similar to: Subset

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sorry, I don't undersatnd what happens Annee_O;Id_Essai;Id_Rep;Id_Geno;Id_Cult;Lib_Geno;St_Cult;Id_Par;X_Par;Y_Par;Id_Cara;Surf_O;Val_O;Ori_O;Stade_O;Date_O;Id_Bloc;Id_TrT1 2004;1006003;1;55094;1012988;XF 338/1;;1;1;1;137;;9.4;P;;09/09/2004;1;0 2004;1006003;1;55094;1012988;XF 338/1;;1;1;1;193;;189;P;;01/01/2004;1;0 2004;1006003;1;55094;1012988;XF 338/1;;1;1;1;103;14.95;85;P;;09/09/2004;1;0

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I have a data frame whose first colum contains the names of the variables and whose second colum contains the values to assign to them: : kkk <- data.frame(vars=c("var1", "var2", "var3"), vals=c(10, 20, 30), stringsAsFactors=F) If I do : assign(kkk$vars[1], kkk$vals[1]) it works : var1 [1] 10 However, if I try with mapply

Hello Gabriel, I recommend you use gpupdate /force on the windows command line after login. The results of above command can be checked afterwards with the "gpresults" command. Can be you have an permission problem on your samba server. Only skimmed ofver the thread but did you try samba-tools ntacl sysvolreset on your samba server? achim~ Am 22.05.2015 um 12:08 schrieb Gabriel

2015-05-22 13:32 GMT+02:00 Gabriel Franca <gabriel.franca at gmail.com>: > > I found it strange more and something I have already noticed a while. > > No GPO is applied when the User is the "Domain Users", so I wonder if I'm > doing something wrong or I have to change something. > > I believe the "Domain Users" are not allowed to change the

How does one remove a column from a data frame when the name of the column to remove is stored in a variable? For Example: colname <- "LOT" newdf <- subset(olddf,select = - colname) The above statement will give an error, but thats what I'm trying to accomplish. If I had used: newdf <- subset(olddf,select = - LOT) then it would have worked, but as I said the column

LDAP can be use in clear text mode or with start_tls. There is still LDAPS which can also be used. Any of these should be used to authenticate users as LDAP[s] is not meant to authenticate anything, it's a DB. Kerberos should be used for authentication as it is meant for that purpose and could grant your users possibility to have SSO. More secure for admins, more simple for users... I have

Hello Gabriel, Am 22.05.2015 um 15:23 schrieb Gabriel Franca: > Good morning people, > > I make the case that Achim Gottinger passed. > > samba-tool ntacl sysvolreset and received the following information: > Segmentation fault (core of the recorded image) > > then sent a samba-tool ntacl sysvolcheck and received the following: > ERROR (<type

Hi all, I still have problems with the predict function by setting up the values on which I want to predict ie: original df: p1 (193 obs) variates y x1 x2 rm(list=ls()) x1<-rnorm(193) x2<-runif(193,-5,5) y<-rnorm(193)+x1+x2 p1<-as.data.frame(cbind(y,x1,x2)) p1 y x1 x2 1 -0.6056448 -0.1113607 -0.5859728 2 -4.2841793 -1.0432688 -3.3116807 ...... 192

Suppose plotx <- "someName" modx <- "otherName" plotxRange <- c(10,20) modxVals <- c(1,2,3) It often happens I want to create a dataframe or object with plotx or modx as the variable names. But can't understand syntax to do that. I can get this done in 2 steps, creating the data frame and then assigning names, as in newdf <- data.frame( c(1, 2, 3, 4),

Good morning List On Friday I had to leave so I could no longer continue with our lab. Weekend and holy all have to rest as much as possible. = D So I'm back and I will put the smb.conf for analysis. # Global parameters [global] workgroup = CMC realm = CMC.CORP netbios name = SAMBA server role = active directory domain controller dns forwarder =

Dear R-helpers, I am stuck on an error in R: When I run my code (below), I get this error back: Error in names(x) <- value : 'names' attribute must be the same length as the vector Then when I use traceback(), R gives me back this in return: `colnames<-`(`*tmp*`, value = c(""Item", "Color" ,"Number", "Size")) I'm not exactly