similar to: Vector indexing question

Hello! I am trying to read Ferret index files from Windows machine on my Mac G5 Leopard machine, but the following returns nil: Ferret::Index::IndexReader.new( index_paths ) Should this work? Are index files guaranteed to be platform independent or not? Is there any problem if files (top direectory) are renamed? izidor P.S. I can create the index myself and then everything works.

How to generate a new factor variable by two other factor variables? For example, if I have two factor variables, factorA and factorB, factorA factorB 0 0 0 0 1 0 0 1 1 1 Is there a simple way to generate a new 4-levels factor variable as factorC factorA factorB 0 0 0 0 0 0 1 1 0 2 0 1

Hi, I'm trying to do a linear regression style one-way ANOVA using some data in a data frame, and (perhaps because I am still relatively unfamiliar with both R and statistics) what I thought I should do was to make the data frame into a factor. By that I mean that I have a data frame whose column labels are the levels of the factor, and the values in the frame are numeric values for the

This morning I tried to see if I could find the r-help mailing list on Google Groups, which has an interface that I like. I found three Google Groups ("The R Project for Statistical Computing", "rproject", and "rhelp") but none of them are connected to the r-help list. Is there perhaps some reason why it wouldn't be a good thing for there to be a connected

Hi, everybody, 3 questions about R-square: ---------(1)----------- Does R2 always increase as variables are added? ---------(2)----------- Does R2 always greater than 1? ---------(3)----------- How is R2 in summary(lm(y~x-1))$r.squared calculated? It is different from (r.square=sum((y.hat-mean (y))^2)/sum((y-mean(y))^2)) I will illustrate these problems by the following codes:

I've made some normal plots of my data using qqplot, and now I would like to fit a line to the points on the plot and check the correlation coefficient to have a more objective measure of how straight the line is. Is there a simple way of doing that? (I'm still pretty new to R.) Thanks, --Paul -- Paul Lynch Aquilent, Inc. National Library of Medicine (Contractor)

Suppose you have a vector of data in x and response values in y. How do you plot together both the points (x,y) and the curve that results from the fitted model, if the model is not y ~ x, but a higher order polynomial, e.g. y~poly(x,2)? (In other words, abline doesn't work for this case.) Thanks, --Paul -- Paul Lynch Aquilent, Inc. National Library of Medicine (Contractor)

Hi, I've downloaded R-2.6.2-win32.exe (base) from two CRAN sites (http://mirrors.ibiblio.org/pub/mirrors/CRAN/ and http://lib.stat.cmu.edu/R/CRAN/) and for both of those sites the expected MD5 hash is reported to be: ed512872818707f27ca05f08be7363c2 *R-2.6.2-win32.exe (See, for example, http://lib.stat.cmu.edu/R/CRAN/bin/windows/base/md5sum.txt). However, when I compute the MD5

Is there a download page for mongrel_cluster? I see that "gem install mongrel_cluster" works, but I can''t see where it''s coming from. Usually gems have some sort of project page somewhere. -- Paul Lynch Aquilent, Inc. National Library of Medicine (Contractor)

How do I completely remove the first column? (x <- matrix(c(1, 44, 124, 80, 254, 70, 190, 0, 2, 35, 110, 70, 240, 73, 216, 0, 3, 41, 114, 80, 279, 68, 178, 0, 4, 31, 100, 80, 284, 68, 149, 0, 5, 61, 190, 110, 315, 68, 182, 1, 6, 61, 130, 88, 250, 70, 185, 0, 7, 44, 130, 94, 298, 68, 161, 0, 8, 58, 110, 74, 384, 67, 175, 0, 9, 52, 120, 80, 310, 66, 144, 0, 10, 52, 120, 80, 337, 67, 130, 0, 11,

dear all, I want to make a dotplot with ratings from Items in 6 ItemsGroups. I reordered the items by rating within each group. I plotted the items by rating conditional on ItemGroup. The ordering works as I wanted but my y-aches labels (items) within each ItemGroup are now unequally spaced, e.g., in some panels there is a gap between one lower rated item and the next higher, to give a picture

I think I posted this patch before, but it looks like it was in December 2012 (!). 1/1 libxl: introduce an option for disabling the non-O_DIRECT workaround Ideally it would go into 4.4, at least. Provided the corresponding qemu part has gone into qemu-xen, which I think it has. Can anyone confirm ?

Dear R Users, I have a couple of proto objects like: wedge <- proto(expr={ start.year <- 2008 end.year <- 2050 }) star.rating <- wedge$proto( star = c(4, 5, 8, 10), gain = c(0, .3, .5, .7), cost = c(0, 2100, 4000, 7500), star.rating <- function(., year) 6.0, setup = function(.){ .$cost.for.star <- approxfun(.$star,

Can someone tell me what I''m doing wrong? I''ve spent way too much time on this -------------------------------------------------------------------------------------- class Picture < ActiveRecord::Base has_many :ratings, :after_add => :increment_rating, :after_remove => :decrement_rating def increment_members(rating) self.rating += rating.amount save!

This is the code if !params[:ratings].nil? params[:ratings].each_key do |r| @selected_ratings << r @movies << Movie.where(''rating = :rating'', :rating => r) @sort = params[:sort] end elsif @selected_ratings = @all_ratings @movies = Movie.order(@sort) @sort = params[:sort] end This is the error You have a nil object

I am looking for hints on how to estimate ratings for competitors in an ongoing pairwise competition using R... my particular area of interest being the game of Go, but the idea of identifying ratings (on a continuous scale) rather than relative rankings seems easily generalized to other competitions so I thought someone might be studying something related already. I presume the rating of a

Hi, I have a mysql table with fields userid,track,frequency e.g u1,1,10 u1,2,100 u1,3,110 u1,4,200 u1,5,120 u1,6,130 . u2,1,23 . . where "frequency" is the number of times a music track is played by a "userid" I need to turn my 'frequency' table into a rating table (it's for a recommender system). So, for each user, I need to categorise the frequency of tracks

Okay, this *should* be easy, but it isn''t, although I reserve the right to smack myself upside the head if it is: Assume that a smart has_many ratings, and a rating belongs_to a smart (the models are fine). Each rating has a column smart_id. Each smart, then, has many ratings, with a column called "rating" that is an int (1-10). I want to find, say, the ten smarts with

I'm an R newbie but recently discovered the ggplot2 and reshape packages which seem incredibly useful and much easier to use for a beginner. Using the data from the IMDB, I'm trying to see how the average movie rating varies by year. Here is what my data looks like: > ratings <- read.delim("groomed.list", header = TRUE, sep = "|", comment.char = "")

I am new to RoR. The problem i am facing is that that i have a few check box and initially when i run my app for the first time i want them all to be selected while for every next time i want it to have the last checked boxes checked. To do this, In my controller i have @all_ratings = Movie.all_ratings @selected_ratings = [] if !params[:ratings].nil?