similar to: do.call vs. lapply for lists

Greetings, I'm learning R and I'm stuck on a basic concept: how to specify a logical condition once and then perform multiple transformations under that condition. The program below is simplified to demonstrate the goal. Its results are exactly what I want, but I would like to check the logical state of gender only once and create both (or any number of) scores at once.

Hi All, I searched around to find the number of R packages currently available, but didn't find anything, so I choose all repositories & told it to install. The list contained about 2,856 (correcting roughly for those installed). But the list includes repetitions such as 19 names that begin with "bvbovine". Selecting only CRAN and CRAN(extras) I get 1,344. Is there an easier

Hi All, I'm using the Hmisc summarize function and used list instead of llist to provide the by variables. It generated an error message. Is this a bug, or do I misunderstand how Hmisc works with lists? The program below demonstrates the error message. Thanks, Bob x<-1:8 group <- c(1,1,1,1,2,2,2,2) gender<- c(1,2,1,2,1,2,1,2) mydata<-data.frame(x,group,gender)

Dear HelpeRs, I'm confused about the role of quotes around package names on the library and detach functions. Books on R use both approaches: library(Hmisc) describe(mydata) detach(package:Hmisc) and library("Hmisc") describe(mydata) detach("package:Hmisc") The help file for detach says "quoted or unquoted" and the help file for library says about the

Hi All, I'm learning JGR 1.4-15 with R 2.4.1 in Windows XP (all patches applied). JGR looks great but I'm having trouble getting the data editor to save my results. I don't see anything in R-help about it. Here are the steps I followed: 1. I chose "Tools>Object Browser" & double-clicked on a data frame, "mydata". 2. A spreadsheet editor popped up and

Hi All, I'm perplexed by the way the unclass function displays a factor whose labels have been swapped with the relevel function. I realize it won't affect any results and that the relevel did nothing useful in this particular case. I'm just doing it to learn ways to manipulate factors. The display of unclass leaves me feeling that the relevel had failed. I've checked three books

Dear R-Helpers, I suspect I'm about to ask a FAQ, but I haven't been able to find an answer in the FAQ, AItR or an R Site Search. When I look at the methods of summary (below) it says, "Non-visible functions are asterisked". I looked at the help file for summary.princomp, which did not comment on it being non-visible. I ran its help file example, which printed visible output. I

Hi Folks, SAS Institute is adding official support for R: http://support.sas.com/rnd/app/studio/Rinterface2.html Cheers, Bob ========================================================= Bob Muenchen (pronounced Min'-chen), Manager, Research Computing Support U of TN Office of Information Technology Stokely Management Center, Suite 200 916 Volunteer Blvd., Knoxville, TN

Hi All, I'm working on a class example that demonstrates one way to deal with factors and their labels. I create a function called myLabeler and apply it with lapply. It works on the whole data frame when I subscript it as in lapply( myQFvars[ ,myQFnames ], myLabeler ) but does not work if I leave the [] subscripts off. I would appreciate it if anyone could tell me why. The program below

Hi All, I'm using the subset function to select a list of variables, some of which are contiguous in the data frame, and others of which are not. It works fine when I use the form: subset(mydata,select=c(x1,x3:x5,x7) ) In reality, my list is far more complex. So I would like to store it in a variable to substitute in for c(x1,x3:x5,x7) but cannot get it to work. That use of the c function

Hi All, If I need to stack two data frames, I can use rbind, but it requires that all variables exist in both sets. I can make that happen, but other stat packages would figure out where the differences were, add the missing variables to each, set their values to missing and stack them. Is there a more automatic way to do that in R? Below is an example program. Thanks, Bob # Top data frame has

Hi All, We have all had to face skeptical colleagues asking if software made by volunteers could match the quality and accuracy of commercially written software. Thanks to the prompting of a recent R-help thread, I read, "R: Regulatory Compliance and Validation Issues, A Guidance Document for the Use of R in Regulated Clinical Trial Environments (http://www.r-project.org/doc/R-FDA.pdf).

Hi All, I'm fiddling with an program to read a text file containing periods that SAS uses for missing values. I know that if I had the original SAS data set instead of a text file, R would handle this conversion for me. Data frames do not allow missing values in their indices but vectors do. Why is that? A search of the error message points out the problem and solution but not why they

Dear R-Helpers, I'm fiddling with my .Rprofile in Windows XP & R 2.7.0 Beta. I prefer to manually save my workspace but automatically save my command history via the .Rprofile. That is working fine once I found that "utils::" was required before the loadhistory & savehistory functions. What I would like to do is add a separator line with a date between the histories of each

Hi All, I've been successfully using the with function for analyses and the transform function for multiple transformations. Then I thought, why not use "with" for both? I ran into problems & couldn't figure them out from help files or books. So I created a simplified version of what I'm doing: rm( list=ls() ) x1<-c(1,3,3) x2<-c(3,2,1) x3<-c(2,5,2)

I am using spss.get to import an SPSS database "Data.sav", created with SPSS 14 : df1 <- spss.get("C:/temp/Data.sav" , lowernames=TRUE, datevars = c("dateinte")) I am getting this warning. I get the same warning with read.spss. Warning message: C:/temp/Data.sav: Unrecognized record type 7, subtype 16 encountered in system file This is a stupid

Hi Do you know some articles, papers, something than tell about comparision between R and others softwares statisticals. Thank You Ricardo -- View this message in context: http://www.nabble.com/Articles-about-comparision-between-R-and-others-softwares-tp19338210p19338210.html Sent from the R help mailing list archive at Nabble.com.

Hi. There was an interesting thread about a year ago, called 'Command equivalent of rgui "File, Save to File"?' (http://tolstoy.newcastle.edu.au/R/e2/help/06/09/0553.html) started by Michael Prager, and contributed to by Duncan Murdoch (I didn't notice anything beyond the four entries they posted). The question was how to replicate programmatically the "Save to

Dear R-Helpers, Why does R show character missing values in vectors as NA and when stored in a data frame as <NA>? I've searched but did not find an explanation. Thanks, Bob > gender <- c("f","f","f",NA,"m","m","m","m") > gender [1] "f" "f" "f" NA "m" "m"

I am looking for the most efficient way to replace all occurrences of NaN in a data frame with NA. I can do this with a double loop, but it seems that there should be a higher level and more efficient way. With is.na, I could use ifelse, but if.nan seems not to have similar capabilities. TIA, Jon Peck Jon K. Peck jkpeck@aya.yale.edu [[alternative HTML version deleted]]