similar to: plotting results from tapply

Hi, there I am trying to replicate an error message in subset() to see what it is that I'm doing wrong with the datasets I am trying to work with. Essentially, I am trying to pass a string vector to subset() in order to select a specific collection of cases (i.e., I have data for these cases in one table, and want to select data from another table that match up with the cases in the

Muchísimas gracias Carlos, de verdad que te agradezco la ayuda, pero no es lo que voy buscando. Quiero colocar en el eje de abscisas la secuencia temporal de los meses, es decir, agosto septiembre, octubre, etc? pero no las fechas de las toma de datos, sino que aparezca la marca de un mes, y la siguiente marca sea la del siguiente mes, etc?, y además que las muestras estén separadas de acuerdo con

Muchas gracias Carlos, previo a mi correo, entre las pruebas que hice estaba una parecida a la que apuntas de la siguiente manera: attach (Libro1) plot (xbar~as.Date(fechas,"%d/%m/%y"), ylim=c(400,660), xaxt="n", type="b", pch=19,cex=1) xlabels<-strptime(fecha,format="%d/%m/%Y") axis.Date (1,at=xlabels,format="%b-%y")

Hola de nuevo, acabo de encontrar la solución. He creado una variable ficticia con los días 1 de cada mes en la secuencia temporal que quería y después he actuado de la siguiente manera attach(Libro1) plot (xbar~as.Date(fecha,"%d/%m/%y"), type="b", pch=19,cex=2,xaxt="n") xlabels<-strptime(ofeje, format = "%d/%m/%y") axis.Date(1,

Estimada Comunidad, solicito vuestra ayuda en un tema quizás un poco tonto, pero no logro dar con la tecla. Estoy intentando hacer una gráfica de la evolución temporal de una variable (xbar) a lo largo del tiempo. La secuencia que he hecho es la siguiente: attach(Libro1) plot (xbar~as.Date(fechas,"%d/%m/%y"), ylim=c(400,650), type="b", pch=19,cex=1)

I am new to R. I want to graph group data using a "Traditional Bar Chart with Standard Error Bar", like the kind shown here: http://samiam.colorado.edu/~mcclella/ftep/twoGroups/twoGroupGraphs.html Is there a simple way to do this? So far, I have only figured out how to plot the bars using barplot. testdata <- scan(, list(group=0,xbar=0,se=0)) 400 0.36038 0.02154 200 0.35927

Hi Gents, I need to get the control limits from qcc function. As follows: qcc(MDI, type = "xbar.one") Call: qcc(data = MDI, type = "xbar.one") xbar.one chart for MDI Summary of group statistics: Min. 1st Qu. Median Mean 3rd Qu. Max. 0.3266 0.4249 0.4371 0.4333 0.4451 0.4858 Group sample size: 1 Number of groups: 383 Center

Hi there, I'm sure there's an easy answer to this, and I can't wait to see it. The question: is there an easy way to sort a data frame by it's row names? My dilemma: I've had to pull apart a data frame, run it through a loop to do some calculations and generate new variables, and then re-construct the chunks back into a data frame at the end. Doing this preserves the row

Hi R-users, I have a data.frame like this (modificated from https://stat.ethz.ch/pipermail/r-help/2007-August/138124.html). y1 <- rnorm(20) + 6.8 y2 <- rnorm(20) + (1:20*1.7 + 1) y3 <- rnorm(20) + (1:20*6.7 + 3.7) y <- c(y1,y2,y3) x <- rep(1:5,12) f <- gl(3,20, labels=paste("lev", 1:3, sep="")) d <- data.frame(x=x,y=y, f=f) and this is how I can

Hi, there I tried this post on R-help but did not generate any replies, so I thought I might try the waters here since it's a more programming-based group. I have written a function that will allow me to calculate the variance components for a model II (random effects) single factor ANOVA (perhaps this is me re-inventing the wheel, but I handn't yet come across anything in R that does

Hi, all I have a rather un-ideal dataset that I am trying to work with, and would appreciate any advice you have on the matter. I have 4 years worth of data taken at 3 depth-zones from which samples have been taken at random. I am looking at the abundance of organism A between depth zones and across years, and am interested in the possible interaction of organism A distributions shifting

Hello, I have written a function that demonstrates the CLT by generating samples following the exponential distribution, calculating the means, plotting the histogram, and drawing the limiting normal curve as an overlay. I have the title of each histogram state the sample size and rate (1/theta) for the exponential (the output is actually 4 histograms), but I can't get the greek letter theta

I am having issues with the following: (muhat = 1/n^2(sum of all the xi's) ) essentially if xbar = the sample mean, muhat = sample mean but square the n. Question: Use R to run a Monte Carlo simulation which compares the finite-sample performance of xbar and muhat. Specifically generate 1000 samples n=30 from a standard normal distribution. For each sample calculate xbar and muhat. I have

Greets, My data looks like: > p3.18 s xbar subgroup 1 0.84 12.2 1 2 1.64 11.2 2 3 2.07 10.6 3 4 2.49 12.2 4 5 0.84 11.2 5 ... Using the command > qcc(p3.18$xbar,type="xbar",sizes=5,center=mean(p3.18$xbar),std.dev=mean(p3.18$s)/0.94,title="X-bar Chart for Paper Sheet Length Data") I get the x-bar chart I expect. However,

Dear Rusers, I would like to color different sections of a histogram different colors. I have an example that was done by "brute force" given below. Has anyone implemented something like this in general? If not, any suggestions/pointers on how to write a general function to do so would be most appreciated. Alan-

Dear all, I am a newbie in R and could not find help on this problem. I am trying to plot an histogram with probabilities in the y axis. This is the code I am using: #TLC uniform n=30 mi=1; mx=6 nrep=1000 xbar=rep(0,nrep) for (i in 1:nrep) {xbar[i]=mean(runif(n,min=mi,max=mx))} hist(xbar,prob=TRUE,breaks="Sturges",xlim=c(1,6),main=paste("n =",n), xlab="Média",

Hi, there I have written a function that will allow me to calculate the variance components for a model II (random effects) single factor ANOVA (perhaps this is me re-inventing the wheel, but I handn't yet come across anything in R that does this for me, but I'm sure people will let me know from this posting if there are). The function takes as it's argument an object which holds

Hi Folks, I have data that looks like this: freq gender xBar 1000 m 2.32 1000 f 3.22 2000 m 4.32 2000 f 4.53 3000 m 3.21 3000 f 3.44 4000 m 4.11 4000 f 3.99 I want to plot two lines (with symbols) for the two groups "m" and "f". I have tried the following: plot(xBar[gender=="m"]~freq[gender=="f"]) followed by

Hi there, I just wanted to take a quick second to thank everyone who maintains this service- just in case you don't hear it enough, there are a plethora of people who rely on this service (as evidenced by the help archives), and even if they don't say it, are greatly thankful for what you do here. Not only are you providing a service to people who are learning R, but indeed helping

Hi, there I am a grad student struggling to get my syntax right in a model I am building in R. I am trying to specify a variable,W, in a loop, such that on the first iteration, it is equal to Wo, my starting value, which I have already specified with Wo<-9.2 On any other iteration other than the first, I want W to equal the previous value of W in the iteration. plus an increment from