similar to: Construct time series objects from raw data stored in csv files

On 3/12/16 12:33 AM, peter dalgaard wrote: >> On 12 Mar 2016, at 00:05 , Mick Jordan <mick.jordan at oracle.com> wrote: >> >> This is definitely obscure but we had a unit test that called .Internal(strptime, "1942/01/01", %Y/%m/%d") with timezone (TZ) set to CET. > Umm, that doesn't even parse. And fixing the typo, it doesn't run: > >>

Hi, again i am stuck in my presentation, and i have never learn R before in my life but need this to be done, so please help me out for a favour: http://www.nabble.com/file/p20333155/kew.dat kew.dat run this in R and these comes up: Month Year Rain 1 Jan 1900 74.400000 2 Feb 1900 80.500000 3 Mar 1900 23.600000 4 Apr 1900 23.600000 5 May 1900 25.100000 6

Dear R Helpers, I am having difficulty with strptime. I wish to find the differences between two vectors of times. I have apparently no difficulty to convert the vectors to the appropriate format using strptime. But, then difftime does not calculate all the differences. Here is the code and output:- dob=strptime(as.character(datx$BDT),'%d-%b-%y'); dob$year=dob$year-100

Hello, I'm trying to use na.spline (package zoo) to fill some missing data in a time series. this works fine, however, if I apply the 'maxgap' argument, I always get the error: <------ Error in na.spline.vec(x., coredata(object.), xout = xout., ...) : attempt to apply non-function ------> I couldn't find a similar error for this case in the mailing lists and zoo vignette,

>>>>> peter dalgaard <pdalgd at gmail.com> >>>>> on Sat, 12 Mar 2016 19:11:40 +0100 writes: > OK, .Internal is not necessary to reproduce oddity in this area. I also see things like (notice 1980) >> strptime(paste0(sample(1900:1999,80,replace=TRUE),"/01/01"), "%Y/%m/%d", tz="CET") ............... >

Hello all! I have a problem with R. I try to merge data like this: structure(c(2.1785, 1.868, 2.1855, 2.5175, 2.025, 2.435, 1.809, 1.628, 1.327, 1.3485, 1.4335, 2.052, 2.2465, 2.151, 1.7945, 1.79, 1.6055, 1.616, 1.633, 1.665, 2.002, 2.152, 1.736, 1.7985, 1.9155, 1.7135, 1.548, 1.568, 1.713, 2.079, 1.875, 2.12, 2.072, 1.906, 1.4645, 1.3025, 1.407, 1.5445, 1.437, 1.463, 1.5235, 1.609, 1.738, 1.478,

Hello all! I have a problem to extract values greater that for example 1820. I try this code: x[x[,1]>1820,]->x1 Please help me! Thank you! The data structure is: structure(c(2.576, 1.728, 3.434, 2.187, 1.928, 1.886, 1.2425, 1.23, 1.075, 1.1785, 1.186, 1.165, 1.732, 1.517, 1.4095, 1.074, 1.618, 1.677, 1.845, 1.594, 1.6655, 1.1605, 1.425, 1.099, 1.007, 1.1795, 1.3855, 1.4065, 1.138, 1.514,

Hello all! I have a problem to group my data (years) in 10 years classes. For example for year year decade 1598 1590-1600 1599 1590-1600 1600 1590-1600 1601 1600-1610 --- my is like this> [1] 1598 1599 1600 1601 1602 1603 1604 1605 1606 1607 1608 1609 1610 1611 1612 [16] 1613 1614 1615 1616 1617 1618 1619 1620 1621 1622 1623 1624 1625 1626 1627 [31] 1628 1629 1630 1631 1632 1633

Thanks Don MacQueen for this reply to my initial query - please SEE MY REPLIES TO THESE IDEAS AND FURTHER INFORMATION BELOW >From: Don MacQueen [macq at llnl.gov] >Sent: 23 February 2010 21:25 >To: Jonathan Williams; r-help at r-project.org > >Subject: Re: [R] Problem with strptime generating missing values where none appear to exist > >What happens if you do all that NA

This is definitely obscure but we had a unit test that called .Internal(strptime, "1942/01/01", %Y/%m/%d") with timezone (TZ) set to CET. In R-3.1.3 that returned "1942-01-01 CEST" which, paradoxically, is correct as they evidently did strange things in Germany during the war period. Java also returns the same. However, R-3.2.4 returns "1942-01-01 CET".

Hello all! I have a problem with my data in R. When I want to plot the following data, I have a problem with y scale. The maximum value is cc. 10 degrees and in R is about 100. I use this code: fasy<-read.table("gridd1.txt",sep="\t",dec=",",header=T,row.names=1) # here are the years: x <- as.numeric(rownames(fasy)) # extract a series that you want to plot: y

OK, .Internal is not necessary to reproduce oddity in this area. I also see things like (notice 1980) > strptime(paste0(sample(1900:1999,80,replace=TRUE),"/01/01"), "%Y/%m/%d", tz="CET") [1] "1942-01-01 CEST" "1902-01-01 CET" "1956-01-01 CET" "1972-01-01 CET" [5] "1962-01-01 CET" "1900-01-01 CET"

Hi r-users,   I have this data below.  I would like to obtain the weekly rainfall sum.  That is I would like to find sum for day 1 to day 7, day 8 - day15, and so on.    year month day rain 1  1922     1   1  0.0 2  1922     1   2  0.0 3  1922     1   3  0.0 4  1922     1   4  0.0 5  1922     1   5  0.0 6  1922     1   6  0.0 7  1922     1   7  0.0 8  1922     1   8  6.6 9  1922     1   9  1.5 10

I have a problem to plot label (Year) only for significant values (in this case spoz and sneg). I use this code, but don't work with labels. library(ggplot2) ggplot(data1, aes(x = Year, y = value,fill=type,width=1))+ geom_bar(stat="identity",position="identity")+ scale_y_continuous(breaks = round(seq(-100, 100, by = 10),10))+ theme_bw() Thank you! the data used is:

Hi, [auto build test ERROR on next-20160602] url: https://github.com/0day-ci/linux/commits/Aaron-Conole/virtio-net-Advised-MTU-feature/20160603-000714 config: i386-allmodconfig (attached as .config) compiler: gcc-6 (Debian 6.1.1-1) 6.1.1 20160430 reproduce: # save the attached .config to linux build tree make ARCH=i386 Note: the

Hi, [auto build test ERROR on next-20160602] url: https://github.com/0day-ci/linux/commits/Aaron-Conole/virtio-net-Advised-MTU-feature/20160603-000714 config: i386-allmodconfig (attached as .config) compiler: gcc-6 (Debian 6.1.1-1) 6.1.1 20160430 reproduce: # save the attached .config to linux build tree make ARCH=i386 Note: the

Dear R-users, I have a complex line by xy-values (ordered by z). And I would like to get interpolated y-values on the positions of x = 0:600. How do I get the correct points? x=c(790,790,790,790,790,786,783,778,778,766,763,761,761,761,715,628,521,350,160,134,134,129,108,101,93,111,161,249,288,243,139,45,7)

Hi, Let?s consider aux1. I wanted to order its data considering its first column as the index > aux1[1:4,] V1 V2 V3 V4 V5 V6 1 0.08506724 150 1956 15.08 233.82 463.295 14 2 0.76205323 203 1922 15.35 218.74 463.295 14 3 0.86274890 195 1835 12.54 203.39 463.295 14 4 0.37940715 152 1567 24.73 190.85 463.295 14 > aux2 <-- aux1[order(aux1[1:4,1]) , ] > aux2

https://bugzilla.mindrot.org/show_bug.cgi?id=1921 Bug #: 1921 Summary: [Patch] memory leak in sftp-client.c Classification: Unclassified Product: Portable OpenSSH Version: -current Platform: All OS/Version: All Status: NEW Severity: trivial Priority: P2 Component: sftp AssignedTo:

Dear List, I am trying to solve a problem by the neural network method(library: nnet). The problem is to express Weight in terms of Age , Sex and Height for twenty people. The data frame consists of 20 observations with four variables: Sex, Age, Height and Weight. Sex is treated as a factor, Age and Weight are variables normalized to unity, as usual. I wanted to construct a neural network, and so