Displaying 20 results from an estimated 1000 matches similar to: "gam parameter predictions --Sorry for double posting"
2010 Jun 25
2
Assigning variable value as name to cbind column
Hi all,
I have this (non-working) script:
dataTest <- data.frame(col1=c(1,2,3))
new.data <- c(1,2)
name <- "test"
n.row <- dim(dataTest)[1]
length(new.data) <- n.row
names(new.data) <- name
cbind(dataTest, name=new.data)
print(dataTest)
and would like to bind the new column 'new.data' to 'dataTest' by
using the value of the variable 'name' as
2010 Feb 18
3
svm regression
Hi,
I am trying to use svm for regression data.
this is how my data looks like:
>dataTrain
x y z
1 4 6
2 5 4
3 7 5
>classTrain
a
2
3
4
>dataTest
x y z
1 7 2
2 8 3
>classTest
a
3
4
5
building the model
model<-svm(dataTrain,classTrain,type="nu-regression")
pred <- predict(model, dataTest)
> pred
1 2
3.008842 3.120078
I
2017 Nov 20
2
samba 4 ad member - idmap = ad for machine accounts
Hi all,
I have exactly the same problem as the OP and tried the solution below, but
I still get the error:
'Username IUCNNL\PC050$ is invalid on this system'. Should I map
useraccount, enable Guest account, chang eunix directory permissions or
things like that?
Problem:
My Windows 10 computers' machine accounts cannot acces shares on a domain
member (samba 4.6 , id map = ad, centos
2009 Apr 22
1
Multiple imputations : wicked dataset ? Wicked computers ? Am I cursed ? (or stupid ?)
Dear list,
I'd like to use multiple imputations to try and save a somewhat badly
mangled dataset (lousy data collection, worse than lousy monitoring, you
know that drill... especially when I am consulted for the first time
about one year *after* data collection).
My dataset has 231 observations of 53 variables, of which only a very
few has no missing data. Most variables have 5-10% of
2009 Nov 25
1
Sampling dataframe
Hi,
I have a table like that:
> datatest
var1 var2 var3
1 1 1 1
2 3 1 2
3 8 1 3
4 6 1 4
5 10 1 5
6 2 2 1
7 4 2 2
8 6 2 3
9 8 2 4
10 10 2 5
I need to create another table based on that with the rules:
take a random sample by var2==1 (2 sample rows for example):
var1 var2 var3
1 1
2011 Feb 23
0
svm(e1071) and scaling of weights
I expected, that I will get the same prediction, if I multiply the
weights for all classes with a constant factor, but I got different
results. Please look for the following code.
> library(e1071)
> data(Glass, package = "mlbench")
> index <- 1:nrow(Glass)
> testindex <- sample(index, trunc(length(index)/5))
> testset <- Glass[testindex, ]
> trainset <-
2010 Sep 30
0
Problem comparing lme objects with anova using do.call
Hi all,
I am running some linear mixed models for longitudinal data using the nlme
package. Part of the code I've developed tests for differences among models
using the anova function, but I can't simply pass the corresponding lme
objects as parameters to the anova function because some of the models do
not converge and others are retained for comparison only if certain criteria
are met.
2007 Oct 13
2
the use of the .C function
Dear All,
could someone please shed some light on the use of the .C or .Fortran function:
I am trying load and running on R the following function
// psi.cpp -- psi function for real arguments.
// Algorithms and coefficient values from "Computation of Special
// Functions", Zhang and Jin, John Wiley and Sons, 1996.
//
// (C) 2003, C. Bond. All rights reserved.
//
//
2011 Aug 15
2
plotting segments only and in color
Hello,
I've a question concerning the display of interval data.
A sample dataset where X is an interval between Xa and Xb
which should be displayed:
Y=c(15,14,23,18,19,9,19,13)
Xa=c(17,22,21,18,19,25,8,19)
Xb=c(22,22,29,34,19,26,17,22)
X = (Xa+Xb)/2
It's easily possible to plot the mean of the interval like:
plot(X,Y)
afterwards I can create lines for the interval with:
2011 Mar 06
4
sorting & subsetting a data.frame
Dear all
This may be obvious, but I cannot get it working. I'm trying to subset
& sort a data frame in one go.
x <- iris
x$Species1 <- as.character(x$Species)
##subsetting alone works fine
with(x, x[Sepal.Length==6.7,])
##sorting alone works fine
with(x, x[order(Sepal.Length, rev(sort(Species1))),])
##gets subsetted, but not sorted as expected
with(x, x[(Sepal.Length==6.7) &
2011 Nov 22
5
x, y for point of intersection
Hi everyone,
?
I am trying to get a point of intersection between a
polyline and a straight line ?.. and get the x and y coordinates of this point.
For exemplification consider this:
?
?
set.seed(123)
?
k1 <-rnorm(100, mean=1.77, sd=3.33)
?k1 <- sort(k1)
q1 <- rnorm(100, mean=2.37, sd=0.74)
q1 <- sort(q1, decreasing = TRUE)
plot(k1, q1, xlim <- c((min(k1)-5),
2012 Feb 09
1
Constraint on one of parameters.
Dear all,
I have a function to optimize for a set of parameters and want to set a
constraint on only one parameter. Here is my function. What I want to do is
estimate the parameters of a bivariate normal distribution where the
correlation has to be between -1 and 1. Would you please advise how to
revise it?
ex=function(s,prob,theta1,theta,xa,xb,xc,xd,t,delta) {
expo1=
2009 Sep 14
9
ActiveRecord::StatementInvalid (invalid date) with Oracle
Hello all. I am a novice Ruby on Rails programmer, starting my first
project using a legacy Oracle 10 database. Using ''reverse_scaffold'' I
have created the models/controllers/views for my existing Oracle
tables.
All seems to work well, using /model/index, /model/show for most of my
tables, *except* when one of the tables contains a Oracle ''date''
column, for
2017 Nov 20
0
samba 4 ad member - idmap = ad for machine accounts
On Mon, 20 Nov 2017 07:59:14 -0700 (MST)
tomict via samba <samba at lists.samba.org> wrote:
> Below is relevant info (I think) for my case
>
> What I did/tried:
> -With ADUC (WS 2012) I added NIS domain 'samdom' to the Unix
> attributes of users, groups, and also to computers (is the latter
> nesecary?) -I test the connection to the shares as system user on the
2006 Aug 02
1
RE
Hi any,
Can some please detail me the createX command in bayesm package?
To make things easy for you to help me, let me put forward my problem
Suppose I have 3 covariates (say X matrix) and my Y has 3 categories say
(1,2,3). Now from the CreateX I understand that the data matrix say 'Xa' must
be of dimension n* (naxp), where 'na' is the number of variables and 'p' is
2009 Mar 20
1
Mean-replacing NAs in a 3d array
Hi all
I have a 3d array containing missing values.
> Xa
, , 1
[,1] [,2]
[1,] 1 3
[2,] NA 4
, , 2
[,1] [,2]
[1,] 5 7
[2,] NA NA
, , 3
[,1] [,2]
[1,] 9 11
[2,] 10 12
I want to replace the missing values with the mean, but the mean of each
'page' in the array (wrong terminology I'm sure). So - for the array
above - [2,1,2] and
2007 Aug 16
3
Urgent Help needed
Dear All:
Urgent help is needed.
I have a data set in matrix format of three columns: X, Y and index of four groups (1,2,3,4). What I need to do is the following;
1- How I can subtract the sample mean of each group indexed 1,2,3,4 from the
corresponding data values of this group and create new columns say X-sample mean
and Y-sample mean? I tried to use the "tapply" but
2011 Oct 10
4
correlation matrix
Hello Gurus
I have two correlation matrices 'xa' and 'xb'
set.seed(100)
d=cbind(x=rnorm(20)+1,
x1=rnorm(20)+1,
x2=rnorm(20)+1)
d1=cbind(x=rnorm(20)+2,
x1=rnorm(20)+2,
x2=rnorm(20)+2)
xa=cor(d,use='complete')
xb=cor(d1,use='complete')
I want to combine these two to get a third matrix which should have half
values from 'xa' and half
2012 Jul 10
3
fill 0-row data.frame with 1 line of NAs
Dear all
Is there a simpler method to achieve the following: When I obtain an
empty data.frame after subsetting, I need for it to contain one line
of NAs. Here's a dummy example:
> (.xb <- iris[ iris$Species=='zz', ])
[1] Sepal.Length Sepal.Width Petal.Length Petal.Width Species
<0 rows> (or 0-length row.names)
> dim(.xb)
[1] 0 5
> (.xa <-
2012 Jun 21
4
convert 'character' vector containing mixed formats to 'Date'
Dear all
I have a 'character' vector containing mixed formats (thanks Excel!)
and I'd like to translate it into a default "%Y-%m-%d" Date vector.
x <- c("1/3/2005", "13/04/2004", "2/5/2005", "2/5/2005", "7/5/2007",
"22/04/2004", "21/04/2005", "20080430", "13/05/2003",