similar to: Working with temporal data [Solved]

Hi, I have several files with data in this format: 20070102 20070102 20070106 20070201 ... The data is sorted and each line represents a date (YYYYMMDD). I would like to analyze this data using R. For instance, I would like to have a histogram by year, month or day. I've already made a simple Perl script that aggregates this data but I believe that R can be much more powerful and easy on

Hi, Since "R" is a (very) generic name, I've been having some trouble searching the web for this topic. Due to this, I've just created a Google Custom Search Engine that includes several of the most relevant sites that have information on R. See it in action at: http://google.com/coop/cse?cx=018133866098353049407%3Aozv9awtetwy This is really a preliminary test. Feel free to

Hi, I'm having a weird result with the length() function: >a [... omited ...] [9994] NA "2003-12-03 16:37:00" "2002-06-26 18:43:00" [9997] "2005-07-04 04:00:00" "2007-02-16 22:09:00" "2007-02-24 15:49:00" [10000] NA > length(LastModified) [1] 9 > length(c(LastModified)) [1] 9 I was expecting to get

Hi, I'm trying to aggregate date values using the aggregate function. For example: aggregate(data,by=list(weekdays(LM),months(LM)),FUN=length) I would also like to aggregate by year but there seems to be no years() function. Should there be one? Is there any alternative choice? Also, a hours() function would be great. Any tip on this? Thanks in advance! S?rgio Nunes

Hi, What's the best way to average dates? I though mean.POISXct would work fine but... > a [1] "2007-04-02 19:22:00 WEST" > b [1] "2007-03-17 16:23:00 WET" > class(a) [1] "POSIXt" "POSIXct" > class(b) [1] "POSIXt" "POSIXct" > mean(a,b) [1] "2007-04-02 19:22:00 WEST" > mean(b,a) [1] "2007-03-17

Hi, I'm looking for a function to measure the dispersion of a set of values ranging from 0 to 1. This function should be 0 if all the values are evenly spaced within the interval and it should be > 0 if values are clustered. The more clustered the values are, the higher should the function be. An example: [0; 0.2; 0.4; 0.6; 0.8; 1] - function should be ~ 0 [0; 0.1; 0.1; 0.15; 1] -

Hi, I'm trying to draw a 2D plot using multiple tints of red. The (simplified) setup is the following: || year | x | y || My idea is that each year is plotted with a different tint of red. Older year (lightest) -> Later year (darkest). I've managed to plot this with different scales of grays simply by doing: palette(gray(length(years):0/length(years))) before the plot and for each

Hi, I'm pretty new to R and I've been having some problems filtering data in matrices. I have the following initial dataset: || year | name | varA || I have multiple values for "varA" for the same "year" and the same "name". Having this as the input I would like to obtain the following: || year | name | {varA mean} || Where I only have one line for each

Hi, I'm pretty new to R, I've just installed version 2.1.1 on Windows. I have a simple (it seems) doubt - how do I change the Console default Language ? It's set to Portuguese but I would like to view it in English. Thanks in advance, S??rgio Nunes

Hi all, after using Amelia II to create 10 imputed data sets I need to average them to have one unique data that includes the average for each cell of the variables imputed, in addition to the values for the variables not imputed. Such data has many variables (some numeric, other factors), and more than 20000 observations. I do not know how to average them out. Any help? Below I provide a small

Hi, It seems that hist() has a buggy behavior when breaking over "days". The bug can be reproduced in a few steps: > d=data.frame(date=c("2009-01-01", "2009-01-02", "2009-01-02")) > d$date=as.Date(d$date) > d$date [1] "2009-01-01" "2009-01-02" "2009-01-02" > h=hist(d$date, "days") > h$count [1] 3

I have OpenSSL forgenrate the CA root file in my server and work fine. My question is, ?howto i say to Samba (configuration) for work with CA certificates? . I dont find information about this. Thanks. Saludos. --- Miguel El mar., 10 nov. 2020 a las 15:22, S?rgio Basto (<sergio at serjux.com>) escribi?: > On Tue, 2020-11-10 at 14:48 -0300, Miguel Angel Coa M. via samba wrote: >

On Thu, 2019-12-05 at 17:15 +0000, Rowland penny via samba wrote: > On 05/12/2019 17:00, S?rgio Basto wrote: > > On Thu, 2019-12-05 at 10:15 +0000, Rowland penny via samba wrote: > > > On 05/12/2019 06:16, S?rgio Basto wrote: > > > > Sorry , I spoke too soon getent passwd "a new user to this > > > > server" > > > > doesn't work .

On Thu, 2019-12-05 at 04:57 +0000, S?rgio Basto via samba wrote: > On Fri, 2019-11-29 at 18:33 +0000, Rowland penny via samba wrote: > > On 29/11/2019 18:17, S?rgio Basto via samba wrote: > > > On Fri, 2019-11-29 at 17:19 +0000, Rowland penny via samba wrote: > > > > Lets start by removing this: krb5-server-1.15.1- > > > > 37.el7_7.2.x86_64 > > >

S?rgio Henrique <sermac at gmail.com> quatschte am Mon, Feb 25, 2013 at 04:26:30PM +0000: > Solved. > > I have sucessfully migrated a windows 2008R2 domain to samba4 and then > create a new samba domain as a replica. > > A lot of steps i had to introduce. Hi S?rgio, > 1- Working on DNS > add samba dc to forest and domain dns _ldap values > change DNS SOA to

On Thu, 2019-12-05 at 10:15 +0000, Rowland penny via samba wrote: > On 05/12/2019 06:16, S?rgio Basto wrote: > > Sorry , I spoke too soon getent passwd "a new user to this server" > > doesn't work . > > But wbinfo -u or wbinfo -g always worked perfectly in any case , > > why > > getent don't ? > > > If 'wbinfo -u' works,

On 28/11/2019 20:01, S?rgio Basto wrote: > This recommendation , why ? wiki say to add it [1] > [1] > https://wiki.samba.org/index.php/Setting_up_a_Share_Using_Windows_ACLs#Enable_Extended_ACL_Support_in_the_smb.conf_File Yes, but under it, in a bright orange warning box, it says this: On a Samba Active Directory (AD) domain controller (DC), extended ACL support is automatically

hello. I have a query about the Matrix package for R. I wrote some code a while ago using the Matrix package version 1.6.2 with an early version of R, to do some linear least squares for regression: xn [,1] [,2] [,3] [,4] [1,] 1 0.7429352 0.5519528 0.4100652 [2,] 1 0.7443713 0.5540886 0.4124477 [3,] 1 0.7447385 0.5546355 0.4130584 [4,] 1 0.7459597 0.5564558

Hi everybody I get it the follow error: The System can not log on. Between parentheses (C0000001). What the means of this, please? -- Gilberto Nunes Suporte Rede Bonja - Bom Jesus/Ielusc Fone: 433-0155 - ramal 235 www.ielusc.br - suporte@ielusc.br Linux User n? 199930 ICQ #136176504 -- Gilberto Nunes Suporte Rede Bonja - Bom Jesus/Ielusc Fone: 433-0155 - ramal 235 www.ielusc.br -

On Tue, May 16, 2023 at 4:00?PM Gilberto Ferreira < gilberto.nunes32 at gmail.com> wrote: > Hi again > I just noticed that there is some updates from glusterd > > apt list --upgradable > Listing... Done > glusterfs-client/unknown 11.0-2 amd64 [upgradable from: 11.0-1] > glusterfs-common/unknown 11.0-2 amd64 [upgradable from: 11.0-1] > glusterfs-server/unknown 11.0-2