similar to: Linking R with Microsoft SQL Server / Client

If you tell me how to update R itself automatically, I will go for your advice. I am not aware of any method to do it... Bye Rick "ONKELINX, Thierry"

Hi I have the following code which I would like to simplify. Id does linear regressions and returns the r-squares, and the coefficients. It runs slow, as it is doing the regressions for each - is it possible to get the values in a dataframe which looks as follow: expert | xx | seeds | r.squared | slope | intercept Thanks in advance, Rainer library(reshape) rsqs <- as.data.frame(

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Hi i have to table with IDs in each one. I want to make a join (as in sql) by the ID. Is any way to use the RODBC package (or other) in local tables (not a access, mysql, sql, etc. ) and made the join? Thanks in advance

I am confused about why the following occurs: > version _ platform i386-pc-mingw32 arch i386 os mingw32 system i386, mingw32 status major 2 minor 4.0

Hi R, Please solve my problem........... I am extracting Bloomberg data from R, in a loop. R is getting fatigued by doing this process and gives some errors. I introduced sleep function. Doing this sometimes I get the results and sometimes not. I even noticed that if I give complete rest for R (don't open R window) for 1 day and then run my code with the sleep function, then the

Hello, I use newly R! I'd like to plot several data set together in one output window! How can I do that? Best regards Hadi --------------------------------- Never miss an email again! [[alternative HTML version deleted]]

Hi all, I am wondering if there is a function available in R for simulating spatial distribution of objects (plants in this case) in order to simulate sampling of a population . Specifically, I would like to be able to change the spatial correlation of individuals. I don't want to reinvent the wheel if it already exists. Thanks, Wade

I'm trying to simulate trend data over a five year period. I want different trend profiles...the simplest being a linear trend. I've been using the following code: patBdta1 <- NULL for(i in 1:100) patBdta1 <- rbind(patBdta1,c(yr1= mean(rbinom(50,1,.50)), yr2 =mean(rbinom(50,1,.51)), yr3 =mean(rbinom(50,1,.52)),

Dear R gurus, I have XY data giving the locations of tree seedlings that were surveyed during a 210 meter belt transect. This belt transect was taken by stretching a line across the field, then measuring all seedlings within 1 meter on either side of the line. The end result was XY coordinates and height for ~1,300 seedlings. I would like to use that data to calculate density of

I want to make a plot, but instead of showing _numerical_ values, I would like to show _symbolic_ values. For example, I want to plot a function y = a x + b, where x varies between Xmin and Xmax. I would like the plot to show, in the x-axis, the strings Xmin and Xmax, instead of their numeric values. Is it possible? Alberto Monteiro

Hi R-users I'm a beginner with R and statistics, so I need some help to start my data analysis. I've been reading some docs and tutorials on R and cluster analysis. I've got a large dataset (102000 points) with values of longitude, latitude and temperature and want to see if I can find groups (clusters). Following some tutorials I can look for principal components but get an error

Hello all-- I've been using 1.13 (v1915) on my Mac pretty intensly for about a month, but today when I tried to generate a plot I recieved this message: Error in quartz(width=9) : too many open devices I was caught by surprise, because I only had the R console open at the time. I checked to be sure, by clicking "Window" at the top bar, and R console was the only window open. I

I am trying to use apply and a list to supply names to a set of tables I want to generate. Below is an example that I hope mimics the larger original problem. EXAMPLE aa <- c( 2,2,1,1,2) bb <- c(5,6,6,7,4) aan <- c("yes", "no") bbn <- c("a", "b", "c", "d") mynames <- c("abby", "billy") mylist <-

Hi, I'm interested in using apply() with t.test() on a data.frame. Specifically, I'd like to use apply() to do the following: t.test(raw.sample[1,alive],raw.sample[1,dead]) t.test(raw.sample[2,alive],raw.sample[2,dead]) t.test(raw.sample[3,alive],raw.sample[3,dead]) etc. I tried the following, apply(raw.sample,1,function(x) t.test(raw.sample[,alive],raw.sample[,dead])) but it gives

Why will the following command not work sapply(objects(),dim) What does it say about the objects list? What does it say about the dim command? Likewise, the following also does not work all<-ls() for (f in all) print(dim(f)) -- Farrel Buchinsky [[alternative HTML version deleted]]

I have these two dataframes in which 'id' is the key field > tabella id nome 1 1 PIEMONTE 2 2 VALLED'AOSTA 3 3 LOMBARDIA 4 4 TRENTINO 5 5 VENETO 6 6 FRIULI AND > tab id nome 1 1 PIEMONTE 2 2 VALLED'AOSTA 3 3 LOMBARDIA 4 4 TRENTINO 5 25 CAMPANIA 6 28 LAZIO Is there any

Hi I have a vector x of length n. I am interested in x[1] being different from the other observations (ie x[-1]). My null hypothesis is that x[1] is drawn from a Gaussian distribution of the same mean as observations x[-1], which are assumed to be iid Gaussian. The (unknown) variance of x[1] is assumed to be the same as the variance of x[-1]. This should be an unpaired t-test. But

Dear R gurus, I would like to use the ccf function on two matrices that are each 196000 x 12. Ideally, I want to be able to go row by row for the two matrices using apply for the ccf function and get one 196000 X 1 array output. The apply function though wants only one array, no? Basically, is there a way to use apply when there are two arrays in order to do something like correlation on a row

Hi Sorry if this is a wrong post in the forum. Please suggest if this is a correct forum to discuss R related basic problem. I wanted to perform the following task by using R: e.g. input data.frame x y ============ a 10 b 20 a 10 a 10 b 15 b 15 b 20 In o/p i need x