compute first and second principal components and

Hello! I'm trying to build a lower triangular matrix (with zeros in the diagonal) from a particular dataframe. The matrix I have to construct has 203 rows and 203 columns and that makes 20503 values to be included within (that's why I can't do it manually). To illustrate the dataframe I have, I'll give you an example of a dataframe and matrix with dimensions 6x6 (to make it

Given a vector;> ab = seq(0.5,1, by=0.1)> ab[1] 0.5 0.6 0.7 0.8 0.9 1.0 The euclidean distance between the vector elements is given by the lower triangular matrix > dd1 = dist(ab,"euclidean")> dd1    1   2   3   4   52 0.1                3 0.2 0.1            4 0.3 0.2 0.1        5 0.4 0.3 0.2 0.1    6 0.5 0.4 0.3 0.2 0.1 Convert the lower triangular matrix to a full

Dear list, Does anyone know how to fit the power law distribution? I have the empirical distribution and would like to check whether it fits power law (with the power estimated from the data). Any hints are appreciated Best regards Galina [[alternative HTML version deleted]]

I want to use read.table to input many files, each for a different year. I would like to use the macro variable 't' to refer to the exact file that I would like to input the data using read.table. How could I do this? Thank you! for (t in 1970:2005) { edge <- read.table(file="edge_t.csv", header=T, sep=",") ## I will have many rows of code following the