similar to: Plotting data with a fitted curve

I am trying to plot a graph but the points on the graph should be different symbols and colors. It should represent what is in the legend. I tried using the points command but this does not work. Is there another command in R that would allow me to use different symbols and colors for the points? Thank you kindly. data(mtcars) plot(mtcars$wt,mtcars$mpg,xlab= "Weight(lbs/1000)",

Hi all, I am using ggplot2 and continuing to find it very useful and pretty. However, I am trying to create some graphics for publication that would be included in an MS Word document (not my choice!) in Windows Vista. The problem is that I want to use stat_smooth() to add an fitted linear model line along with its 95% confidence band, but I cannot seem to get the confidence band in a format

Has anyone had success with producing legends to a qplot graph such that the legend is placed on the bottom, under the abcissa rather than to the right hand side ? The following doesn't move the legend: library(ggplot2) qplot(mpg, wt, data=mtcars, colour=cyl, gpar(legend.position="bottom") ) I am using ggplot2_0.8.2. Thanks in advance, Avram

Dear friends, I'm on windows, R 2.15.1 - library(ggplot2) #compiled under 2.15.2 qplot(mpg, wt, data=mtcars, colour=cyl) # directly from the qplot help Error in rename(x, .base_to_ggplot, warn_missing = FALSE) : could not find function "revalue" Is that due to a .1 lack in R All the best Troels Ring

Hi Jason, > Well, one last questions about stack plot (please forgive the lame example > below). I thought the below allow me to resize the the "title" of the > stacked histogram, but no luck. Any suggestions as to the modificaiton > necessary to get it to work? Right now the title is obscured by the plot > and my boss will be none too happy. Thanks again. Yes,

Dear List, I just googled to find out if notched box plots are possible with ggplot2, but couldn't find a answer to it. boxplot() has the option: notch = TRUE, e.g.: boxplot(mpg$hwy, notch=TRUE) My example code (taken from the net) is: require(ggplot2) qplot(class, hwy, fill=factor(year), data=mpg, geom="boxplot", position="dodge")+theme_bw() Thank you for you help!

Is there a download page for mongrel_cluster? I see that "gem install mongrel_cluster" works, but I can''t see where it''s coming from. Usually gems have some sort of project page somewhere. -- Paul Lynch Aquilent, Inc. National Library of Medicine (Contractor)

Hello, Maybe I missed something - most likely .:-( I create a gplot and then makes some changes to the plot using grid graphics functions. These changes show up on the display OK, but when I save using ggsave() the grid changes do not show up. How do I save the plot with these changes? Thanks in advance. -- View this message in context:

I have the following Data structure $ step45 : Factor w/ 2 levels $ obserror : num 6.2 6.2 5.6 6.6 6.6 ... $ Mon : num 2.2 2.0 1.0 3.2 2.0 ... $ inc.comp : num 4 5 2 5 5 5 5 5 4 4 ... all I wanted to do is plotting Mon against obserror, the colors should be by step45 and the size of the symbol should be according to inc.comp so I did this:

I am trying to draw a polar plot, which is easy enough to do in the plotrix package through the polar.plot function. However I would like to change the origin of the length vector. For instance all my length values are between 75 and 85, so instead of having the origin as 0 (the default) I'd like it to be, say, 50. Is there any way do to this in the polar.plot function, or if not is there an

Hi list, I have a question regarding post-hoc extraction of data from a two-way categorical anova. I have a categorical anova of this form: width ~ steepness + patchiness (4 steepness levels, 4 patchiness levels) This simple setup answers if for the widths I collected across different levels of steepness and patchiness significant differences can be found. Is there a way to look at these

Hello everyone, I am (happily) using ggplot2 for all my plotting now and I wondered is there is an easy way to specify xlim and ylim somewhere when using the ggplot syntax, as opposed to the qplot syntax. Eg. qplot(data=mtcars,y=wt, x=qsec,xlim=c(0,30)) <-> ggplot(mtcars, aes(y=wt, x=qsec)) + geom_point() + ??? Indeed the ggplot syntax is in general more flexible and powerful and

Dear All (probably Hadley), I am now trying to customise some plots using a bar geom. I do not want to use the default binning statistic, but rather calculate the bar heigths separately. I do manage this, but for comparison purposes I would like to have a set of plots all with the same y-axis height. But I do not seem to find out how to fix the scale of the y-axis in this case. Any tips?

Hi, I would like to make a suggestion for a small syntactic modification of FUN argument in the family of functions [lsv]apply(). The idea is to allow one-liner expressions without typing "function(item) {...}" to surround them. The argument to the anonymous function is simply referred as ".". Let take an example. With this new feature, the following call

I'm sure this exists elsewhere, but, as a trade-off, could you achieve what you want with a separate helper function F(expr) that constructs the function you want to pass to [lsv]apply()? Something that would allow you to write: sapply(split(mtcars, mtcars$cyl), F(summary(lm(mpg ~ wt,.))$r.squared)) Such an F() function would apply elsewhere too. /Henrik On Thu, Apr 16, 2020 at 9:30 AM

Hi everyone, This is about documentation for the model.frame() page. The get_all_vars() function (added in R 2.5.0) is a great addition, but the behavior of its '...' argument is different from that of model.frame() with which it is documented and this creates ambiguity. The current docs read: \item{\dots}{further arguments such as \code{data}, \code{na.action}, \code{subset}. Any

> lm2 <- function(...) lm(...) > lm2(mpg ~ wt, data=mtcars) Call: lm(formula = ..1, data = ..2) Coefficients: (Intercept) wt 37.285 -5.344 > lm2(mpg ~ wt, weights=cyl, data=mtcars) Error in eval(expr, envir, enclos) : ..2 used in an incorrect context, no ... to look in Can anyone explain why this is happening? (Obviously this is a manufactured example, but it

Dear List I have math test scores for male and female students where gender is a dummy code (female =1). I also have a variety of other demographic variables. However to begin, I want to create a very simple stripchart where female math scores are a blue circle and male scores are a red triangle. I am having difficulty using conditional statements to accomplish this. Thank you. ------

Dear R users, Does the results below make any sense? Can the the interval of the correlation coefficient be between *-1.0185* and -0.8265 at 95% confidence level? Liviu > library(boot) > data(mtcars) > with(mtcars, cor.test(mpg, wt, met="spearman")) Spearman's rank correlation rho data: mpg and wt S = 10292, p-value = 1.488e-11 alternative hypothesis: true rho is not

>library(ggplot2) >(p<- qplot(mpg, wt, data=mtcars)) What I am doing is to set color of the ticks to hide them. >grid.gedit(gPath("xaxis", "ticks"), gp=gpar(col="white")) It should be a better way to achieve the purpose. Thanks.