similar to: Hmisc summary.formula.reverse export problem

R users, I'm trying to set a column width to one of the columns in a latex table (using Hsmic package, latex function). My intention is to get \begin{tabular}{lp{1.2in}llllll}\hline\hline Here's an example ####### R code ######### DF <- data.frame(Titanic) DF$long <- paste("This is a veeeeeeeeeeryyyyyyyyyy long line") DF <- DF[, names(DF)[c(6,1:5)]] library(Hmisc)

Hello, I'm producing text from my data.frame using cat function. I would like to use for loop to export each column in my data.frame into separate text files. Here is the example code r <- t(Indometh) for (i in 1:ncol(r)) { cat("Some text,", "\n") cat("\n") cat("More text, More text, More text") cat("\n")

I have a text file similar to this (separated by spaces): x <- "DF12 This is an example 1 This DF12 This is an 1232 This is DF14 This is 12334 This is an DF15 This 23 This is an example " and I know the field lengths of each variable (there is 5 variables in this data set), which are: varlength <- c(2, 2, 18, 5, 18) How can I import this kind of data into R, using the varlength

R users, I have a simple lapply question. g <- list(a=1:3, b=4:6, c=7:9) g <- lapply(g, function(x) as.data.frame(x)) lapply(g, function(x) cbind(x, var1 = rep(names(g), each=nrow(x))[1:nrow(x)])) I get $a x var1 1 1 a 2 2 a 3 3 a $b x var1 1 4 a 2 5 a 3 6 a $c x var1 1 7 a 2 8 a 3 9 a And I would like to have $a x var1 1 1 a 2 2 a 3 3 a

R-users, Is there a function for ceiling to the nearest ten? a <- 1:10*4 a [1] 4 8 12 16 20 24 28 32 36 40 The resulting vector should look like this ("ceiling to the nearest ten") [1] 10 10 20 20 20 30 30 40 40 40 Thanks in advance Lauri

Dear list, I tried to find a solution for this problem from the archives but couldn't find any. I would like sample sequence of ten days from vector d d <- seq(as.Date("2007-02-12"), as.Date("2008-08-18"), by="days") so that the days follow each other (sample(d, 10) is not the appropriate solution). Any ideas? Best regards, Lauri

Hi R-users, Following this post http://tolstoy.newcastle.edu.au/R/help/06/06/28965.html , how do I get last two rows (or six or ten) by id group out of the data frame? Here the example gives just the last row. Sincere thanks, Lauri [[alternative HTML version deleted]]

Hello, I have difficulties combining boxes and lines in plot legend. I searched previous R-posts and found this (with no solution): http://tolstoy.newcastle.edu.au/R/help/06/07/30248.html. Is there a way to avoid boxes behind the line legends? x1 <- rnorm(100) x2 <- rnorm(100, 2) hist(x1, main = "", col = "orange",ylab = "density", xlab = "x", freq =

Hi R-users, I have a simple question for R heavy users. If I have a data frame like this dfr <- data.frame(id=1:16, categ=rep(LETTERS[1:4], 4), var3=c(8,7,6,6,5,4,5,4,3,4,3,2,3,2,1,1)) dfr <- dfr[order(dfr$categ),] and I want to score values or points in variable named "var3" following this kind of logic: 1. the highest value of var3 within category (variable named

Hi R-users, I have a dataset like this: kuvaaja kuva yhteispisteet Hannu isokala 8 Hannu kaapin alta löytynyt 2 Hannu kaapin alta löytynyt 2 8 Hannu limamikko 1 Hannu maukasta marmeladia 8 Hannu skrinnareita 4 Hate madekoukkujen suojelupyhimys 3 Hate matka aikaan joka ei enää palaa 3 Hate munat puoliks padassa 6 Hate pyynikki 2 Hate vailla armeerausta 2

Hi, I have a data.frame like this: y <- rnorm(60) lev <- gl(3,20, labels=paste("lev", 1:3, sep="")) date1 <- as.Date(seq(ISOdate(2007,9,1), ISOdate(2007,11,5), by=60*60*24)) date1 <- date1[-c(3,4,15,34,38,40)] df <- data.frame(lev=lev, date1=date1, y=y) I would like to produce a new data.frame with missing days in df$date1 in each df$lev, like this: lev

Hi R-users, What is the best way to achieve a table which contains all days and months between years 2007-2020? I would like to calculate number of days in each month within those years (to data frame). Regards, Lauri [[alternative HTML version deleted]]

Hi, Suppose I have a data.frame like this Lines <- "var1 var2 var3 var4 var5 var6 0 2 1 2 0 0 2 3 7 6 0 1 1.5 4 9 9 6 0 1.0 6 10 22 3 3 " DF <- read.table(textConnection(Lines), skip=1) names(DF) <- scan(textConnection(Lines), what = "", nlines = 1) How do I find the

R users, I have a vector of dates days <- seq(as.Date("2007/1/1"), as.Date("2008/1/31"), "days") and I would like to have week numbers from 1 to 52 for each year. How do I do that? Now I get 00-53 using format(days, "%W") > range(format(days, "%W")) [1] "00" "53" I have read "Date and Time Classes in R" (R

R users, My intention is to take factors out of DF, create list of tables and export these tables separately using write.table or sink function. write.table writes tables out as DF:s, should I use sink instead? Here is my example: a <- data.frame( indx = 1:20, var1 = rep(c("I20", "I40", "A50", "B60"), each=5),

Hi R-users, How do I calculate a number of NA's in a row of every second column in my data frame? As a starting point: dfr <- data.frame(sapply(x, function(x) sample(0:x, 6, replace = TRUE))) dfr[dfr==0] <- NA So, I would like to count the number of NA in row one, two, three etc. of columns X1, X3, X5 etc. Thanks in advance Lauri [[alternative HTML version deleted]]

Hi R-users, I have a list a <- list(one=matrix(rnorm(20), 5, 4), two=matrix(rnorm(20, 3, 0.5),5,4)) How to add rowSums (calculated using lapply) to corresponding matrix in this list lapply(a, function(x) rowSums(x)) ?? -Lauri

Hi, I installed R on USB-drive, but when I run Rgui.exe from bin folder, I get this error: ----------------------- R version 2.10.1 (2009-12-14) Copyright (C) 2009 The R Foundation for Statistical Computing ISBN 3-900051-07-0 R is free software and comes with ABSOLUTELY NO WARRANTY. You are welcome to redistribute it under certain conditions. Type 'license()' or 'licence()' for

Hi, I'm trying to read several Excel sheets from an Excel file into a list. I'm using read.xls from package 'gdata'. I would like to know how I can check the number of sheets before the loop (in the example below) so that I could adjust the loop counter? Any suggestions? DF.list <- list() for (i in 1:4) { DF.list[[i]] <- read.xls("sample_file.xls", sheet=i,

R users, I'm at a loss with a problem considering running .tex files produced by Sweave. When I run (R 2.7.0): --------------------------------------------------- #Taken from ?Sweave testfile <- system.file("Sweave", "Sweave-test-1.Rnw", package = "utils") ## enforce par(ask=FALSE) options(device.ask.default=FALSE) ## create a LaTeX file Sweave(testfile)