Displaying 20 results from an estimated 4000 matches similar to: "R: Appending the files"
2010 Feb 12
3
Code working but too slow, any idea for how to speed it up ?(no loop in it)
Hello my friends,
here is a code I wrote with no loops on matrix that is taking too long (2
seconds and I call him 720 times --> 12 minutes):
mat1 and mat2 are both matrix with 103 columns and 164 rows.
sequence <- matrix(seq(1 : ncol(mat1)))
returns <- apply(sequence, 1, function, mat1= mat1, mat2 = mat2, day = 1)
function<- function(mat1, mat2, colNb, day){
2007 Nov 12
1
update matrix with subset of it where only row names match
I guess this has a simple solution:
I have matrix 'mat1' which has row and column names, e.g.:
A B C
row1 0 0 0
row2 0 0 0
....
rown 0 0 0
I have a another matrix 'mat2', essentially a subset of 'mat1' where the
rownames are all in 'mat1' e.g.:
B
row3 5
row8 6
row54 7
I want to insert the values of matrix mat2 for column B (in reality it
could be some or
2005 Nov 03
4
merging dataframes
Dear List,
I often have to merge two or more data frames containing unique row
names but with some columns (names) common to the two data frames and
some columns not common. This toy example will explain the kind of setup
I am talking about:
mat1 <- as.data.frame(matrix(rnorm(20), nrow = 5))
mat2 <- as.data.frame(matrix(rnorm(20), nrow = 4))
rownames(mat1) <- paste("site",
2007 Jul 24
1
cor inside/outside a function has different output
I'm calculating correlations between two matrices
mat1 <- matrix(sample(1:500,25), ncol = 5,
dimnames=list(paste("mat1row", 1:5, sep=""),
paste("mat1col", 1:5, sep="")))
mat2 <- matrix(sample(501:1000,25), ncol = 5,
dimnames=list(paste("mat2row", 1:5, sep=""),
paste("mat2col", 1:5, sep="")))
2003 Oct 31
2
Summing elements in a list
Hi,
Suppose that I have a list where each component is a list of two
matrices. I also have a vector of weights. How can I collapse my
list of lists into a single list of two matrices where each matrix
in the result is the weighted sum of the corresponding matrices.
I could use a loop but this is a nested calculation so I was hoping
there is a more efficient way to do this. To help clarify,
2010 Jan 29
7
Simple question on replace a matrix row
Hello, I have a matrix mat1 of dim [1,8] and mat2 of dim[30,8], I want to
replace the first row of mat2 with mat1, this is what I do:
mat2[1,]<-mat1 but it transforms mat2 in a list I don't understand, I want
it to stay a matrix...
-----
Anna Lippel
--
View this message in context: http://n4.nabble.com/Simple-question-on-replace-a-matrix-row-tp1427857p1427857.html
Sent from the R help
2010 Oct 14
1
rbind ing matrices and resetting column numbers
Sorry for the verbose example. I want to row bind two matrices, and all works except I want the column labelled "row" to be sequential in the new matrix, shown as "mat3" here, i.e. needs to be 1:6 and not 1:3 repeated twice. Any suggestions?
Thanks
J
> colnm1 <- c("row","ti","counti")
> colnm2 <-
2007 Nov 21
2
matrix elementwise average with NA's
Hello fellow R users,
I have a matrix computation that I imagine should be relatively easy to do, however I cannot figure out a nice way to do it. I have two matrices, for example
mat1 <- matrix(c(1:5,rep(NA,5), 6:10), nrow=3, byrow=T)
mat2 <- matrix(c(2:6, 6:10, rep(NA,5)), nrow=3, byrow=T)
I'd like to compute the element-wise average for non-NA entries. Of course
(mat1+mat2)/2
2010 Mar 29
2
Need help on matrix manipulation
Dear all,
Ket say I have 3 matrices :
mat1 <- matrix(rnorm(16), 4)
mat2 <- matrix(rnorm(16), 4)
mat3 <- matrix(rnorm(16), 4)
Now I want to merge those three matrices to a single one with dimension
4*3=12 and 4 wherein
on resulting matrix, row 1,4,7,10 will be row-1,2,3,4 of "mat1", row
2,5,8,11 will be row-1,2,3,4 of "mat2" and row 3,6,8,12 will be row-1,2,3,4
of
2007 Sep 13
2
Running R file from Command line.
Hi all,
Is there any way through which i can run a R file from Command line.
For example
> r mean.R
Thanks and Regards,
Vaibhav Gathibandhe
[[alternative HTML version deleted]]
2010 Jan 27
1
How to sort data.frame
Dear R heleprs
Suppose I have following data
Scenarios
combination_names
series1
series2
Sc1
MAT2 GAU1
7.26554
8.409778
Sc2
MAT2 GAU2
7.438128
8.130275
Sc3
MAT3 GAU1
8.058422
8.06457
Sc4
MAT1 GAU2
8.179855
8.022071
Sc5
MAT3 GAU2
8.184033
8.191831
Sc6
MAT3 GAU2
7.50312
8.232425
Sc7
MAT1 GAU2
7.603291
8.200993
Sc8
MAT1 GAU1
8.221755
8.380097
Sc9
MAT3 GAU2
7.904908
2010 Mar 02
2
turn character string into unevaluated R object
Hi,
How to turn a character string into an unevaluated R object? I want to load some files in a directory into data matrix R objects. I could do this with read.table and assign (see below). Then, I want to turn the character string representing a file name (the evaluated expression of i) into an unevaluated R object. Basically, I want to create matrices whose names are the same as the related file
2008 Aug 15
2
cor() btwn columns in two matrices - no complete element pairs
Hi everyone,
I'm trying to calculate correlation coefficients between corresponding
columns in two matrices with identical dimensions but different data. The
problem is that the matrices contain NAs in different locations. I am using
the following code to try to calculate correlations between complete sets of
data:
#Code start
maxcol<-ncol(mat1)
for (i in 1:maxcol)
{
2011 Oct 17
2
Reading data with 'awk' - basics?
Hi,
I had a large file for which I require a subset of rows. Instead of reading
it all into memory, I use the awk command to get the relevant rows. However,
I'm doing it pretty inefficiently as I write the subset to disk, before
reading it into R. Is there a way that I can read it into an R object
without writing to disk? For example, this is what I do currently:
## write test sample file
2013 Jun 24
1
help needed with printing multiple arguments as vectors, not matrices
**
I am using the following way to get p-values from fiser exact test.
However, I do need to print for each pair the values "n00, n01, n10, n11".
How can I print that as a table and not a matrix as below along with the
p-value? Any help will be greatly appreciated
fish <- function(y, x) {n00 = sum((1-x)*(1-y)); n01 = sum((1-x)*y);
n10 = sum(x*(1-y)); n11 = sum(x*y); a =
2013 Jan 04
2
Working with Matrix
Hello again,
Let say I have 2 matrices which equal number of columns but different
number of rows like:
Mat1 <- matrix(1:20, 4, 5)
Mat2 <- matrix(1:25, 5, 5)
Now for each column 1-to-5 I need to fetch the corresponding columns
of these 2 matrices and add the corresponding elements (ignoring NA
values if any). Therefore for the 1st column I need to do:
(1+1), (2+2),...,(4+4), (NA+5)
and
2007 Jan 21
2
multiple bases to decimal (was: comparing two matrices)
Hi again,
I was contemplating the solution using base 3:
set.seed(3)
mat2 <- matrix(sample(0:2, 15, replace=T), 5, 3)
Extracting the line numbers is simple:
bases <- c(3, 3, 3)^(2:0) # or just 3^(2:0)
colSums(apply(mat2, 1, function(x) x*bases)) + 1
[1] 7 23 25 8 1
The problem is sometimes the columns have different number of levels, as in:
mat1 <- expand.grid(0:2, 0:2,
2008 Aug 01
2
Storing Matrices into Hash
Hi,
Suppose I have these two matrices (could be more).
What I need to do is to store these matrices into a hash.
So that I can call back any of the matrix back later.
Is there a way to do it?
> mat_1
[,1] [,2]
[1,] 9.327924e-01 0.067207616
[2,] 9.869321e-01 0.013067929
[3,] 9.892814e-01 0.010718579
[4,] 9.931603e-01 0.006839735
[5,] 9.149056e-01 0.085094444
2008 Mar 05
1
coxme - fitting random treatment effect nested within centre
Dear all,
I am using "coxme" function in Kinship library to fit random treatment effect nested within centre. I got 3 treatments (0,1,2) and 3 centres. I used following commands, but got an error.
> ugroup=paste(rep(1:3,each=3),rep(0:2,3),sep='/')
> mat1=bdsmatrix(rep(c(1,1,1,1,1,1,1,1,1),3),blocksize=rep(3,3),dimnames=list(ugroup,ugroup))
>
2005 Apr 29
1
na.action
Hi,
I had the following code:
testp <- rcorr(t(datcm1),type = "pearson")
mat1 <- testp[[1]][,] > 0.6
mat2 <- testp[[3]][,] < 0.05
mat3 <- mat1 + mat2
The resulting mat3 (smaller version) matrix looks like:
NA 0 0 0
0 NA 0 NA
0 0 NA 2
0 0 2 NA
To get to the number of times a '2' appears in the rows, I was