similar to: Date variable

Dear all, Suppose I have a date variable: c = "99/05/12" I want to extract the parts of this date like month number, year and day. I can do it in SPSS. Is it possible to do this in R as well? Rgd, --------------------------------- Here’s a new way to find what you're looking for - Yahoo! Answers [[alternative HTML version deleted]]

Dear all R users, Is there any function to omit repeated values in a vector? Your help will be highly appreciated. Thanks stat --------------------------------- Here’s a new way to find what you're looking for - Yahoo! Answers [[alternative HTML version deleted]]

Hello, I want to know what do you think about my function. I know that it isn't briliant :/ but what do you think? What I should do that my function will be better? (now is very slow and not ideal, sometimes I also get a mistake!) ########## My function ############################################# dzieci<-transform(dzieci, zywnosc=0) zywnoscCalosc<- function( jedzenie, sklep, n1, n2,

Thank you very much for your reply. Your code work well with this example. I modified a little to fit my real data, I got an error massage. Error in split.default(x = seq_len(nrow(x)), f = f, drop = drop, ...) : Group length is 0 but data length > 0 On Thu, Jan 31, 2013 at 12:21 PM, arun kirshna [via R] < ml-node+s789695n4657196h87@n4.nabble.com> wrote: > Hi, > Try this: >

Derar Rxperts, I have a strange situation.. I see curly brackets around "strip.levels" in multipanel strips while using lattice::xyplot. .How do I get rid of the curly brackets? For some reason, I am not able to reproduce the problem using an example below... Any suggestions are highly welcome! Thanks, Santosh q <-

Dear Rxperts, How do I hide the top and right axes in multiple panel plots? A couple of examples are provided below.. Would highly appreciate appreciate your assistance.. #Example 1 library(latticeExtra) xyplot((1:200)/20 ~ (1:200)/20, type = c("p", "g"), scales = list(x = list(log = 2,alternating=0), y = list(log = 10,alternating=0)), xscale.components =

The issue is not with boxplot, but with split. boxplot.formula() calls boxplot(split(split(mf[[response]], mf[-response]), ...), but look at what split() returns when there are empty levels in the factor: > f <- factor(gl(3, 6), levels=1:5) > y <- rnorm(f) > split(y, f) $"1" [1] 0.4832124 1.1924811 0.3657797 1.7400198 0.5577356 0.9889520 $"2" [1] -1.1296642

Hello All, I'm trying to print specific row and column for Observed_Scores matrix, however, when I execute the command "Observed_Scores[1,1]", I get the message "Error in Observed_Scores[1, 1] : incorrect number of dimensions". Could you please help and let me know where is the mistake? Here is my program: library(ltm) library(psych) # Settting the working directory

Dear R-list members, I've had a hard time trying to solve a non-linear system (nls) of equations which structure for the equation i, i=1,...,4, is as follows: f_i(d_1,d_2,d_3,d_4)-k_i(l,m,s) = 0 (1) In the expression above, both f_i and k_i are known functions and l, m and s are known constants. I would like to estimate the vector d=(d_1,d_2,d_3,d_4) which is solution

I have numerous objects, each containing continuous data representing the same variable, movement rate, yet each having a different number of rows. e.g. d1<-as.matrix(rnorm(5)) d2<-as.matrix(rnorm(3)) d3<-as.matrix(rnorm(6)) How can I merge these three columns side-by-side in order to create a table regardless of the difference in length? I wish to analyze the output in a spreadsheet

For adjusted survival curves I took the sample code from here: https://rpubs.com/daspringate/survival and adapted for my date, but got error. I would like to understand what is my mistake. Thanks! #ADAPTATION FOR MY DATA library(survival) library(survminer) df<-read.csv("F:/R/data/base.csv", header = TRUE, sep = ";") head(df) ID start stop censor sex age stage treatment 1

Dear All, I am trying to simulate data for a spline/piecewise regression model. I am missing something fundamental in my simulation procedure because when I try to fit my simulated data using the Gauss-Newton method in SAS, I am getting some wacky parameter estimates. Can anyone please check my simulation code and tell me what mistake I am making in generating data for spline model? Thank you

Dear all I'm pretty sure that I'm approaching the problem in a wrong way. Suppose the following character vector: > (x[1:10] <- paste(x[1:10], sample(1:10, 10), sep='')) [1] "a10" "b7" "c2" "d3" "e6" "f1" "g5" "h8" "i9" "j4" > x [1] "a10" "b7"

Hello, I finally run my measurement model in sem - successfully. Now, I am trying to print out the path diagram that is based on the results - but for some reason it's not working. Below is my script - but the problem is probably in my very last line: # ANALYSIS OF ANXIETY, DEPRESSION, AND FEAR - LISREL P.31 library(sem) # Creating the ANXIETY, DEPRESSION, AND FEAR intercorrelation matrix

I am new to R. I just tried to recreate in R (using sem package and the identical input data) a solution for a simple measurment model I have found before in LISREL. LISREL had no problems and converged in just 3 iterations. In sem, I got no solution, just the warning message: "Could not compute QR decomposition of Hessian. Optimization probably did not converge. in: sem.default(ram =

Dear r-users, Suppose I have three datasets: Dataset-1: Date x y Jan-1,2005 120 230 Jan-2,2005 123 -125 Jan-3,2005 -110 300 Jan-4,2005 114 -21 Jan-7,2005 11 299 Mar-5,2005 200 311 Dataset-2: Date x y Jan-2,2005 123 -125 Jan-3,2005 -110 300 Jan-4,2005 114 -21

Dear r users, Few days ago I posted the same topic but unable to receive any suggestion. So I am asking this same question. I was trying to fit a garch(1,1) model to my dataset. But while executing I got a warning message "NaNs produced in: sqrt(pred$e)". And got the estimated sd's along with five "NA", but as per my best knowledge I should get only one

Dear WizaRds, Working through sampling theory, I tried to comprehend the concept of stratification and apply it with Survey to a small example. My question is more of theoretic nature, so I apologize if this does not fully fit this board's intention, but I have come to a complete stop in my efforts and need an expert to help me along. Please help: age<-matrix(c(rep(1,5), rep(2,3),

Dear all R users, Suppose I have a data frame "data" like this: 5/2/2006 36560 5/3/2006 36538 5/4/2006 36452 5/5/2006 36510 5/8/2006 36485 5/9/2006 36502 5/10/2006 36584 5/11/2006 36571 Now I want to create a for loop like this: date = "5/10/2006" for (i in 1: 8) { if (data[i,1] > date) break }

Hola, soy María, Estoy realizando un trabajo de control de calidad usando en R diferentes tipos de "Control charts", desde el tipo xbar.one, u, p, c,...Y al validar el cálculo de los estadísticos media y desviación típica de mis "Control Charts" en Excel, e investigando, me he dado cuenta de que R calcula las desviaciones de distinto modo según sea el tipo de control chart;