similar to: Double-banger function names: preferences and suggestions

I am trying to specify a legend title to be other than the variable name, but I find that the legend splits because scale_shape() takes effect but scale_colour() does not. Can someone spot my error? Here's some toy code that produces the problem on my system (R2.8.1, windows, today's CRAN package updates): library(ggplot2) a <- sample(letters[1:5],100,replace=T) b <-

Hi all, Is there any chance that readRDS and saveRDS might one day become read.rds and write.rds? That would make them more consistent with the other reading and writing functions. Hadley -- Assistant Professor / Dobelman Family Junior Chair Department of Statistics / Rice University http://had.co.nz/

Hello all, I'm now using image() to show image data (in my case dumps of SOM weights) but would like to show RGB colour data, not just single "z" colour values. I've currently been using seq() to skip 4 values, so I can show the R, G or B channels separately as "z". But is there a way I can show all three channels simultaneously as a proper colour image? Thanks, B.

You might find http://adv-r.hadley.nz/s3.html to be helpful (in particular, http://adv-r.hadley.nz/s3.html#constructors-1, gives my advice about subclass constructors) Hadley On Mon, Aug 7, 2017 at 7:06 PM, Kym Nitschke <kym.nitschke at icloud.com> wrote: > Hi R Users, > > I am relatively new to programming in R ? so I apologise if my questions appear ?dumb?. > > I am using

Same thing happens with S3 if you redefine print(). I thought that code was actually calculating the function to call rather than the symbol to use, but apparently not. Shouldn't be too hard to fix. luke On Tue, 30 Jun 2015, Hadley Wickham wrote: > On Tue, Jun 30, 2015 at 2:20 PM, Duncan Murdoch > <murdoch.duncan at gmail.com> wrote: >> On 30/06/2015 1:57 PM, Hadley

Help for help says: The 'topic' argument may also be a function call, to ask for documentation on a corresponding method. See the section on method documentation. and The authors of formal ('S4') methods can provide documentation on specific methods, as well as overall documentation on the methods of a particular function. The

Hi all, Can anyone help me understand why an implicit print (i.e. just typing df at the console), is so much slower than an explicit print (i.e. print(df)) in the example below? I see the difference in both Rstudio and in a terminal. # Construct large df as quickly as possible dummy <- 1:18e6 df <- lapply(1:10, function(x) dummy) names(df) <- letters[1:10] class(df) <-

Hi ggplot experts, I need to plot two time series of stacked data: a barchart with bars for each month. To compare the data of two years I need to combine both time series with in a single graph via position=doge. How should I do that? I tried the following scenario: I added two layers with the time series of the stacked data for both years. That worked well exept the bars are obscuring each

On Sat, Jul 7, 2018 at 1:50 PM, Gabe Becker <becker.gabe at gene.com> wrote: > Hadley, > >> >> I was thinking primarily of completing the set of is.matrix() and >> is.array(), or generally, how do you say: is `x` a 1d dimensional >> thing? > > > Can you clarify what you mean by dimensionality sense and specifically 1d > here? What do we call a

On 10/15/07, Henrik Bengtsson <hb at maths.lth.se> wrote: > [As agreed, CC:ing r-devel since others might be interested in this as well.] > > Hi. > > On 10/15/07, Dirk Eddelbuettel <edd at debian.org> wrote: > > > > Hi Hadley, > > > > On 15 October 2007 at 09:51, hadley wickham wrote: > > | Would you consider making digest a generic

On 30/06/2015 1:57 PM, Hadley Wickham wrote: > A slightly simpler formulation of the problem is: > > show <- function(...) stop("My show!") > methods::setClass("Person", slots = list(name = "character")) > methods::new("Person", name = "Tom") > #> Error in (function (...) : My show! Just to be clear: the complaint is

Hi R Users, I am relatively new to programming in R ? so I apologise if my questions appear ?dumb?. I am using a package that defines a number of S3 classes. I want to create an S3 child class of one of these classes. The parent class has a contractor with many arguments. I have been having difficulty writing the child class contractor. I have been unable to find a good reference in the internet

Hi, I have simple R question. I have a vector x that contains real numbers. I would like to create another vector col that is the same length of x such that: if x[i] < 250 then col[i] = "red" else if x[i] < 500 then col[i] = "blue" else if x[i] < 750 then col[i] = "green" else col[i] = "black" for all i I am convinced that there is probably a

On 30/06/2015 5:27 PM, Lorenz, David wrote: > There is something I'm really missing here. The function show is a > standardGeneric function, so the correct way to write it as method like > this: That describes methods::show. The problem is that the default print mechanism isn't calling methods::show() (or base::print() as Luke says), it's calling show() or print() in the

On Fri, Aug 12, 2016 at 11:31 AM, Hadley Wickham <h.wickham at gmail.com> wrote: >> >> One possibility would also be to consider a "numbers-only" or >> >> rather "same type"-only {e.g., would also work for characters} >> >> version. >> >> > I don't know what you mean by these. >> >> In the

Hi all, Because str uses the generic version of length and names, it's currently very easy to create objects that break str: a <- structure(list(1:5), class = "a") length.a <- function(x) 2L str(a) b <- structure(list(1:5), class = "b") names.b <- function(x) character() str(b) These are obvious toy examples, but it is a real problem if you want to create

Hi all, all.equal is generally very useful when you want to find the differences between two objects. It breaks down however, when you have two long strings to compare: > all.equal(a, b) [1] "1 string mismatch" Does any one know of any good text diffing tools implemented in R? Thanks, Hadley -- Assistant Professor / Dobelman Family Junior Chair Department of Statistics / Rice

Hello I tried to define replacement functions for the class "mylist". When I test them in an active R session, they work -- however, when I put them into a package, they don't. Why and how to fix? make_my_list <- function( x, y ) { return(structure(list(x, y, class="mylist"))) } mylist <- make_my_list(1:4, letters[3:7]) mylist mylist[['x']] <- 4:6

Hi all, Would someone mind pointing to me to the inspiration for the use of the L suffix to mean "integer"? This is obviously hard to google for, and the R language definition (https://cran.r-project.org/doc/manuals/r-release/R-lang.html#Constants) is silent. Hadley -- http://hadley.nz

Hi all, Is there a better to way to subset the ROWs (in the sense of NROW) of an vector, matrix, data frame or array than this? subset_ROW <- function(x, i) { nd <- length(dim(x)) if (nd <= 1L) { x[i] } else { dims <- rep(list(quote(expr = )), nd - 1L) do.call(`[`, c(list(quote(x), quote(i)), dims, list(drop = FALSE))) } } subset_ROW(1:10, 4:6) #> [1] 4 5 6