similar to: converting list to an array

Hi I rbind data frames in a loop in a cumulative way and the performance detriorates very quickly. My code looks like this: for( k in 1:N) { filename <- paste("/tmp/myData_",as.character(k),".txt",sep="") myDataTmp <- read.table(filename,header=TRUE,sep=",") if( k == 1) { myData <- myDataTmp } else{ myData

Hi what does this mean when i get above error? When I call function foo(), specifying parameters a and b as below a<-5 b<-6 > y <- foo(a,b) > Error in foo(a, b) : unused argument(s) (6) Thanks Zava -------------------------------------------------------- This is not an offer (or solicitation of an offer) to bu...{{dropped:24}}

Hi, what is the recommended way to vertically concatenate 2 data frames with the same column names but different number of rows? My problem is something along these lines: df1 <- data.frame(var1=var1,var2=var2,var3=var3) # nrow(df1)=1000 df2 <- data.frame(var1=var4,var2=var5,var3=var6) # nrow(df2)=2000 I tried df <- c(df1,df2), no success. stack does not seem to be appropriate

Hi, is there any function in R that shifts elements of a vector to the opposite direction of what Lag() of the Hmisc package does? (something like, Lag(x, shift = -1) ) Thanks Zava -------------------------------------------------------- This is not an offer (or solicitation of an offer) to buy/se...{{dropped}}

Hi, i am trying to connect to a DB2 server using the DBI library. getData <- function() { driver <- dbDriver("DB2") conn <- dbConnect(driver,"server","uname","pword") data <- dbSendquery(conn, "select etc.") } When I run the function, i get the error > data <- getData() Error in

I have two R objects, allDataSubset1 and allDataSubset2 and the str of both of them is shown below ( I don't show all 18 lists for space purposes ). The difference between them is that the times ( and possibly the days ) and the data is different and what I want to do is merge them so that only the data in Subset2 that is the same day and times as Subset 1 remains in the merged dataset.

Hi, I am just starting to play with R. What is the recommended manner for calculating time spans between 2 dates? In particular, should I be using the "chron" or the "date" package (so far I just found how to calculate a timespan in terms of days)? Thanks Zava -------------------------------------------------------- This is not an offer (or solicitation of an offer) to

Hi, I would like to generate below triangular matrix for some a. 0 0 0 0 0 0 1 0 0 0 0 0 a 1 0 0 0 0 a^2 a 1 0 0 0 a^3 a^2 a 1 0 0 a^4 a^3 a^2 a 1 0 What's an efficient way to do this? (this matrix being KxK, K very large) Thanks Zava -------------------------------------------------------- This is not an offer (or solicitation of an offer) to buy/se...{{dropped}}

Hi, I have a file fileFoo.R, say that contains these two lines, invoking function foo that is specified in "foo_details.R": source("foo_details.R") foo(parameter1) I want to specify and pass parameter1 in my command line when invoking R in linux: R --no-save <fileFoo.R. How can I do that? And how can I retrieve the value of parameter1 in my fileFoo.R function

Hello I tried to define replacement functions for the class "mylist". When I test them in an active R session, they work -- however, when I put them into a package, they don't. Why and how to fix? make_my_list <- function( x, y ) { return(structure(list(x, y, class="mylist"))) } mylist <- make_my_list(1:4, letters[3:7]) mylist mylist[['x']] <- 4:6

I can define a list containing NULL elements: > myList <- list("aaa",NULL,TRUE) > names(myList) <- c("first","second","third") > myList $first [1] "aaa" $second NULL $third [1] TRUE > length(myList) [1] 3 However, if I assign NULL to any of the list element then such element is deleted from the list: > myList$second <-

Hi, I'm pretty new to R. I have an object (say a list) and I I have a function that I call on various columns in that list (excuse terminology if it's wrong/ambiguous). Imagine its like this (actual values are unimportant) and called mylist: >mylist A B 1 5 2 5 3 6 4 8 5 0 I have a function: foo = function(param){ #modify list A or B values depending on

Hi, I'm have a list of integer vectors and I want to perform an outer() like operation on the list. As an example, take the following list: mylist <- list(1:5,3:9,8:12) A simple example of the kind of thing I want to do is to find the sum of the shared numbers between each vector to give a result like: result <- array(c(15,12,0,12,42,17,0,17,50), dim=c(3,3)) Two for() loops is the

Dear R users, Let's say I have a list with components being 'm' matrices (as exemplified in the "mylist" object below). Now, I'd like to subset this list based on an index vector, which will partition each matrix 'm' in 2 sub-matrices. My questions are: 1. Is there an elegant way to have the results shown in mylist2 for an arbitrary number of matrices in mylist?

Hi I have a list : mylist <- list( a = NULL, b = 1, c = 2 ) > mylist[1] $a NULL > is.null(mylist[1]) [1] FALSE > is.null(mylist$a) [1] TRUE why? I need to use mylist[1]

I have this awkward problem with trellis (lattice). I am trying to generate some plots through loops but the .eps file is empty. When I generate them in a list and print them outside the loop all is fine. this is an example below:( nothing shows up in foo.eps, but all show up in foo1.eps) R vesion 2.0.1, lattice version 0.10-16, on a debian 2.6.8-1 kernel. X <- data.frame(x=rnorm(10000),

How do I parse an identifier of a list component, e.g. mylist$mycomponent or mylist[[1]] ? Parse does not do the job, e.g. parse(text="mylist$mycomponent") returns an expression with just one term, instead of "mylist", "$", "mycomponent". What I need is a way to extract the list name (e.g. "mylist"), given an identifier of a component.

I've been doing some consulting with students who seem to come to R from SAS. They are usually pre-occupied with do loops and it is tough to persuade them to trust R lists rather than keeping 100s of named matrices floating around. Often it happens that there is a list with lots of matrices or data frames in it and we need to "stack those together". I thought it would be a simple

Dear List, Let's say I have a list whose components are 2 matrices (as exemplified in the "mylist" object below). I'd like to create a list with components being 4 matrices based on an logical index vector. is there a way to simplify what I'm doing to obtain the results in "mylist2"? I'd like something that would work on an arbitrary number of elements in

Sorry My previous report is not detailed. In R, you will get this: > mylist <- list() > mylist[[1]] Error in mylist[[1]] : subscript out of bounds > mylist[[1]] <- c(1) Error: (list) object cannot be coerced to vector type 14 > mylist[[1]] <- c(1,2) > mylist[[1]] <- c(1) > mylist [[1]] [1] 1 I was trying to assigning c(1) to (mylist[[1]] <- c(1)) -- it seems