similar to: Pagination_links without "?page=" but with params[:id]

Hi Guys, I am trying to paginate the results from a search. When I use actual constants in the search conditions, it works fine: def query @k2_result_pages, @k2_results = paginate (:k2_results, :conditions => [''e_date >= ? AND e_date <= ?'', ''2006-07-12'', ''2006-08-12''],

I just installed version 1.1.4 and it seems like I started having problems with the pagination_links method. When I call the method using something like this (using the :params option--and this seems to be the problem), <%= pagination_links @todo_pages, :params => params %> then it duplicates part of the controller in the generated url. For example, before one of my paginator links

Hello, I have 2 tables table colors : +----------------------+ | id | user_id | name | +----------------------+ | 1 | 1 | test1 | | 2 | 2 | test2 | | 3 | 3 | test3 | +----------------------+ table users : +----------------------+ | id | enabled | name | +----------------------+ | 1 | 1 | bob | | 2 | 1

Simple question. Is it possible to generate a link like <a href="http://www.google.com" target="_blank" >google</a> with the link_to function ? Thanks

I intend to override pagination_links method. I added following lines of code in application_helper.rb module ActionView module Helpers def pagination_links(paginator, options={}, html_options={}) raise("boom!!") end end end But my code is not executing my code. The view is still using the method pagination_links from rails. What''s the correct way to override

my pagination_links seems to auto generate the links using the current controller, action and id. The page they''re appearing on however have a friendly url I have created. I want to be able to make pagination urls generated by pagination_links "user friendly" as well so that they match my current naming convention.....i know there must be a way to do this....any ideas?

(To preface this - you can just imagine I am making the cookbook from the Rolling with Ruby on Rails tutorial) I have made a customer list view (list.rhtml), so that I could include attributes from multiple database tables. This works fine, however, the list page no longer paginates (i.e. does limit the item list to 10 items at a time, with a 1, 2, 3... links at the bottom) I am trying to

I am trying to do a simple search by product name. The first page returns fine, but when I try to go to any other pages of the search results, I lose the original search parameters from my search form and get NilClass errors. Here is the code in my controller: namesearch = "%" + params[:name].strip + "%" @product_pages, @products = paginate :product,

How : <a href="/show/all">All</a> Could become : <a href="/show/all" title="Show All" >All</a> This is possible with the standdard link_to function ?

Hello, How to style the pagination links ? I simply try to set the number of the current page to another color. But I have the "..." also colored. Paginator have options to style ? Thanks

I''m trying to figure out how to change the order of a list view and it''s obvious to me that I don''t understand what I get from a simple scaffold to know enough to alter it. If someone would be so kind to tell me what this means ... def list @placment_pages, @placements = paginate :placements, :per_page => 10 end @placement_pages, # I am guessing that this

because I am a grasshopper... Now that I can sort my ''list''...is there a logical way of not repeating myself to having essentially the same list view with multiple sorts? i.e. def list_cl # ordered by clients last name @placement_pages, @placements = paginate( :placements, :include => [:client], :order_by =>

This post addresses URLs generated by Ruby on Rails from a human factors point of view. Allow me to use Hieraki as an example. Hieraki is a great application. It was one of my first introductions to the power of Ruby on Rails. Scenario: When I navigated to Chapter 1 of a book the URL in my address bar was http://www.library.com/read/chapter/6. This inconsistancy ("Am I on Chapter 1 or

I want append custom query parameters to my pagination links, like ?page=1&foo=bar. I can''t quite figure out how to do this with the pagination_links helper, although I believe the API says you should be able to: pagination_links(paginator, options={}, html_options={}) options are: :params: any additional routing parameters for page URLs Has anyone tried this? thanks, jeff --

I''m trying to create a paginated list that will take note of the "end_date" field in my table. This is what I have: @post_pages, @posts = paginate(:posts, :per_page => 10, :order_by => ''end_date'') in the controller. And for the view: <h1>Posts ending soon</h1> <ul><% for post in @posts do %> <strong>Post Title:

Hey all, I''m using a simple search function. It''s working great except for foreign keys. I have one table pets (id,name,owner_id) and another table people(id,name) owner_id being a foreign key of pet pointing to people name. here it is on the pet controller: @paginator, @pets= paginate(:pets, :conditions =>["name OR owner_id like

I''ve been working on an application lately that has a lot of advanced search and filtering functionality (with ranges and substring searches for each attribute). Despite being a pretty common use case, this isn''t supported particularly well by any framework I''ve used, including Rails. I''d like to fix that. :) Right now, my major pet peeves are: 1. Long,

Ahoy, I checked the API and did some forum searches but didn''t find anything good on table sorting. Is there a "railish" way to do this? My current method really is lacking (i''m on like rails day 2) <th><%= link_to ''Name'', :action => ''list'', :order => ''name'' %></th>

Hi there, Is there a neat and easy way to implement pagination with letters rather than numbers eg : A B C D ... Z Rob

> Unfortunately I still get the same error. Here is my code now (the > commented line works): > > def list > @upload_pages, @uploads = paginate(:uploads, :per_page => > 20, :order > => ''id'') > # @upload_pages, @uploads = paginate(:uploads, :per_page => 20) > end You may have an older version, try using the order_by clause