similar to: problem in adf command

Displaying 20 results from an estimated 1000 matches similar to: "problem in adf command"

2007 Aug 04
3
request
I want to calculate the commulative sum of any numeric vector with the following command but this following command does not work "comsum" My question is , how we can calculate the commulative sum of any numeric vector with above command Thanks Zahid Khan Lecturer in Statistics Department of Mathematics Hazara University Mansehra. ---------------------------------
2006 May 05
2
extract p-value from urppTest
Dear List, How do I pick the p-value out of the urppTest result? For adfTest the p-value can be extracted by A2 at test$p.value following A2 <- adfTest(myData[,i], lags=2, type=c("c")) What do I do for urppTest? The above doesn't seem to work. There is a slot @test with $output, which is a list of various test results that didn't want to give away only the p-value
2005 Mar 23
1
Error in unitrootTest (fSeries)
Hello, I am getting the following error message from unitrootTest. Do you have any clue of what could be wrong. Details: AMD64 (x86_64) Gentoo Linux system. library(fSeries) kmodel <- list(ar=c(.3,0,0,0,0.7,-.4*.7),d=1) x=armaSim(nobs,model=kmodel) unitrootTest(x,trend="c",statistic="t",method="adf",lags=2) Error in file(file, "r") : unable to open
2008 Dec 08
1
About adf.test
Dear sir, I am a new user of R statistical package. I want to perform adf.test(augmented dickey fuller test), which packages I need to install in order to perform it. I am getting following message on my monitor. *x<-rnorm(1000) > adf.test(x) Error: could not find function "adf.test" *I am waiting for your response. Kamlesh Kumar. -- Kamlesh Kumar Appt. No. - QQ420,
2009 Jun 05
1
ADF test
Hi, While doing the ADF test in R using the following command I am getting the error and the result.."> x.ct=ur.df(rev$REVENUE,start=1,end=length(rev$REVENUE),frequency=1) Error in ur.df(rev$REVENUE, start = 1, end = length(rev$REVENUE), frequency = 1) : unused argument(s) (start = 1, end = 4, frequency = 1) >
2011 Oct 11
5
Help to write to a file
Dear all: I am having some problems to use the function "sink()". Basically I am doing a loop over two files which contain unit-root variables. Then on a loop, I extract every i element of both files to create an object called z. If z meets some requirements, then I perform a unit root test (ADF test), otherwise not. As this process is repeated several times, for each i I want to get
2005 Jun 29
2
comparison of packages for Unit Root test
Dear R Users, Could somebody please compare the packages of unit root test ( Uroot, Ucra, tseries and fseries ) regarding the type of test ( without constant and trend, with constant , and with constant and trend ) ? Regards, Amir Safari --------------------------------- Rekindle the Rivalries. Sign up for Fantasy Football [[alternative HTML version deleted]]
2006 Aug 28
1
Help on function adf.test
Hello everybody, I've got a matrix called EUROPEDATA and I want to calculate the adf test statistic (part of the tseries package) on a rolling basis for window my.win on each column; i.e. each column of EUROPEDATA represents a particular variable; for the first column I calculate the adf test statistic for window my.win = 60 for example, roll forward one observation, calculate the adf
2007 Feb 13
1
lag orders with ADF.test
Hello! I do not understand what is meant by: "aic" and "bic" follow a top-down strategy based on the Akaike's and Schwarz's information criteria in the datails to the ADF.test function. What does a "top-down strategy" mean? Probably the respective criterion is minimized and the mode vector contains the lag orders at which the criterion attains it
2009 Jun 09
1
Using ADF.Test
Hi, I am quite new to R and would appreciate some guidance, if possible. I have imported a csv file: spread <- read.csv("Spread.csv") I get the following error when I try to run adf.test: > adf.test(spread,alternative = c("stationary", "explosive"),0) Error in embed(y, k) : 'x' is not a vector or matrix Why is this? -- View this message in context:
2013 Apr 30
1
ADF test --time series
Hi all, I was running the adf test in R. CODE 1: adf.test(data$LOSS) Augmented Dickey-Fuller Test data: data$LOSS Dickey-Fuller = -1.9864, Lag order = 2, p-value = 0.5775 alternative hypothesis: stationary CODE 2: adf.test(diff(diff(data$LOSS))) Augmented Dickey-Fuller Test data: diff(diff(data$LOSS)) Dickey-Fuller = -6.9287, Lag order = 2, p-value = 0.01 alternative
2008 Jan 10
1
question regarding kpss tests from urca, uroot and tseries packages
Hi R users! I've come across using kpss tests for time series analysis and i have a question that troubles me since i don't have much experience with time series and the mathematical part underlining it. x<-c(253, 252, 275, 275, 272, 254, 272, 252, 249, 300, 244, 258, 255, 285, 301, 278, 279, 304, 275, 276, 313, 292, 302, 322, 281, 298, 305, 295, 286, 327, 286, 270, 289, 293, 287,
2008 Apr 04
1
Problems with Unit Root testing using ur.df function
Hi All, I'm new to R and am trying to run a unit root test on the vector "y" (a time series of inflation (i.e. changes in the Consumer Price Index quarter on quarter)). I've run the Augmented-Dickey-Fuller Test below (R's URCA package). It gives me an error that it cannot find the function ur.df unless I comment out the third last line of code (see below). I try to call
2007 Aug 16
2
ADF test
Hi all, Hope you people do not feel irritated for repeatedly sending mail on Time series. Here I got another problem on the same, and hope I would get some answer from you. I have following dataset: data[,1] [1] 4.96 4.95 4.96 4.96 4.97 4.97 4.97 4.97 4.97 4.98 4.98 4.98 4.98 4.98 4.99 4.99 5.00 5.01 [19] 5.01 5.00 5.01 5.01 5.01 5.01 5.02 5.01 5.02 5.02 5.03 5.03 5.03
2009 May 15
1
Dickey-Fuller Tests with no constant and no trend
R has a Dickey-Fuller Test implementation (adf.test) that tests for unit roots in an autoregressive process with a constant and linear trend. Is there a DF implementation that doesn't use the constant or trend? Thanks, Jake. -- View this message in context: http://www.nabble.com/Dickey-Fuller-Tests-with-no-constant-and-no-trend-tp23565210p23565210.html Sent from the R help mailing list
2003 Jun 03
1
tseries "adf.test"
I have a question regarding the adf.test command in the tseries library. I have a vector of time series observations (2265 daily log prices for the OEX to be exact). I also have this same data in first-differenced form. I want to test both vectors individually for staionarity with an Augmented Dickey-Fuller test. I noticed when I use the adf.test command from the tseries library, the general
2010 Aug 23
1
Dickey–Fuller test in R
Hi, While doing the adf test using ur.df ?price.df2=ur.df(y=log(price),type = "drift", selectlags="AIC") summary(price.df2)? It gives two values for ?value of test statistic is: -1.5992?? 2.32? one value is the t-test (or t-ratio), what is the other one? Please help. TIA Aditya
2013 Mar 22
4
error while extracting the p-value from adf.test
Hello all, I tried to extract the p-value from adf.test in tseries; however, I got the error message such as > ht=adf.test(list.var$aa) > ht$p-value Error in ht$p - value : non-numeric argument to binary operator > ht Augmented Dickey-Fuller Test data: list.var$aa Dickey-Fuller = -2.3147, Lag order = 4, p-value = 0.4461 alternative hypothesis: stationary > ht$data [1]
2005 Feb 19
2
best analysis method : for time series ans cross sectional data
Howdy What I 'd like to analyze with a large data on building permits is to find time series effect of urban policy on buildings as well as cross-sectional effects in any. In 1990 the specialZone urban policy was introduced. I guess that the effects of this specialZone policy would be different from countys. There are counties that do not welcome this specialZone forced to design it. One of
2010 Mar 18
1
Regression of a time series on its Quarters
# Dear List, # I want to characterize a time series according to its Quarter components. # My data ("a.ts": http://docs.google.com/View?id=dfvvwzr2_478cr9k4cdb)? look like: #???????????????? Qtr1????????? Qtr2????????? Qtr3????????? Qtr4 #?? 1948 -0.0714961837? 0.0101747827? 0.0654816569 -0.0227830729 #?? 1949 -0.1175517556? 0.1151378692? 0.1015777858 -0.1971535900 #?? 1950?