Displaying 20 results from an estimated 3000 matches similar to: "Problems replicating rows and associated increasing index"
2007 Aug 06
1
Create vectors form matrices
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2009 Jan 07
5
rbind for matrices - rep argument
Dear R users,I'm facing a trivial problem, but I really can't solve it. I've
tried a dozen of codes, but I can't get the result I want.
The question is: I have a dataframe like this one
[,1] [,2] [,3] [,4] [,5]
[1,] 1 2 3 4 5
[2,] 2 5 5 4 9
[3,] 1 6 8 1 2
[4,] 8 6 4 1 5
made up of decimal numbers, of course.
I want to
2010 Nov 19
1
profile in lme4 and lme4a/lme4b
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2009 Jan 13
5
If...while...or what else??
Dear R users,I come to you with a quite silly question I think, but I hope
you can answer me...
That is, I've got some problems in using the if and while conditions in a
loop.
Substantially, I want to select rows in a dataset depending on an index
variable (suppose it ranges from 1 to 5), so to make a specific analysis
(homemade of course) on thie new dataset. Mi first tought has been to do a
2008 Jan 10
1
Fwd: multinomial regression for clustered data
Hello dear R-users,
does any of you know a way to perform a multinomial regression with
clustered data (i.e. repeated measurements)? I made the first analysis with
Stata option vce cluster in the mlogit command but was looking for a similar
functionality in R too...
thanks all!
niccolò
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2011 Oct 10
3
Superposing mean line to xyplot
Dear R-users,
I'm using lattice package and function xyplot for the first time so
you will excuse me for my inexperience. I'm facing quite a simple
problem but I'm having troubles on how to solve it, I've read tons of
old mails in the archives and looked at some slides from?Deepayan
Sarkar but still can not get the point.
This is the context. I've got data on 9 microRNAs, each
2007 May 15
1
Re : Bootstrap sampling for repeated measures
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2011 Oct 09
1
help with using last observation carried forward analysis for a clinical trial please
Hi,
I have a series of id's with multiple visits and questionnaire scores. This
is a clinical trial that will be analyzed using the last observation carried
forward method. In other words, in order to comply with intent to treat
analysis when many subjects withdraw, data points for the last visit must be
generated and filled in with the last observation. The ultimate goal is to
tabulate the
2013 Apr 29
1
how to add new rows in a dataframe?
Hi,
dat1<- read.table(text="
id??????????????? t???????????????????? scores
2???????????????? 0??????????????????????? 1.2
2???????????????? 2???????????????????????? 2.3
2???????????????? 3??????????????????????? 3.6
2???????????????? 4??????????????????????? 5.6
2???????????????? 6??????????????????????? 7.8
3???????????????? 0??????????????????????? 1.6
3????????????????
2011 Feb 06
20
debian squeeze released.
Do you know if squeeze has xen support?
_______________________________________________
Xen-users mailing list
Xen-users@lists.xensource.com
http://lists.xensource.com/xen-users
2012 Jul 02
2
using "na.locf" from package zoo to fill NA gaps
Hi everybody,
I have a small question about the function "na.locf" from the package "zoo".
I saw in the help that this function is able to fill NA gaps with the last
value before the NA gap (or with the next value).
But it is possible to fill my NA gaps according to the last AND the next
value at the same time?
Actually, I want R to fill my gaps with the method of
2003 Nov 14
4
LOCF - Last Observation Carried Forward
Hi!
Is there a possibilty in R to carry out LOCF (Last Observation Carried Forward) analysis or to create a new data frame (array, matrix) with LOCF? Or some helpful functions, packages?
Karl
---------------------------------
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2005 May 17
2
cumsum on chron objects
Hi,
Is there some alternative to cumsum for chron objects? I have data frames
that contain some chron objects that look like this:
DateTime
13/10/03 12:30:35
NA
NA
NA
15/10/03 16:30:05
NA
NA
...
and I've been trying to replace the NA's so that a date/time sequence is
created starting with the preceding available value. Because the number of
rows with NA's following each available
2006 Jun 27
2
Survival
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2010 Feb 22
2
Creating regularly spaced time series from irregular one
Hello,
I have a series of intraday (high-frequency) price data in the form of POSIX
timestamp followed by the value.
I sucesfuly loaded that into "its" package object. I would like to create
from it a regularly spaced time series of prices (for example 1min, 5min,
etc apart) so i could calcualte returns.
There is an interpolation function locf() that for timestamp with value NA
uses last
2010 Jun 28
1
Zoo series to a date time stamp that is regular
NOTE: I will provide data if necessary, but I didn't want clutter
everyones mailbox
All:
I have a time series with level and temperature data for 11 sites for
each of three bases. I will have to do this more than once is what I
am saying here. OK, The time series are zoo objects with index
values in chron format. The problem is that the date and times should
be at even 15 min intervals,
2007 Nov 26
3
Fwd: Empty list to use in a for cycle
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2007 May 10
3
Quick question on merging two time-series of different frequencies
Hi,
A quick beginner's question. I have two time series, A with
daily data, and another B with data at varying frequencies, but mostly
annual. Both the series are sorted ascending.
I need to merge these two series together in the following way: For any
entry of A, the lookup should match with B until we find an entry of B
that's larger than A's.
For all A[i], i = 1,...,N and B[j],
2010 Apr 05
2
find the "next non-NA" value within each row of a data-frame
#I wish to find the "next non-NA" value within each row of a data-frame.
#e.g. I have a data frame mydata. Rows 1, 2 & 3 have soem NA values.
mydata <- data.frame(matrix(seq(20*6), 20, 6))
mydata[1,3:5] <- NA
mydata[2,2:3] <- NA
mydata[2,5] <- NA
mydata[3,6] <- NA
mydata[1:3,]
#this loop accomplishes the task; I am tryign toi learn a "better" way
for(i
2011 Sep 30
1
last observation carried forward +1
Hi R-helpers
I'm looking for a vectorised function which does missing value replacement
as in last observation carried forward in the zoo package but instead of a
locf, I would like the locf function to add +1 to each time a missing value
occurred. See below for an example.
> require(zoo)
> x <- 5:15
> x[4:7] <- NA
> coredata(na.locf(zoo(x)))
[1] 5 6 7 7 7 7 7 12 13