similar to: indexing

Hello, I've got a data.frame like this: > > assignation <- data.frame(value=c(6.5,7.5,8.5,12.0),class=c(1,3,5,2)) > > assignation > value class 1 6.5 1 2 7.5 3 3 8.5 5 4 12.0 2 > > > and a long vector of classes like this: > > x <- c(1,1,2,7,6,5,4,3,2,2,2...) > And would like to obtain a vector of length =

Hi, Is there a way to know which library is giving a warning? Specifically, I'm getting a set of warnings: "Too many open raster files" Thanks and best wishes, -- Javier Garc?a-Pintado Institute of Earth Sciences Jaume Almera (CSIC) Lluis Sole Sabaris s/n, 08028 Barcelona Phone: +34 934095410 Fax: +34 934110012 e-mail:jgarcia at ija.csic.es

Hi, I'm trying to use expression() to write a text to a graphic in the margin. Using: mtext(expression(beta),side=1,line=2) writes a perfect beta greek character, but I need to add a subindex "max", and I'm trying: mtext(paste(expression(beta),"max"),side=1,line=2) simply writes "beta max" in the plot. Please, Could you tell me what I'm doing wrong?

Hi all, Let's say I have a long data frame and a short one, both with three colums: $east, $north, $value And I need to fill in the short$value, extracting the corresponding value from long$value, for coinciding $east and $north in both tables. I know the possibility: for (i in 1:length(short$value)){ short$value[i] <- long$value[long$east==short$east & long$north==short$north] } How

Hello, A brief question that I am not able to resolve by my own, but I presume it's easy for you: I've used apply to find the values closer to 0 in each row of a matrix: closer.to.0 <- apply(abs(myarray),MARGIN=1,"min") My question is how could I use which (or another way) to obtain a vector that indicates which columns contains these "closer to 0" values? (I

Hi! Is there any way of having a greyed ("ghosted") text (i.e, 2006) in the background of a plot? I'm making a dynamic plot and would like to show the year of each time step as a big greyed text in the background. (the idea comes from Hans Rosling video: http://video.google.com/videoplay?docid=4237353244338529080&sourceid=searchfeed ) Thanks Agus -- Dr. Agustin Lobo Institut

Hi! Given a vector (or a factor within a df),i.e. v1 <- c(1,1,1,2,3,4,1,10,3) and a dictionary cbind(c(1,2,3),c(1001,1002,1003)) is there a function (on the same line than recode() in car) to get v2 as c(1001,1001,1001,1002,1003,4,1001,10,1003) ? I'm using myself a function based on match() since long ago (I think that thanks to advice by Prof. B. Ripley), but would like to know if there

Hi! Is it possible to set a file to which both commands and output would get automatically saved? I've tried with sink(), but only get the output. I mean something like a combined history and sink, as you get with File/Save to File.. in the windows GUI. Tis is done with diary filename in Matlab, and you can state diary on and diary off to control what is being saved to the file. Thanks Agus

Which is the proper way to rename a factor? If I do: test$Parc[test$Parc=="Ol?rdola"]<-"Ol?rdola" R complains that Warning message: invalid factor level, NAs generated in: `[<-.factor`(`*tmp*`, test$Parc == "Ol?rdola", value = "Ol?rdola") Thanks Agus -- Dr. Agustin Lobo Institut de Ciencies de la Terra "Jaume Almera" (CSIC) LLuis Sole

I've set layout(matrix(c(1,3,2,4),ncol=2)) and par(mar=c(0, 4, 4, 0) + 0.0) and par(mar=c(0, 0, 4, 3) + 0.0) for the upper-left and upper-right plots, but still get an space between both plots, is there any way to completely eliminate that space? Thanks Agus -- Dr. Agustin Lobo Institut de Ciencies de la Terra "Jaume Almera" (CSIC) LLuis Sole Sabaris s/n 08028 Barcelona Spain

Is there an specific function to eliminate blank space within strings? Thanks -- Dr. Agustin Lobo Institut de Ciencies de la Terra "Jaume Almera" (CSIC) LLuis Sole Sabaris s/n 08028 Barcelona Spain Tel. 34 934095410 Fax. 34 934110012 email: Agustin.Lobo at ija.csic.es http://www.ija.csic.es/gt/obster

Given: > mitest <- matrix(1:16,ncol=4) > dimnames(mitest)[[1]] <- c("a","b","c","d") > dimnames(mitest)[[2]] <- c("a","b","c","d") > mitest a b c d a 1 5 9 13 b 2 6 10 14 c 3 7 11 15 d 4 8 12 16 I can do: > mitest[cbind(c(1,2,3),c(2,3,2))] [1] 5 10 7 but using the names does not

Given char vector delme2: > str(delme2) chr [1:1065] "30-1-08 8:48:21" "30-1-08 8:55:17" "30-1-08 9:00:22" ... I do: > delme3 <- strptime(delme2,format="%d-%m-%y %H:%M:%S") But then: > str(delme3) POSIXlt[1:9], format: "2008-01-30 08:48:21" "2008-01-30 08:55:17" ... > length(delme3) [1] 9 whie >

Hi! I'm confused by this: > as.numeric(as.POSIXct(518400,origin="2001-01-01")) [1] 978822000 I guess the problem is that as.numeric() assumes a different origin, but cannot find any default origin. How can I get back the seconds from the POSIXct format? In other words, which the inverse function of as.POSIXct()? I've tried as.numeric and unclass() using a origin=

Hi! If I'm plotting 2 variables with the same units (i.e. wing length of 2 species), how can I force that X and Y axes have the same size for length unit? For example, if X ranges from 0 to 10 and Y ranges from 10 to 30, I want Y axis to be twice as long as X axis. I know I can just put xlim and ylim from 0 to 30, i.e., plot(runif(10,0,10),runif(10,10,30),xlim=c(0,30),ylim=c(0,30)) but this

Hi! In the example: hc <- hclust(dist(USArrests), "ave") dend1 <- as.dendrogram(hc) dend2 <- cut(dend1, h=70) Do the branches "Branch 1", "Branch 2", "Branch 2"...in dend2$upper str(dend2$upper) --[dendrogram w/ 2 branches and 4 members at h = 152] |--[dendrogram w/ 2 branches and 2 members at h = 77.6] | |--leaf "Branch 1" (h=

Agustin, posted on R-help. I think the problem is one of the debian/ubuntu package 'r-cran-robustbase' and its setup or (missing?) dependencies. I can confirm Agustin's problem, working on Ubuntu 8.04.2 (8.04 is a "LTS" = long time support version). apt-get install r-cran-robustbase works fine, but when trying to load the package, there's a DLL - dependency on

Dear list: Given > str(b3) 'data.frame': 159 obs. of 6 variables: $ index_pollution : num 8.228 10.513 0.549 0.915 10.416 ... $ position_descrip: chr "2" "2" "2" NA ... $ position_geo : chr "3" "0" "3" "3" ... $ institution : Factor w/ 3 levels "digesa","mem",..: 3 3 3 3 3 3

I do not understand, from a PCA point of view, the option center=F of prcomp() According to the help page, the calculation in prcomp() "is done by a singular value decomposition of the (centered and possibly scaled) data matrix, not by using eigen on the covariance matrix" (as it's done by princomp()) . "This is generally the preferred method for numerical accuracy"

Hello, I have a program that used to run well in October, it uses library snow. Since then, one change has ocurred (snow library has been updated) and another could have ocurred (I've unadvertently modified something). Anyway, now when I make the call: parallel.model.results <- clusterApply(cl,processors.struct,MCexe) exactly as I used to do, where MCexe is my function and